No, need more samples / data to convince me
0.5^3 = 12.5%
no, still need more data!
6 times would convince me. Thats only a 1.3 % chance, very convincing!
H0 = 0.3 Ha > 0.3
We must assume that the sample of 80 we collected was random, and that 80 people is less than the total population of customers
N(0.3,sqrt(0.3*0.7)/80)
Ha: p>0.63
p = 0.057
Yes, 5% is a low enough chance that this program probably works. They seem to consistantly be above the mean and the p value is low enough to reject the null.