chapter 15_25,31,33,35,41

Problem 25

  1. p(c)+p(s)-p(b)=83

  2. no, theyre not disjoint beucase a chciken can have both Salmonella and Campylobacter.

  3. p(c) = 0.81 and P(c|s) = 0.86

Not independent, the condition changes the probability

Problem 31

p(d) = 36+48/202=0.41 p(d|f) = 0.49

Not independent, since the condition of gender changes the probablity of chances you will be a certain party.

Problem 33

  1. p(luggage) = 0.695 p(luggage|on time) = 0.95

Not independent, since the condition if she is on time affects the probablity that she will get her luggage

  1. 0.695

Problem 35

p(on time and no luggage) p(delayed and no luggage) p(0.150.05) p(0.850.35) 0.0075 0.2975

0.2975/0.0075+0.2975

0.975

Problem 41

  1. 0.2

  2. 0.272

  3. 0.096/0.096+0.176 = 0.353

  4. 0.0329