I’m Laith Elkurd. I was born and raised just west of Cleveland, OH. I completed my undergraduate degree at Loyola University of Chicago in Biophysics and Mathematics. Which means that I’m more accustomed to equations of the form \(dS = dQ/T\) than programming in R but I’m definitely enjoying learning this material so far. If we’re keeping things honest, then I haven’t decided what I plan to do after I complete the MS BANA program. My hopes are to apply the skills gained in order to serve communities in need of its benefits. That being said ask me the same question again in a few months.
100 * ((1 + (0.05/12)) ^ 24)
## [1] 110.4941
((3333/222) - floor(3333/222)) * 222
## [1] 3
Here we get a remainder of 3
y <- function(n) ((1 + (1/n)) ^ n)
y(10)
## [1] 2.593742
y(1000)
## [1] 2.716924
y(10000)
## [1] 2.718146
y(1000000)
## [1] 2.71828
y(10000000)
## [1] 2.718282
y(100000000)
## [1] 2.718282
y(1000000000)
## [1] 2.718282
y(10000000000)
## [1] 2.718282
y(100000000000)
## [1] 2.718282
y(1000000000000)
## [1] 2.718523
y(10000000000000)
## [1] 2.71611
y(100000000000000)
## [1] 2.71611
y(1000000000000000)
## [1] 3.035035
y(10000000000000000)
## [1] 1
y(100000000000000000)
## [1] 1
y(1000000000000000000)
## [1] 1
Here we see that the equation approaches ~~ 2.716 for inputs up to 1.0*10^16
At 1.0*10^17 the value becomes ~~ 3.035
And finally at 1.0*10^18 and above the equation converges to 1
D <- 1000
K <- 5
h <- 0.25
Q <- sqrt((2 * D * K) / h)
Q
## [1] 200
P <- 100
r <- 0.08
n <- 12
t <- 3
F <- P * ((1 + (r/n)) ^ (n * t))
F
## [1] 127.0237