Shreya Ghelani
Introduction to Me!
Hi! I am Shreya Ghelani, a graduate student at the University of Cincinnati pursuing a master’s program in Business Analytics. This is my first encounter with R markdown and I am pretty excited. I was born and raised in Mumbai - a wonderful city, very close to my heart. I love reading and writing although somehwere along the way, trying to keep up with the pace of life, these delightful hobbies have taken a back seat. My dream is to backpack around the world! My favourite quote is ~ “Ultimately, the race is to be the best you!”
Academic Background
- M.S. in Business Analytics University of Cincinnati (currently pursuing)
- B.Technology in Computer Engineering VJTI
Professional Background
Before coming to UC, I worked with Credit Suisse as a Technolofy Analyst for close to three years. During that time, I realized that I wanted to work in the fields of business intelligence and analytics. I aspire to harness the power of data and contribute to meaningful work.
Week 1 Exercises
- Compute 100(1+0.05/12)^24
x <- 100 * (1 + 0.05/12)^24
print(x)## [1] 110.4941- What is the remainder when 3333 is divided by 222?
y <- 3333 %% 222
print(y)## [1] 3- Investigate the behavior of (1+1/n)^n for large, integer values in n.
n <- c(10000, 5000000, 45890789)
formula <- (1 + 1/n)^n
print(formula)## [1] 2.718146 2.718282 2.718282- The Economic Order Quantity (EOQ) gives the optimal order quantity as Q=√2DK/h where D is the annual demand, K is the fixed cost per order, and h is the annual holding cost per item. Create and set the variables D=1000, K=5, and h=0.25 and compute the associated value of Q.
D <- 1000
K <- 5
h <- 0.25
Q <- (2*D*K/h)^0.5
print(Q)## [1] 200- for an initial principal amount P and a nominal annual interest rate r that is compounded n times per year over a span of t years, the final value of a certificate of deposit is F=P(1+r/n)^nt. Create and set the variables P=100, r=0.08, n=12, and t=3 and compute the associated value of F.
P <- 100
r <- 0.08
n <- 12
t <- 3
F <- P * (1 + r/n)^(n*t)
print(F)## [1] 127.0237