435-2(384)=-333
pnorm(-333,435,384)
## [1] 0.02275013
this means that 2.27 percent of recivers would be running neagtive 333 yards.
The problem here is that clearly no receivers will be running negative years, so our prediciton is wrong. We cant use th enormal model here since the data is highly skewed and non symetric
N(1152,84)
87.8 th percentile, so 100 - 87.8 = 12.2 %
71.6 th percentile
23.3 %
N(1152,84)
1259.6 pounds
1081.3 pounds
1107.9 - 1196.0 pounds
N(1152,84)
1130.7 pounds
1347.4 pounds
IQR = 1208.7 - 1095.3 = 113.4 pounds
50.9 mean, 54, 0.28/0.72
z=0.582
0.52=(54/50.9)/s =5.3 grams
N(67.1,x)
z=2.05
2.05=(0.54-67.1)/x =6.7