1.
2.602
-1.729.
+/- 2.179
2.
2.581
-2.462
+/- 2.738
3.
1.379
-1.714
Skip this problem.
Not enough evidence to reject the null because the left-tail test and statistic test is greater than the critical value
4.
40.43
1.711, -1.711
Skip this problem.
We reject the null because the test statistic is greater than the critical value
5.
2.502
-2.819, 2.819
Skip this problem.
Not sufficient evidence to reject the null, since the test statistic is between the critical values.
Lower bound = 99.39 and upper bound = 110.21. Since the 99% confidence interval includes 100, we do not reject the statement in the null
11.
(a)H0: M=$67, m>$67
Ho: = $67
Ha: > $67
There is a .02 probability of obtaining a sample mean of $67. If we obtained 100 simple random sample of size n = 40
Because p-value is low w ereject tehe statement in the null hypothesis
13.
Ho: = 22.
Ha: > 22
The sample is random. Sample size is large, n =200 >/30
Classical approach , and we would reject the null
There is sufficient evidence to conclude that students who complete scoring above 22 on the math portion of ACT
15.
p value < .0005
There is sufficient evidence to conclude that the mean volume of alcohol is less than the normal volume 17.
p value .25 > p value .2
There is not enough sufficient evidence
19.
lower bound = 35.44 upper bound = 42.356
There is not significant evidence to conclude that the mean average death-row inmate has changed.
1.
28.869
14.041
16.047, 45.722
3.
20.496
13.091
Skip this problem
Do not reject H0 null hypothesis
13.
Note. The sample standard deviation of the data shown is.\(15.205043\). You will have to knit this to see the number though.
3.325
Not sufficient evidence to conclude that the standard deviation wait-time is less than 18 seconds
15.
15.639, 15.659
There is sufficient evidence to conclude that Rose is a more consistent player.