Note: \(\mu\).

10.1

9.

Right-Tailed;mu

10.

Left-Tailed; p

11.

Two-Tailed; sigma

12.

Right-Tailed; p

13.

Left-tailed; mu

14.

Two-tailed; sigma

15.

Ho: p=0.105

H1: p>0.105

  1. TYPE I ERROR: The evidence Would lead the sociologist to believe that p > 0.105 when in fact the registered birth of teenager mothers did not increase.
  2. TYPE II ERROR: the evidence did not lead the sociologist to believe the proportion of teenage births has increased when in fact it did increase.

16.

Ho: mu = 17,072

H1: mu NOT = 17,072

B)Type I ERROR: The sample evidence led the researcher to conclude that the mean charitabe contributions has changed when in fact it did not change. C) TYPE II ERROR: The sample evidence did not lead the researcher to conclude the mean has changed, when in fact it did change.

17.

Ho: mu = $218,600

H1: mu < $218,600

B)TYPE I ERROR: The sample evidence led the R.E. Broker to conclude mu<218,600 when in fact the mean did not decrease C)TYPE II ERROR: The sample evidence did not lead the R.E. Broker to conclude the mean priceof a single home decreased, when in fact the mean price did decrease.

18.

Ho: mu=32 ounces

H1: mu NOT = 32 Ounces

  1. TYPE I ERROR: The eivdence led the consumer advocateto conclude the peanut butter jar does not contain 32 ounces when in fact it does.
  1. type II ERROR: The evidence did not lead the consumer advocate to conclude the weight of peanut butter jar is different than 32 ounces, when in fact it is different

19.

Ho: sigma = 0.7

H1: sigma < 0.7

  1. TIPE I ERROR: The sample evidence led the manager to reject the hypothesis that the variability to open the valce is 0.7, when in fact it is 0.7
  2. TYPE II ERROR: The manager would fails to reject that the variability to open the valce is 0.7 when in fact it is < than 0.7.

20.

Ho: p= 0.19

H1: p > 0.19

  1. Tupe I ERROR: The sample evidence led the school nurse to conclude the percentage of 6-11 years old in her school who is overweight is higher than 19%, when in fact it’s not.
  2. TYPE II ERROR: The sample evidence did not lead the school nurse to conclude the % of 6-11 years old in her school has increased when in fact it’s is > than 19%.

21.

Ho: mu = $47.47

H1: mu NOT = $47.47 B) TYPE I ERROR: The sample evidence led the researcher to conlcude the mean monthly cell bill is different than $47.47 when the bill is in fact $47.47 c) type II ERROR: the sample evidence did not lead the researcher to conclude the mean monthly cell bill is different than $47.47, when in fact the mean is different thna $47.47

10.2

7.

a)HO: p = 0.3 HI: p >0.3; NPO(1-PO)> 10 = 42>10 -RIGHT-TAILED Zo = 2.31 - REJECT NULL HYPOTHESIS b) P-VALUE = P(Z>2.31) = 0.0104 - reject the null hypothesis c) There’s sufficient evidence to reject the Null hypothesis at the level of significant (alpha = 0.05)

9.

  1. HO: P = 0.55 H1: P < 0.55; LEFT-TAILED; npo(1-po) = 37.1 >10; Zo = -0.74 - DO NOT REJECT NULL HYPOTHESIS
  2. PVALUE = P(Z<-0.74) = 0.2296 - DO NOT REJECT NULL HYPOTHESIS
  3. There’s not enough evidence at level of significant (alpha = 0.1) to reject the null hyphotesis

11.

  1. Ho: p = 0.9 H1: not = 0.9; TWO-TAILED; npo(1-po)> 10 = 45 > 10; Zo= -1.49; DO NOT REJECT NULL HYPOTHESIS
  2. Pvalue = P(Z<-1.49) + p (z >1.49) = 2P(Z<-1.49) = 2(0.0681) = 0.1362; DO NOT REJECT NULL HYPOTHESIS
  3. There’s not enough evidence to reject the null hypothesis 13.

P VALUE means that 27 out of 100 samples will give a sample proportion high or higher than the one obtained if population proportion is 0.5; 27 out of 100 is not unusual; therefore we DO NOT REJECT the Null hypothesis. There’s not enough evidence to conclude that throwing darts at the stock pages results in a majority of winners. 15.

  1. test statisic and critical value = Zo = 0.65 - DO NOT REJECT NULL HYPOTHESIS pvalue here = p(z>0.65)= 0.2578 - DO NOT REJECT NULL HYPOTHESIS

  2. There’s not enough evidence to conclude that more tha 1.9% lipitor users experience flulike symptoms as a side effect at level of significance (alpha = 0.01)

17.

  1. test statisic and critical value = Zo = 1.09 -DO NOT REJECT THE NULL HYPOTHESIS pvalue here = P(Z>1.09)= 0.1379; DO NOT REJECT NULL HYPOTHESIS

  2. There’s not enough evidence to conclude that the majority of adults in teh U.S. will not have enough $ for retirement.

19.

  1. test statisic and critical value = Zo= 2.60; REJECT NULL HYPOTHESIS pvalue here = P(Z>2.60)= 0.0047

  2. There’s enough evidence to support the claim that the % of adults who feel basic math skills are critical to their job is > 0.56