2.1

7

  1. China

  2. 50 million

  3. 350 million

  4. Because China has such a higher population that it’s more likely to have a higher frequency simply because of the population size.

9

  1. 69%

  2. 55,200,000

  3. Inferential

11

  1. 0.42 , 0.61

  2. 55+

  3. 18-34

  4. As age increases, they are more likely to buy when made in America

13

Never: 0.0262

Rarely: 0.0678

Sometimes: 0.1156

Most of the time: 0.2632

Always: 0.5272

  1. 52.7%

  2. 9.4%

d e f

my_data <- c(125, 324, 552, 1257, 2518)

groups <- c("Never", "Rarely", "Sometimes", "Most", "Always")

barplot(my_data, main = "Wearing Seatbelts", names.arg = groups)

barplot(my_data, main = "Wearing Seatbelts", names.arg = groups, col = c("red","blue","green","yellow", "black"))

rel_freq <- my_data / sum(my_data)

barplot(rel_freq, main = "Wearing Seatbelts", names.arg = groups, col = c("red","blue","green","yellow","black"))

pie(my_data, labels = groups, main = "Wearing Seatbelts")

  1. Inferential

15

More then 1 hour: 0.3678

Up to 1 hour: 0.1873

A few time a week: 0.1288

A few times a month: 0.0790

Never: 0.2371

  1. 23.7%

c d e

my_data <- c(377, 192, 132, 81, 243)

groups <- c("More 1", "Up to 1", "Few times week", "Few times month", "Never")

barplot(my_data, main = "Use the internet", names.arg = groups)

barplot(my_data, main = "Use the internet", names.arg = groups, col = c("red","blue","green","yellow", "black"))

rel_freq <- my_data / sum(my_data)

barplot(rel_freq, main = "Use the internet", names.arg = groups, col = c("red","blue","green","yellow","black"))

pie(my_data, labels = groups, main = "Use the internet")

  1. It’s not completely accurate because he’s using this small sample to infer something about an entire population

2.2

9

  1. 8

  2. 2

  3. 15

  4. 4

  5. 15%

  6. Bell shaped

10

  1. 4

  2. 9

  3. 17.31%

  4. Bell shaped

11

  1. 200

  2. 10

  3. 60-69 (2), 70-79 (3), 80-89 (13), 90-99 (42), 100-109 (58), 110-119 (40), 120-129 (31), 130-139 (8), 140-149 (2), 150-159 (1)

  4. 100-109

  5. 150-159

  6. 5.5%

  7. No

12

  1. 200

  2. Skip this problem

  3. 0-200

  4. Skewed right

  5. This statement is not right because Texas is a much larger state than Vermont so it will obviously have more of these incidents. To be fair in comparison you should compare the relative frequencies not the frequencies.

13

  1. Skewed right, more people are going to be in lower and middle class than in upper class

  2. Bell shaped, most people will probably get in the middle range with some higher and some lower

  3. Skewed right, more families will have a handful of people than a very large amount

  4. Skewed left, most Alzheimer’s patients are older with cases in young people being much more rare

14

  1. Uniform, this will probably be the same number weekly unless there is a holiday or special event

  2. Uniform, there will most likely be kids of all ages equally

  3. Skewed left, most people with hearing loss are older

  4. Bell shaped, most will be around the average height with equal amounts being a bit shorter or taller