library(readxl)
library(ggpubr)
## Loading required package: ggplot2
A5Q1_Sheet1_<- read_excel("C:/Users/USER/OneDrive - Saint Louis University/AA 5221/Assignment 5/A5Q1(Sheet1).xlsx")
View(A5Q1_Sheet1_)
#plot
ggscatter(
A5Q1_Sheet1_,
x = "age",
y = "education",
add = "reg.line",
xlab = "age",
ylab = "education"
)

#Interpretations
# The relationship is linear.
# The relationship is positive.
# There are outliers.
mean (A5Q1_Sheet1_ $age)
## [1] 35.32634
sd (A5Q1_Sheet1_ $age)
## [1] 11.45344
median (A5Q1_Sheet1_ $age)
## [1] 35.79811
mean (A5Q1_Sheet1_ $education)
## [1] 13.82705
sd (A5Q1_Sheet1_ $education)
## [1] 2.595901
median (A5Q1_Sheet1_ $education)
## [1] 14.02915
#Histogram
hist(A5Q1_Sheet1_$age,
main = "age",
breaks = 20,
col = "lightblue",
border = "white",
cex.main = 1,
cex.axis = 1,
cex.lab = 1)

hist(A5Q1_Sheet1_ $education,
main = "education",
breaks = 20,
col = "lightcoral",
border = "white",
cex.main = 1,
cex.axis = 1,
cex.lab = 1)

#Interpretations
# Variable 1: age
# The variable looks normally distributed.
# The data is symmetrical.
# The data has a proper bell curve.
# Variable 2: education
# The variable looks normally distributed.
# The data is symmetrical.
# The data has a proper bell curve.
#Shapiro Wilk test
shapiro.test(A5Q1_Sheet1_ $age)
##
## Shapiro-Wilk normality test
##
## data: A5Q1_Sheet1_$age
## W = 0.99194, p-value = 0.5581
shapiro.test(A5Q1_Sheet1_ $education)
##
## Shapiro-Wilk normality test
##
## data: A5Q1_Sheet1_$education
## W = 0.9908, p-value = 0.4385
# Variable 1: age
# The variable is normally distributed (p > .05).
# Variable 2: education
# The variable is normally distributed (p > .05).
# using Pearson Correlation
# We use Pearson Correlation because both our histograms appear to be normal and also both Shapiro-wilk tsts indicate normality.
cor.test(
A5Q1_Sheet1_$age,
A5Q1_Sheet1_$education,
method = "pearson"
)
##
## Pearson's product-moment correlation
##
## data: A5Q1_Sheet1_$age and A5Q1_Sheet1_$education
## t = 7.4066, df = 148, p-value = 9.113e-12
## alternative hypothesis: true correlation is not equal to 0
## 95 percent confidence interval:
## 0.3924728 0.6279534
## sample estimates:
## cor
## 0.5200256
# A Pearson correlation was conducted to test the relationship between age (M = 35.33, SD = 11.45) and education (M = 13.83, SD = 2.61).
# There was a statistically significant relationship between the two variables, r(148) = .52, p < .001
# The relationship was positive and strong.
# As age increased, education increased.