Question 1

Ken picked a number and multiplied it by 9. Use ‘divisibility rules’ to determine which number CANNOT be the result of this multiplication.

A. 7011

B. 7126

C. 7137

D. 7209

# install.packages("tidyverse")
library(tidyverse)
## Warning: package 'lubridate' was built under R version 4.5.2
## ── Attaching core tidyverse packages ──────────────────────── tidyverse 2.0.0 ──
## ✔ dplyr     1.1.4     ✔ readr     2.1.5
## ✔ forcats   1.0.1     ✔ stringr   1.5.2
## ✔ ggplot2   4.0.0     ✔ tibble    3.3.0
## ✔ lubridate 1.9.4     ✔ tidyr     1.3.1
## ✔ purrr     1.1.0     
## ── Conflicts ────────────────────────────────────────── tidyverse_conflicts() ──
## ✖ dplyr::filter() masks stats::filter()
## ✖ dplyr::lag()    masks stats::lag()
## ℹ Use the conflicted package (<http://conflicted.r-lib.org/>) to force all conflicts to become errors
q1_data <- data.frame(Choice = LETTERS[1:4],
                      Number = c(7011,7126,7137,7209))
correct_answer <- q1_data %>%
  filter(Number %% 9 != 0) %>%
  pull(Choice)
cat("The correct answer is:",correct_answer,"\n")
## The correct answer is: B

Question 2

The data below shows the weights of 100 parcels that the courier delivered last Monday. Construct a bar graph of the data and determine how many parcels weighed 8 pounds or more.

# install.packages("tidyverse")
library(tidyverse)
q2_data <- data.frame(Weight = 4:11,
                      Frequency = c(2,18,15,30,22,16,6,1))
parcels8 <- q2_data %>%
  filter(Weight >= 8) %>%
  select(Frequency) %>%
  sum()
ggplot(q2_data,aes(x = factor(Weight),y = Frequency)) +
  geom_col() +
  labs(title = "100 Parcel Weight Data",
       caption = paste("There are",parcels8,"parcels that weighed 8 pounds or more."),
       x = "x",
       y = "y") +
  theme_gray()