titanic <- read.csv("/Users/kamilahchaidez/Downloads/titanic.csv")
summary(titanic)
## pclass survived name sex
## Min. :1.000 Min. :0.000 Length :1310 Length :1310
## 1st Qu.:2.000 1st Qu.:0.000 N.unique :1308 N.unique : 3
## Median :3.000 Median :0.000 N.blank : 1 N.blank : 1
## Mean :2.295 Mean :0.382 Min.nchar: 0 Min.nchar: 0
## 3rd Qu.:3.000 3rd Qu.:1.000 Max.nchar: 82 Max.nchar: 6
## Max. :3.000 Max. :1.000
## NAs :1 NAs :1
## age sibsp parch ticket
## Min. : 0.1667 Min. :0.0000 Min. :0.000 Length :1310
## 1st Qu.:21.0000 1st Qu.:0.0000 1st Qu.:0.000 N.unique : 930
## Median :28.0000 Median :0.0000 Median :0.000 N.blank : 1
## Mean :29.8811 Mean :0.4989 Mean :0.385 Min.nchar: 0
## 3rd Qu.:39.0000 3rd Qu.:1.0000 3rd Qu.:0.000 Max.nchar: 18
## Max. :80.0000 Max. :8.0000 Max. :9.000
## NAs :264 NAs :1 NAs :1
## fare cabin embarked boat
## Min. : 0.000 Length :1310 Length :1310 Length :1310
## 1st Qu.: 7.896 N.unique : 187 N.unique : 4 N.unique : 28
## Median : 14.454 N.blank :1015 N.blank : 3 N.blank : 824
## Mean : 33.295 Min.nchar: 0 Min.nchar: 0 Min.nchar: 0
## 3rd Qu.: 31.275 Max.nchar: 15 Max.nchar: 1 Max.nchar: 7
## Max. :512.329
## NAs :2
## body home.dest
## Min. : 1.0 Length :1310
## 1st Qu.: 72.0 N.unique : 370
## Median :155.0 N.blank : 565
## Mean :160.8 Min.nchar: 0
## 3rd Qu.:256.0 Max.nchar: 50
## Max. :328.0
## NAs :1189
str(titanic)
## 'data.frame': 1310 obs. of 14 variables:
## $ pclass : int 1 1 1 1 1 1 1 1 1 1 ...
## $ survived : int 1 1 0 0 0 1 1 0 1 0 ...
## $ name : chr "Allen, Miss. Elisabeth Walton" "Allison, Master. Hudson Trevor" "Allison, Miss. Helen Loraine" "Allison, Mr. Hudson Joshua Creighton" ...
## $ sex : chr "female" "male" "female" "male" ...
## $ age : num 29 0.917 2 30 25 ...
## $ sibsp : int 0 1 1 1 1 0 1 0 2 0 ...
## $ parch : int 0 2 2 2 2 0 0 0 0 0 ...
## $ ticket : chr "24160" "113781" "113781" "113781" ...
## $ fare : num 211 152 152 152 152 ...
## $ cabin : chr "B5" "C22 C26" "C22 C26" "C22 C26" ...
## $ embarked : chr "S" "S" "S" "S" ...
## $ boat : chr "2" "11" "" "" ...
## $ body : int NA NA NA 135 NA NA NA NA NA 22 ...
## $ home.dest: chr "St Louis, MO" "Montreal, PQ / Chesterville, ON" "Montreal, PQ / Chesterville, ON" "Montreal, PQ / Chesterville, ON" ...
head(titanic)
## pclass survived name sex
## 1 1 1 Allen, Miss. Elisabeth Walton female
## 2 1 1 Allison, Master. Hudson Trevor male
## 3 1 0 Allison, Miss. Helen Loraine female
## 4 1 0 Allison, Mr. Hudson Joshua Creighton male
## 5 1 0 Allison, Mrs. Hudson J C (Bessie Waldo Daniels) female
## 6 1 1 Anderson, Mr. Harry male
## age sibsp parch ticket fare cabin embarked boat body
## 1 29.0000 0 0 24160 211.3375 B5 S 2 NA
## 2 0.9167 1 2 113781 151.5500 C22 C26 S 11 NA
## 3 2.0000 1 2 113781 151.5500 C22 C26 S NA
## 4 30.0000 1 2 113781 151.5500 C22 C26 S 135
## 5 25.0000 1 2 113781 151.5500 C22 C26 S NA
## 6 48.0000 0 0 19952 26.5500 E12 S 3 NA
## home.dest
## 1 St Louis, MO
## 2 Montreal, PQ / Chesterville, ON
## 3 Montreal, PQ / Chesterville, ON
## 4 Montreal, PQ / Chesterville, ON
## 5 Montreal, PQ / Chesterville, ON
## 6 New York, NY
Titanic <- titanic[, c("pclass", "age", "sex", "survived")]
Titanic$survived <- as.factor(
ifelse(
Titanic$survived == 0,
"Murio",
"Sobrevive"
)
)
Titanic$pclass <- as.factor(Titanic$pclass)
Titanic$sex <- as.factor(Titanic$sex)
str(Titanic)
## 'data.frame': 1310 obs. of 4 variables:
## $ pclass : Factor w/ 3 levels "1","2","3": 1 1 1 1 1 1 1 1 1 1 ...
## $ age : num 29 0.917 2 30 25 ...
## $ sex : Factor w/ 3 levels "","female","male": 2 3 2 3 2 3 2 3 2 3 ...
## $ survived: Factor w/ 2 levels "Murio","Sobrevive": 2 2 1 1 1 2 2 1 2 1 ...
sum(is.na(Titanic))
## [1] 266
sapply(
Titanic,
function(x) sum(is.na(x))
)
## pclass age sex survived
## 1 264 0 1
Titanic <- na.omit(Titanic)
str(Titanic)
## 'data.frame': 1046 obs. of 4 variables:
## $ pclass : Factor w/ 3 levels "1","2","3": 1 1 1 1 1 1 1 1 1 1 ...
## $ age : num 29 0.917 2 30 25 ...
## $ sex : Factor w/ 3 levels "","female","male": 2 3 2 3 2 3 2 3 2 3 ...
## $ survived: Factor w/ 2 levels "Murio","Sobrevive": 2 2 1 1 1 2 2 1 2 1 ...
## - attr(*, "na.action")= 'omit' Named int [1:264] 16 38 41 47 60 70 71 75 81 107 ...
## ..- attr(*, "names")= chr [1:264] "16" "38" "41" "47" ...
library(rpart)
arbol <- rpart(
formula = survived ~ .,
data = Titanic,
method = "class"
)
arbol
## n= 1046
##
## node), split, n, loss, yval, (yprob)
## * denotes terminal node
##
## 1) root 1046 427 Murio (0.59177820 0.40822180)
## 2) sex=male 658 135 Murio (0.79483283 0.20516717)
## 4) age>=9.5 615 110 Murio (0.82113821 0.17886179) *
## 5) age< 9.5 43 18 Sobrevive (0.41860465 0.58139535)
## 10) pclass=3 29 11 Murio (0.62068966 0.37931034) *
## 11) pclass=1,2 14 0 Sobrevive (0.00000000 1.00000000) *
## 3) sex=female 388 96 Sobrevive (0.24742268 0.75257732)
## 6) pclass=3 152 72 Murio (0.52631579 0.47368421)
## 12) age>=1.5 145 66 Murio (0.54482759 0.45517241) *
## 13) age< 1.5 7 1 Sobrevive (0.14285714 0.85714286) *
## 7) pclass=1,2 236 16 Sobrevive (0.06779661 0.93220339) *
library(rpart.plot)
rpart.plot(arbol)
prp(
arbol,
extra = 7,
prefix = "fraccion "
)
printcp(arbol)
##
## Classification tree:
## rpart(formula = survived ~ ., data = Titanic, method = "class")
##
## Variables actually used in tree construction:
## [1] age pclass sex
##
## Root node error: 427/1046 = 0.40822
##
## n= 1046
##
## CP nsplit rel error xerror xstd
## 1 0.459016 0 1.00000 1.00000 0.037228
## 2 0.018735 1 0.54098 0.54098 0.031419
## 3 0.016393 2 0.52225 0.59016 0.032390
## 4 0.011710 4 0.48946 0.55035 0.031612
## 5 0.010000 5 0.47775 0.54333 0.031468
summary(arbol)
## Call:
## rpart(formula = survived ~ ., data = Titanic, method = "class")
## n= 1046
##
## CP nsplit rel error xerror xstd
## 1 0.45901639 0 1.0000000 1.0000000 0.03722764
## 2 0.01873536 1 0.5409836 0.5409836 0.03141891
## 3 0.01639344 2 0.5222482 0.5901639 0.03239044
## 4 0.01170960 4 0.4894614 0.5503513 0.03161190
## 5 0.01000000 5 0.4777518 0.5433255 0.03146752
##
## Variable importance
## sex pclass age
## 68 22 10
##
## Node number 1: 1046 observations, complexity param=0.4590164
## predicted class=Murio expected loss=0.4082218 P(node) =1
## class counts: 619 427
## probabilities: 0.592 0.408
## left son=2 (658 obs) right son=3 (388 obs)
## Primary splits:
## sex splits as -RL, improve=146.278900, (0 missing)
## pclass splits as RRL, improve= 41.412180, (0 missing)
## age < 8.5 to the right, improve= 8.228231, (0 missing)
##
## Node number 2: 658 observations, complexity param=0.01639344
## predicted class=Murio expected loss=0.2051672 P(node) =0.6290631
## class counts: 523 135
## probabilities: 0.795 0.205
## left son=4 (615 obs) right son=5 (43 obs)
## Primary splits:
## age < 9.5 to the right, improve=13.024220, (0 missing)
## pclass splits as RLL, improve= 8.334816, (0 missing)
##
## Node number 3: 388 observations, complexity param=0.01873536
## predicted class=Sobrevive expected loss=0.2474227 P(node) =0.3709369
## class counts: 96 292
## probabilities: 0.247 0.753
## left son=6 (152 obs) right son=7 (236 obs)
## Primary splits:
## pclass splits as RRL, improve=38.874860, (0 missing)
## age < 30.75 to the left, improve= 2.915006, (0 missing)
## Surrogate splits:
## age < 18.75 to the left, agree=0.673, adj=0.164, (0 split)
##
## Node number 4: 615 observations
## predicted class=Murio expected loss=0.1788618 P(node) =0.5879541
## class counts: 505 110
## probabilities: 0.821 0.179
##
## Node number 5: 43 observations, complexity param=0.01639344
## predicted class=Sobrevive expected loss=0.4186047 P(node) =0.04110899
## class counts: 18 25
## probabilities: 0.419 0.581
## left son=10 (29 obs) right son=11 (14 obs)
## Primary splits:
## pclass splits as RRL, improve=7.2750600, (0 missing)
## age < 3.5 to the right, improve=0.9085875, (0 missing)
##
## Node number 6: 152 observations, complexity param=0.0117096
## predicted class=Murio expected loss=0.4736842 P(node) =0.1453155
## class counts: 80 72
## probabilities: 0.526 0.474
## left son=12 (145 obs) right son=13 (7 obs)
## Primary splits:
## age < 1.5 to the right, improve=2.157947, (0 missing)
##
## Node number 7: 236 observations
## predicted class=Sobrevive expected loss=0.06779661 P(node) =0.2256214
## class counts: 16 220
## probabilities: 0.068 0.932
##
## Node number 10: 29 observations
## predicted class=Murio expected loss=0.3793103 P(node) =0.02772467
## class counts: 18 11
## probabilities: 0.621 0.379
##
## Node number 11: 14 observations
## predicted class=Sobrevive expected loss=0 P(node) =0.01338432
## class counts: 0 14
## probabilities: 0.000 1.000
##
## Node number 12: 145 observations
## predicted class=Murio expected loss=0.4551724 P(node) =0.1386233
## class counts: 79 66
## probabilities: 0.545 0.455
##
## Node number 13: 7 observations
## predicted class=Sobrevive expected loss=0.1428571 P(node) =0.006692161
## class counts: 1 6
## probabilities: 0.143 0.857
predicciones <- predict(
arbol,
Titanic,
type = "class"
)
head(predicciones)
## 1 2 3 4 5 6
## Sobrevive Sobrevive Sobrevive Murio Sobrevive Murio
## Levels: Murio Sobrevive
matriz_confusion <- table(
Real = Titanic$survived,
Prediccion = predicciones
)
matriz_confusion
## Prediccion
## Real Murio Sobrevive
## Murio 602 17
## Sobrevive 187 240
exactitud <- sum(
diag(matriz_confusion)
) / sum(matriz_confusion)
exactitud
## [1] 0.8049713
Las probabilidades más altas de sobrevivir en el Titanic corresponden principalmente a mujeres de primera y segunda clase y a algunos niños.
Las probabilidades más bajas de sobrevivir corresponden principalmente a hombres adultos.
El árbol de decisión permite observar cómo variables como la edad, el sexo y la clase del pasajero ayudan a clasificar si una persona sobrevivió o murió.
La matriz de confusión permite comparar los valores reales con las predicciones del modelo.
La exactitud muestra qué proporción de pasajeros fue clasificada correctamente por el árbol de decisión.