#Import dataset
Q3 <- read_excel("C:/Users/Julia/OneDrive/Desktop/Assignment 6/Question 3/A6Q3-2.xlsx")
#Descriptive Statistics
Q3 %>%
group_by(Exercise) %>%
summarise(
Mean = mean(Weight, na.rm = TRUE),
Median = median(Weight, na.rm = TRUE),
SD = sd(Weight, na.rm = TRUE),
N = n()
)
## # A tibble: 2 × 5
## Exercise Mean Median SD N
## <chr> <dbl> <dbl> <dbl> <int>
## 1 cardio 74.7 73.3 7.57 25
## 2 nocardio 70.8 69.5 7.35 25
#Create histograms
#No Cardio Histogram
hist(Q3$Weight[Q3$Exercise == "nocardio"],
main = "Histogram of No Cardio Weight",
xlab = "Weight (kg)",
ylab = "Frequency",
col = "lightblue",
border = "black",
breaks = 10)
# Interpretation
#Group 1: No Cardio
# The data is normally distributed.
# The data is symmetrical.
# The data has a proper bell curve.
# Interpretation
#Group 2: Cardio Histogram
hist(Q3$Weight[Q3$Exercise == "cardio"],
main = "Histogram of Cardio Weight",
xlab = "Weight (kg)",
ylab = "Frequency",
col = "lightgreen",
border = "black",
breaks = 10)
#Interpretation
#Group 2: Cardio
#The data is normally distributed.
#The data is symmetrical.
#The data has a proper bell curve.
#Create Boxplot for Outliers
ggboxplot(Q3, x = "Exercise", y = "Weight",
color = "Exercise",
palette = "jco",
add = "jitter")
#Interpretation
#The nocardio boxplot has dots outside the boxplot.
#The dots are close to the whiskers.
#The boxplot is normal.
#The cardio boxplot has dots outside the boxplot.
#The dots are close to the whiskers.
#The boxplot is normal.
#Shapiro-Wilk Tests
shapiro.test(Q3$Weight[Q3$Exercise == "nocardio"])
##
## Shapiro-Wilk normality test
##
## data: Q3$Weight[Q3$Exercise == "nocardio"]
## W = 0.97686, p-value = 0.8166
shapiro.test(Q3$Weight[Q3$Exercise == "cardio"])
##
## Shapiro-Wilk normality test
##
## data: Q3$Weight[Q3$Exercise == "cardio"]
## W = 0.96745, p-value = 0.5812
Shapiro-Wilk Interpretation: Group 1: No Cardio The first group is normally distributed, (p = .817).
Group 2: Cardio The second group is normally distributed, (p = .581).
#Independent T-Test
t.test(Weight ~ Exercise, data = Q3, var.equal = TRUE)
##
## Two Sample t-test
##
## data: Weight by Exercise
## t = 1.8552, df = 48, p-value = 0.06971
## alternative hypothesis: true difference in means between group cardio and group nocardio is not equal to 0
## 95 percent confidence interval:
## -0.3280454 8.1605622
## sample estimates:
## mean in group cardio mean in group nocardio
## 74.73336 70.81710
Independent T-Test Interpretation: An Independent T-Test was conducted to determine if there was a difference in weight (kg) between participants that did cardio versus those that did not do cardio. The weight of the group that did cardio (M = 74.70, SD = 7.57) was not significantly different from the group that did not do cardio (M = 70.80, SD = 7.35), t(48) = 1.86, p > .05.