Introduction

This document provides a detailed, step-by-step derivation of the full conditional distributions for all parameters in the exponential kriging model from equations (6.1) and (6.3) of Hierarchical Modeling and Analysis for Spatial Data (3rd Edition).

Special focus is given to deriving:

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\boldsymbol{\beta})\]

Part 1: Understanding Hierarchical Models

1.1 What is a Hierarchical Model?

A hierarchical model (also called a multi-level model) organizes parameters into levels or stages. Each level depends on parameters from the level above it:

Level 0: Data (observed)
    ↑ depends on
Level 1: Latent Process (unobserved)
    ↑ depends on
Level 2: Parameters
    ↑ depends on
Level 3: Hyperparameters (fixed or given priors)

1.2 Our Exponential Kriging Model as a Hierarchy

Level 1: Data Model

\[\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2 \sim N(\mathbf{X}\boldsymbol{\beta} + \mathbf{W}, \tau^2 \mathbf{I})\]

  • \(\mathbf{Y}\) depends on \(\boldsymbol{\beta}\), \(\mathbf{W}\), and \(\tau^2\)
  • \(\boldsymbol{\beta}\) = regression coefficients
  • \(\mathbf{W}\) = spatial random effects
  • \(\tau^2\) = measurement error variance (nugget)

Level 2: Process Model

\[\mathbf{W} \mid \sigma^2, \phi \sim N(\mathbf{0}, \sigma^2 H(\phi))\]

  • \(\mathbf{W}\) depends on \(\sigma^2\) and \(\phi\)
  • \(\sigma^2\) = spatial variance (partial sill)
  • \(\phi\) = spatial decay parameter
  • \(H(\phi)\) = correlation matrix with entries \(\exp(-\phi \|\mathbf{s}_i - \mathbf{s}_j\|)\)

Level 3: Priors

\[\boldsymbol{\beta} \sim N(\boldsymbol{\mu}_\beta, \Sigma_\beta)\]

\[\tau^2 \sim IG(a_\tau, b_\tau)\]

\[\sigma^2 \sim IG(a_\sigma, b_\sigma)\]

\[\phi \sim \text{Gamma}(a_\phi, b_\phi)\]


1.3 Visualizing the Dependencies

                    ┌─────────────────┐
                    │   Hyperpriors   │
                    │  (Fixed values) │
                    └────────┬────────┘
                             │
                    ┌────────▼────────┐
                    │     Priors      │
                    │ β, τ², σ², φ    │
                    └────────┬────────┘
                             │
                    ┌────────▼────────┐
                    │  Process Model  │
                    │   W | σ², φ     │
                    └────────┬────────┘
                             │
                    ┌────────▼────────┐
                    │   Data Model    │
                    │  Y | β, W, τ²   │
                    └─────────────────┘

Key Insight: Each level depends only on the level directly above it.

1.4 The Factorization Rule

In a hierarchical model, the joint distribution equals the product of each variable’s conditional distribution given its parents:

\[\boxed{p(\text{all variables}) = \prod_{\text{each variable } V} p(V \mid \text{parents of } V)}\]

Applying to Our Model:

Variable Depends On (Parents) Conditional Distribution
\(\mathbf{Y}\) \(\boldsymbol{\beta}, \mathbf{W}, \tau^2\) \(p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2)\)
\(\mathbf{W}\) \(\sigma^2, \phi\) \(p(\mathbf{W} \mid \sigma^2, \phi)\)
\(\boldsymbol{\beta}\) None (prior) \(p(\boldsymbol{\beta})\)
\(\tau^2\) None (prior) \(p(\tau^2)\)
\(\sigma^2\) None (prior) \(p(\sigma^2)\)
\(\phi\) None (prior) \(p(\phi)\)

The Full Joint Distribution:

\[\boxed{p(\mathbf{Y}, \mathbf{W}, \boldsymbol{\beta}, \tau^2, \sigma^2, \phi) = p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W} \mid \sigma^2, \phi) \times p(\boldsymbol{\beta}) \times p(\tau^2) \times p(\sigma^2) \times p(\phi)}\]

1.5 Deriving \(p(\mathbf{Y}, \mathbf{W}, \tau^2, \sigma^2, \phi \mid \boldsymbol{\beta})\)

Step 1: Start with the Full Joint

\[p(\mathbf{Y}, \mathbf{W}, \boldsymbol{\beta}, \tau^2, \sigma^2, \phi) = p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W} \mid \sigma^2, \phi) \times p(\boldsymbol{\beta}) \times p(\tau^2) \times p(\sigma^2) \times p(\phi)\]

Step 2: Condition on \(\boldsymbol{\beta}\)

When we condition on \(\boldsymbol{\beta}\), we treat it as fixed/known. This means we divide by \(p(\boldsymbol{\beta})\):

\[p(\mathbf{Y}, \mathbf{W}, \tau^2, \sigma^2, \phi \mid \boldsymbol{\beta}) = \frac{p(\mathbf{Y}, \mathbf{W}, \boldsymbol{\beta}, \tau^2, \sigma^2, \phi)}{p(\boldsymbol{\beta})}\]

Step 3: Substitute and Cancel

\[\boxed{p(\mathbf{Y}, \mathbf{W}, \tau^2, \sigma^2, \phi \mid \boldsymbol{\beta}) = p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W} \mid \sigma^2, \phi) \times p(\tau^2) \times p(\sigma^2) \times p(\phi)}\]


1.6 Why This Factorization Works

Reason 1: Conditional Independence

Variables are conditionally independent given their parents: - \(\mathbf{W}\) and \(\boldsymbol{\beta}\) are independent given \(\sigma^2, \phi\) - \(\tau^2\) and \(\boldsymbol{\beta}\) are independent (separate priors)

Reason 2: The Chain Rule

\[p(A, B, C) = p(A \mid B, C) \times p(B \mid C) \times p(C)\]

Reason 3: The Production Line Analogy

  1. Draw \(\boldsymbol{\beta}\) from prior (conditioning on it = fixed)
  2. Draw \(\tau^2\) from prior
  3. Draw \(\sigma^2\) and \(\phi\) from priors
  4. Draw \(\mathbf{W}\) from \(N(0, \sigma^2 H(\phi))\)
  5. Draw \(\mathbf{Y}\) from \(N(\mathbf{X}\boldsymbol{\beta} + \mathbf{W}, \tau^2 \mathbf{I})\)

The probability of the sequence is the product of each step’s probability.


1.7 Summary Table: Variables and Their Dependencies

Variable Type Depends On Does NOT Depend On
\(\mathbf{Y}\) Data \(\boldsymbol{\beta}, \mathbf{W}, \tau^2\) \(\sigma^2, \phi\)
\(\mathbf{W}\) Latent \(\sigma^2, \phi\) \(\boldsymbol{\beta}, \tau^2\)
\(\boldsymbol{\beta}\) Parameter None (prior) \(\mathbf{W}, \tau^2, \sigma^2, \phi\)
\(\tau^2\) Parameter None (prior) \(\boldsymbol{\beta}, \mathbf{W}, \sigma^2, \phi\)
\(\sigma^2\) Parameter None (prior) \(\boldsymbol{\beta}, \mathbf{W}, \tau^2, \phi\)
\(\phi\) Parameter None (prior) \(\boldsymbol{\beta}, \mathbf{W}, \tau^2, \sigma^2\)

Part 2: Detailed Derivation of

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\boldsymbol{\beta})\]

2.1 Step 1: Start with the Definition of Conditional Probability

For any two random variables/vectors \(A\) and \(B\):

\[P(A \mid B) = \frac{P(A \cap B)}{P(B)}\]

For continuous random variables with probability density functions:

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) = \frac{p(\boldsymbol{\beta}, \mathbf{Y}, \mathbf{W}, \tau^2)}{p(\mathbf{Y}, \mathbf{W}, \tau^2)}\]


2.2 Step 2: Write the Joint Distribution \(p(\boldsymbol{\beta}, \mathbf{Y}, \mathbf{W}, \tau^2)\)

Using the Chain Rule of Probability:

\[p(\boldsymbol{\beta}, \mathbf{Y}, \mathbf{W}, \tau^2) = p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\boldsymbol{\beta}, \mathbf{W}, \tau^2)\]

Now apply the Chain Rule again to \(p(\boldsymbol{\beta}, \mathbf{W}, \tau^2)\):

\[p(\boldsymbol{\beta}, \mathbf{W}, \tau^2) = p(\mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) \times p(\boldsymbol{\beta})\]

Substituting back:

\[p(\boldsymbol{\beta}, \mathbf{Y}, \mathbf{W}, \tau^2) = p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) \times p(\boldsymbol{\beta})\]

2.3 Step 3: Substitute into Bayes’ Theorem

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) = \frac{p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) \times p(\boldsymbol{\beta})}{p(\mathbf{Y}, \mathbf{W}, \tau^2)}\]

2.4 Step 4: Identify the Denominator

The denominator \(p(\mathbf{Y}, \mathbf{W}, \tau^2)\) is the marginal likelihood:

\[p(\mathbf{Y}, \mathbf{W}, \tau^2) = \int p(\mathbf{Y}, \mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) \, p(\boldsymbol{\beta}) \, d\boldsymbol{\beta}\]

Important: This integral is over \(\boldsymbol{\beta}\). The result is a number that does not depend on \(\boldsymbol{\beta}\).

Therefore, for the purpose of finding the distribution of \(\boldsymbol{\beta}\), the denominator is a constant.


2.5 Step 5: Simplify the Proportionality

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) \times p(\boldsymbol{\beta})\]

2.6 Step 6: Analyze \(p(\mathbf{W}, \tau^2 \mid \boldsymbol{\beta})\)

Option A: Using Conditional Independence from the Hierarchical Model

In our hierarchical model:

\[\mathbf{W} \mid \sigma^2, \phi \sim N(\mathbf{0}, \sigma^2 H(\phi))\]

\[\tau^2 \sim IG(a_\tau, b_\tau)\]

Key observation: \(\mathbf{W}\) and \(\tau^2\) are independent of \(\boldsymbol{\beta}\).

Why? - \(\mathbf{W}\) depends only on \(\sigma^2\) and \(\phi\) (not on \(\boldsymbol{\beta}\)) - \(\tau^2\) has its own prior (not on \(\boldsymbol{\beta}\))

Therefore:

\[p(\mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) = p(\mathbf{W} \mid \sigma^2, \phi) \times p(\tau^2)\]

Option B: Using the Full Joint Distribution

Recall the full joint distribution from the hierarchical structure:

\[p(\mathbf{Y}, \mathbf{W}, \boldsymbol{\beta}, \tau^2, \sigma^2, \phi) = p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W} \mid \sigma^2, \phi) \times p(\boldsymbol{\beta}) \times p(\tau^2) \times p(\sigma^2) \times p(\phi)\]

Now, condition on \(\boldsymbol{\beta}\) (treat it as known):

\[p(\mathbf{Y}, \mathbf{W}, \tau^2, \sigma^2, \phi \mid \boldsymbol{\beta}) = \frac{p(\mathbf{Y}, \mathbf{W}, \boldsymbol{\beta}, \tau^2, \sigma^2, \phi)}{p(\boldsymbol{\beta})}\]

\[= p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W} \mid \sigma^2, \phi) \times p(\tau^2) \times p(\sigma^2) \times p(\phi)\]

Now integrate out \(\sigma^2\) and \(\phi\):

\[p(\mathbf{Y}, \mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) = \int\int p(\mathbf{Y}, \mathbf{W}, \tau^2, \sigma^2, \phi \mid \boldsymbol{\beta}) \, d\sigma^2 \, d\phi\]

\[= p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\tau^2) \times \int p(\mathbf{W} \mid \sigma^2, \phi) \, p(\sigma^2) \, p(\phi) \, d\sigma^2 \, d\phi\]

The integral is just a constant \(C\) that does not depend on \(\boldsymbol{\beta}\):

\[p(\mathbf{Y}, \mathbf{W}, \tau^2 \mid \boldsymbol{\beta}) = C \times p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\tau^2)\]

2.7 Step 7: Substitute Back

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times C \times p(\tau^2) \times p(\boldsymbol{\beta})\]

Since \(C\) and \(p(\tau^2)\) are constants with respect to \(\boldsymbol{\beta}\):

\[\boxed{p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\boldsymbol{\beta})}\]

2.8 Visual Summary of the Derivation

Step 1: Start with Bayes' Theorem
         ↓
p(β | Y, W, τ²) = p(Y | β, W, τ²) × p(β, W, τ²) / p(Y, W, τ²)
         ↓
Step 2: Apply Chain Rule
         ↓
p(β, W, τ²) = p(W, τ² | β) × p(β)
         ↓
Step 3: Substitute
         ↓
p(β | Y, W, τ²) = p(Y | β, W, τ²) × p(W, τ² | β) × p(β) / p(Y, W, τ²)
         ↓
Step 4: Identify constants
         ↓
p(W, τ² | β) = p(W | σ², φ) × p(τ²)   [from hierarchical model]
p(Y, W, τ²) = constant (doesn't depend on β)
         ↓
Step 5: Drop constants
         ↓
p(β | Y, W, τ²) ∝ p(Y | β, W, τ²) × p(β)

2.9 Intuitive Interpretation

Term Meaning Role
\(p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2)\) Posterior What we know about \(\boldsymbol{\beta}\) after seeing data
\(p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2)\) Likelihood How well \(\boldsymbol{\beta}\) explains the data \(\mathbf{Y}\) (given \(\mathbf{W}\) and \(\tau^2\))
\(p(\boldsymbol{\beta})\) Prior What we knew about \(\boldsymbol{\beta}\) before seeing data

The equation says:

“Our updated belief about \(\boldsymbol{\beta}\) is proportional to how well it explains the data times what we believed before seeing the data.”


2.10 Special Cases

Case 1: Flat Prior (Non-informative)

If \(p(\boldsymbol{\beta}) \propto 1\) (constant):

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2)\]

The posterior is proportional to the likelihood — the data dominates.

Case 2: Very Informative Prior

If \(p(\boldsymbol{\beta})\) is very concentrated (small variance):

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \approx p(\boldsymbol{\beta})\]

The prior dominates — the data has little influence.

Part 3: Model Specification

3.1 The Exponential Kriging Model

\[Y(\mathbf{s}) = \mathbf{x}(\mathbf{s})^T \boldsymbol{\beta} + W(\mathbf{s}) + \epsilon(\mathbf{s})\]

Where: - \(W(\mathbf{s}) \sim GP(0, \sigma^2 H(\phi))\) - \(\epsilon(\mathbf{s}) \sim N(0, \tau^2)\) - \(H(\phi)_{ij} = \exp(-\phi \|\mathbf{s}_i - \mathbf{s}_j\|)\)

3.2 Two Forms

Conditional (Hierarchical) Form

Stage 1:

\[\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2 \sim N(\mathbf{X}\boldsymbol{\beta} + \mathbf{W}, \tau^2 \mathbf{I})\]

Stage 2:

\[\mathbf{W} \mid \sigma^2, \phi \sim N(\mathbf{0}, \sigma^2 H(\phi))\]

Marginal Form (after integrating out \(\mathbf{W}\))

\[\mathbf{Y} \mid \boldsymbol{\beta}, \sigma^2, \tau^2, \phi \sim N(\mathbf{X}\boldsymbol{\beta}, \sigma^2 H(\phi) + \tau^2 \mathbf{I})\]

3.3 Prior Distributions

  • \(\boldsymbol{\beta} \sim N(\boldsymbol{\mu}_\beta, \Sigma_\beta)\)
  • \(\tau^2 \sim IG(a_\tau, b_\tau)\)
  • \(\sigma^2 \sim IG(a_\sigma, b_\sigma)\)
  • \(\phi \sim \text{Gamma}(a_\phi, b_\phi)\)

Part 4: Full Conditional for \(\boldsymbol{\beta}\)

4.1 Apply Bayes’ Theorem

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\boldsymbol{\beta})\]

Justification: Which Terms Depend on \(\boldsymbol{\beta}\)?

Term Depends on \(\boldsymbol{\beta}\)? Status
\(p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2)\) YES Keep
\(p(\mathbf{W} \mid \sigma^2, \phi)\) NO (depends on \(\sigma^2, \phi\)) Constant → drop
\(p(\tau^2)\) NO Constant → drop
\(p(\sigma^2)\) NO Constant → drop
\(p(\phi)\) NO Constant → drop
\(p(\boldsymbol{\beta})\) YES Keep

4.2 Write the Likelihood

From \(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2 \sim N(\mathbf{X}\boldsymbol{\beta} + \mathbf{W}, \tau^2 \mathbf{I})\):

\[p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \propto \exp\left\{-\frac{1}{2\tau^2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})^T (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})\right\}\]


4.3 Write the Prior

From \(\boldsymbol{\beta} \sim N(\boldsymbol{\mu}_\beta, \Sigma_\beta)\):

\[p(\boldsymbol{\beta}) \propto \exp\left\{-\frac{1}{2} (\boldsymbol{\beta} - \boldsymbol{\mu}_\beta)^T \Sigma_\beta^{-1} (\boldsymbol{\beta} - \boldsymbol{\mu}_\beta)\right\}\]

4.4 Multiply

\[p(\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2) \propto \exp\left\{-\frac{1}{2\tau^2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})^T (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W}) - \frac{1}{2} (\boldsymbol{\beta} - \boldsymbol{\mu}_\beta)^T \Sigma_\beta^{-1} (\boldsymbol{\beta} - \boldsymbol{\mu}_\beta)\right\}\]


4.5 Complete the Square

This yields a multivariate normal:

\[\boxed{\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2 \sim N\left( \boldsymbol{\mu}_\beta^*, \Sigma_\beta^* \right)}\]

Where:

\[\Sigma_\beta^* = \left( \frac{1}{\tau^2} \mathbf{X}^T \mathbf{X} + \Sigma_\beta^{-1} \right)^{-1}\]

\[\boldsymbol{\mu}_\beta^* = \Sigma_\beta^* \left( \frac{1}{\tau^2} \mathbf{X}^T (\mathbf{Y} - \mathbf{W}) + \Sigma_\beta^{-1} \boldsymbol{\mu}_\beta \right)\]

Special Case: Flat Prior

If \(\Sigma_\beta^{-1} \to 0\):

\[\boldsymbol{\beta} \mid \mathbf{Y}, \mathbf{W}, \tau^2 \sim N\left( (\mathbf{X}^T \mathbf{X})^{-1} \mathbf{X}^T (\mathbf{Y} - \mathbf{W}), \tau^2 (\mathbf{X}^T \mathbf{X})^{-1} \right)\]

Part 5: Full Conditional for \(\mathbf{W}\)

5.1 Apply Bayes’ Theorem

\[p(\mathbf{W} \mid \mathbf{Y}, \boldsymbol{\beta}, \sigma^2, \tau^2, \phi) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\mathbf{W} \mid \sigma^2, \phi)\]

5.2 Multiply Likelihood and Prior

\[\propto \exp\left\{-\frac{1}{2\tau^2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})^T (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W}) - \frac{1}{2\sigma^2} \mathbf{W}^T H(\phi)^{-1} \mathbf{W}\right\}\]

5.3 Complete the Square

\[\boxed{\mathbf{W} \mid \mathbf{Y}, \boldsymbol{\beta}, \sigma^2, \tau^2, \phi \sim N\left( \boldsymbol{\mu}_W^*, \Sigma_W^* \right)}\]

Where:

\[\Sigma_W^* = \left( \frac{1}{\tau^2} \mathbf{I} + \frac{1}{\sigma^2} H(\phi)^{-1} \right)^{-1}\]

\[\boldsymbol{\mu}_W^* = \Sigma_W^* \left( \frac{1}{\tau^2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta}) \right)\]

Alternative Form (Sherman-Morrison-Woodbury)

\[\Sigma_W^* = \tau^2 \mathbf{I} - \tau^2 H(\phi) \left( \tau^2 H(\phi) + \sigma^2 \mathbf{I} \right)^{-1} \tau^2 \mathbf{I}\]

\[\boldsymbol{\mu}_W^* = H(\phi) \left( \tau^2 H(\phi) + \sigma^2 \mathbf{I} \right)^{-1} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta})\]

Part 6: Full Conditional for \(\tau^2\)

6.1 Apply Bayes’ Theorem

\[p(\tau^2 \mid \mathbf{Y}, \boldsymbol{\beta}, \mathbf{W}) \propto p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \times p(\tau^2)\]

6.2 Multiply

\[\propto (\tau^2)^{-n/2} \exp\left\{-\frac{1}{2\tau^2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})^T (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})\right\} \times (\tau^2)^{-(a_\tau + 1)} \exp\left(-\frac{b_\tau}{\tau^2}\right)\]

6.3 Recognize Inverse-Gamma

\[\boxed{\tau^2 \mid \mathbf{Y}, \boldsymbol{\beta}, \mathbf{W} \sim IG\left( a_\tau^*, b_\tau^* \right)}\]

Where:

\[a_\tau^* = a_\tau + \frac{n}{2}\]

\[b_\tau^* = b_\tau + \frac{1}{2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})^T (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta} - \mathbf{W})\]

Part 7: Full Conditional for \(\sigma^2\)

7.1 Apply Bayes’ Theorem

\[p(\sigma^2 \mid \mathbf{W}, \phi) \propto p(\mathbf{W} \mid \sigma^2, \phi) \times p(\sigma^2)\]

7.2 Multiply

\[\propto (\sigma^2)^{-n/2} \exp\left\{-\frac{1}{2\sigma^2} \mathbf{W}^T H(\phi)^{-1} \mathbf{W}\right\} \times (\sigma^2)^{-(a_\sigma + 1)} \exp\left(-\frac{b_\sigma}{\sigma^2}\right)\]

7.3 Recognize Inverse-Gamma

\[\boxed{\sigma^2 \mid \mathbf{W}, \phi \sim IG\left( a_\sigma^*, b_\sigma^* \right)}\]

Where:

\[a_\sigma^* = a_\sigma + \frac{n}{2}\]

\[b_\sigma^* = b_\sigma + \frac{1}{2} \mathbf{W}^T H(\phi)^{-1} \mathbf{W}\]


Part 8: Full Conditional for \(\phi\)

8.1 Apply Bayes’ Theorem

\[p(\phi \mid \mathbf{W}, \sigma^2) \propto p(\mathbf{W} \mid \sigma^2, \phi) \times p(\phi)\]

8.2 Multiply

\[\propto |H(\phi)|^{-1/2} \exp\left\{-\frac{1}{2\sigma^2} \mathbf{W}^T H(\phi)^{-1} \mathbf{W}\right\} \times p(\phi)\]

8.3 Non-Standard Distribution

\(\phi\) appears inside \(H(\phi)\) in a nonlinear way through \(\exp(-\phi \|\mathbf{s}_i - \mathbf{s}_j\|)\). There is no closed-form conjugate distribution.

\[\boxed{\text{Update } \phi \text{ using Metropolis-Hastings or slice sampling}}\]

Marginalized Form (if \(\mathbf{W}\) is integrated out):

\[p(\phi \mid \mathbf{Y}, \boldsymbol{\beta}, \sigma^2, \tau^2) \propto \left| \sigma^2 H(\phi) + \tau^2 \mathbf{I} \right|^{-1/2} \exp\left\{-\frac{1}{2} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta})^T (\sigma^2 H(\phi) + \tau^2 \mathbf{I})^{-1} (\mathbf{Y} - \mathbf{X}\boldsymbol{\beta}) \right\} \times p(\phi)\]


Part 9: Summary Table

Parameter Full Conditional Distribution Type Update Method
\(\boldsymbol{\beta}\) \(N\left( \boldsymbol{\mu}_\beta^*, \Sigma_\beta^* \right)\) Closed form Gibbs
\(\mathbf{W}\) \(N\left( \boldsymbol{\mu}_W^*, \Sigma_W^* \right)\) Closed form Gibbs
\(\tau^2\) \(IG\left( a_\tau^*, b_\tau^* \right)\) Closed form Gibbs
\(\sigma^2\) \(IG\left( a_\sigma^*, b_\sigma^* \right)\) Closed form Gibbs
\(\phi\) Non-standard No closed form Metropolis-Hastings / Slice

Part 10: Why the Marginal Form?

10.1 Integrating Out \(\mathbf{W}\)

The marginal likelihood is obtained by integrating \(\mathbf{W}\) out of the joint distribution:

\[p(\mathbf{Y} \mid \boldsymbol{\beta}, \sigma^2, \tau^2, \phi) = \int p(\mathbf{Y} \mid \boldsymbol{\beta}, \mathbf{W}, \tau^2) \; p(\mathbf{W} \mid \sigma^2, \phi) \; d\mathbf{W}\]

Since both are normal, the integral is analytic:

\[\mathbf{Y} \mid \boldsymbol{\beta}, \sigma^2, \tau^2, \phi \sim N(\mathbf{X}\boldsymbol{\beta}, \sigma^2 H(\phi) + \tau^2 \mathbf{I})\]

10.2 Advantages of the Marginal Form

  1. Fewer parameters in MCMC (no \(\mathbf{W}\) updates inside the chain)
  2. Better conditioned covariance matrix: \(\sigma^2 H(\phi) + \tau^2 \mathbf{I}\) is less singular than \(\sigma^2 H(\phi)\) alone
  3. Faster convergence and better mixing

10.3 Recovering \(\mathbf{W}\)

After MCMC, draw \(\mathbf{W}\) from its conditional distribution:

\[p(\mathbf{W} \mid \mathbf{Y}, \boldsymbol{\beta}, \sigma^2, \tau^2, \phi) = N\left( \boldsymbol{\mu}_W^*, \Sigma_W^* \right)\]


References

  • Banerjee, S., Gelfand, A. E., & Carlin, B. P. (2026). Hierarchical Modeling and Analysis for Spatial Data (3rd ed.). CRC Press.
  • Chapter 6: Hierarchical Modeling for Univariate Spatial Data
  • Section 6.3: Details on Bayesian Inference for Isotropic Models