A5Q2

’’’(R) MYTABLE <- table(A5Q2\(nationality, A5Q2\)scholarship_awarded) MYTABLE

0 1 Domestic 39 111 International 118 32

chisq.test(MYTABLE)

Pearson’s Chi-squared test with Yates’ continuity correction

data: MYTABLE X-squared = 81.297, df = 1, p-value < 2.2e-16

rcompanion::cramerV(MYTABLE) Cramer V 0.5272

#A Chi-Square Test of Independence was conducted to determine if there was an association between NATIONALITY and SCHOLARSHIP awardance.

The results showed that there was an association between the two variables, χ²(1) = 81.29, p = 3.32.

The association was strong, (Cramer’s V = .52).

’’’