’’’{r}
library(readxl)
’’’
’’’{r}
library(ggpubr)
’’’
’’’{r}
A4Q2 <- read_excel(“Desktop/A4Q2.xlsx”)
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’’’{r}
View(A4Q2)
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’’’{r}
ggscatter(A4Q2,x=“phone”,y=“sleep”,add=“reg.line”,xlab=“Phone”,ylab=“Sleep”)
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The relationship is linear. The relationship is negative. The relationship is weak to moderate. There are outliers.
’’’{r}
mean(A4Q2$phone)
’’’
[1] 3.804609
’’’{r}
sd(A4Q2$phone)
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[1] 2.661866
’’’{r}
median(A4Q2$phone)
’’’
[1] 3.270839
’’’{r}
mean(A4Q2$sleep)
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[1] 7.559076
’’’{r}
sd(A4Q2$sleep)
’’’
[1] 1.208797
’’’{r}
median(A4Q2$sleep)
’’’ [1] 7.524099
’’’{r}
hist(A4Q2$phone,main=“Phone”,breaks=20,col=“blue”,border=“white”,cex.main=1,cex.axis=1,cex.lab=1)
’’’
’’’{r}
hist(A4Q2$sleep,main=“Sleep”,breaks=20,col=“red”,border=“white”,cex.main=1,cex.axis=1,cex.lab=1)
’’’
Variable 1: Phone The first variable looks abnormally distributed. The data is negatively skewed. The data does not have a proper bell curve.
Variable 2: Sleep The second variable looks abnormally distributed. The data is positively skewed. The data does not have a proper bell curve.
’’’{r}
shapiro.test(A4Q2$phone)
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Shapiro-Wilk normality test
data: A4Q2$phone W = 0.89755, p-value = 9.641e-09
’’’{r}
shapiro.test(A4Q2$sleep)
’’’ Shapiro-Wilk normality test
data: A4Q2$sleep W = 0.91407, p-value = 8.964e-08
Variable 1: Phone The first variable is abnormally distributed (p = 9.641e-09)
Variable 2: Sleep The second variable is abnormally distributed (p = 8.964e-08)
’’’{r}
cor.test(A4Q2\(phone,A4Q2\)sleep,method=“spearman”)
’’’
Spearman's rank correlation rho
data: A4Q2\(phone and A4Q2\)sleep S = 908390, p-value < 2.2e-16 alternative hypothesis: true rho is not equal to 0 sample estimates: rho -0.6149873
A Spearman correlation was conducted to test the relationship between a person’s phone usage in hours (Mdn = 3.27) and sleep in hours (Mdn = 7.52). There was a statistically significant relationship between the two variables, rho = -.61, p < .001. The relationship was negative and strong. As phone usage increased, sleep decreased.