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library(readxl)

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library(ggpubr)

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Loading required package: ggplot2

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A4Q1 <- read_excel(“Desktop/A4Q1.xlsx”)

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View(A4Q1)

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ggscatter(A4Q1,x=“age”,y=“education”,add=“reg.line”,xlab=“Age”,ylab=“Education”)

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The relationship is linear. The relationship is positive. The relationship is weak to moderate. There are outliers. > ’’’{r}

mean(A4Q1$age)

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[1] 35.32634

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sd(A4Q1$age)

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[1] 11.45344

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median(A4Q1$age)

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[1] 35.79811

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mean(A4Q1$education)

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[1] 13.82705

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sd(A4Q1$education)

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[1] 2.595901

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median(A4Q1$education)

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[1] 14.02915

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hist(A4Q1$age,main=“Age”,breaks=20,col=“blue”,border=“white”,cex.main=1,cex.axis=1,cex.lab=1)

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’’’{r}

hist(A4Q1$education,main=“Education”,breaks=20,col=“red”,border=“white”,cex.main=1,cex.axis=1,cex.lab=1)

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Variable 1: Age The first variable looks normally distributed. The data is symmetrical. The data has a proper bell curve.

Variable 2: Education The second variable looks normally distributed. The data is symmetrical. The data has a proper bell curve.

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shapiro.test(A4Q1$age)

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Shapiro-Wilk normality test

data: A4Q1$age W = 0.99194, p-value = 0.5581

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shapiro.test(A4Q1$education)

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Shapiro-Wilk normality test

data: A4Q1$education W = 0.9908, p-value = 0.4385

Variable 1: Age The first variable is normally distributed (p = .56).

Variable 2: Education The second variable is normally distributed (p = .44)

’’’{r}

cor.test(A4Q1\(age,A4Q1\)education,method=“pearson”)

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Pearson’s product-moment correlation

data: A4Q1\(age and A4Q1\)education t = 7.4066, df = 148, p-value = 9.113e-12 alternative hypothesis: true correlation is not equal to 0 95 percent confidence interval: 0.3924728 0.6279534 sample estimates: cor 0.5200256

A Pearson correlation was conducted to test the relationship between a person’s age in years (M = 35.33, SD = 11.45) and education in years (M = 13.83, SD = 2.6). There was a statistically significant relationship between the two variables, r(148) = .52, p = <.001. The relationship was positive and strong. As age increased, education increased.