This is the last homework. Part 1 uses linear regression on country-level data. Part 2 uses logistic regression on a medical dataset.
Download AllCountries.csv from the Datasets folder on
Blackboard. The dataset has 217 countries with variables including GDP,
LifeExpectancy, Health, Internet, CO2, Energy, Electricity, and
more.
countries <- read.csv("AllCountries.csv")
head(countries)
## Country Code LandArea Population Density GDP Rural CO2 PumpPrice
## 1 Afghanistan AFG 652.86 37.172 56.9 521 74.5 0.29 0.70
## 2 Albania ALB 27.40 2.866 104.6 5254 39.7 1.98 1.36
## 3 Algeria DZA 2381.74 42.228 17.7 4279 27.4 3.74 0.28
## 4 American Samoa ASM 0.20 0.055 277.3 NA 12.8 NA NA
## 5 Andorra AND 0.47 0.077 163.8 42030 11.9 5.83 NA
## 6 Angola AGO 1246.70 30.810 24.7 3432 34.5 1.29 0.97
## Military Health ArmedForces Internet Cell HIV Hunger Diabetes BirthRate
## 1 3.72 2.01 323 11.4 67.4 NA 30.3 9.6 32.5
## 2 4.08 9.51 9 71.8 123.7 0.1 5.5 10.1 11.7
## 3 13.81 10.73 317 47.7 111.0 0.1 4.7 6.7 22.3
## 4 NA NA NA NA NA NA NA NA NA
## 5 NA 14.02 NA 98.9 104.4 NA NA 8.0 NA
## 6 9.40 5.43 117 14.3 44.7 1.9 23.9 3.9 41.3
## DeathRate ElderlyPop LifeExpectancy FemaleLabor Unemployment Energy
## 1 6.6 2.6 64.0 50.3 1.5 NA
## 2 7.5 13.6 78.5 55.9 13.9 808
## 3 4.8 6.4 76.3 16.4 12.1 1328
## 4 NA NA NA NA NA NA
## 5 NA NA NA NA NA NA
## 6 8.4 2.5 61.8 76.4 7.3 545
## Electricity Developed
## 1 NA NA
## 2 2309 1
## 3 1363 1
## 4 NA NA
## 5 NA NA
## 6 312 1
Fit a simple linear regression model predicting
LifeExpectancy from GDP.
# Your code:
Linreg <- lm(LifeExpectancy ~ GDP, data = countries)
summary(Linreg)
##
## Call:
## lm(formula = LifeExpectancy ~ GDP, data = countries)
##
## Residuals:
## Min 1Q Median 3Q Max
## -16.352 -3.882 1.550 4.458 9.330
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 6.842e+01 5.415e-01 126.36 <2e-16 ***
## GDP 2.476e-04 2.141e-05 11.56 <2e-16 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 5.901 on 177 degrees of freedom
## (38 observations deleted due to missingness)
## Multiple R-squared: 0.4304, Adjusted R-squared: 0.4272
## F-statistic: 133.7 on 1 and 177 DF, p-value: < 2.2e-16
Report the intercept and slope. What does the slope mean in plain English (e.g., “for every X increase in GDP, life expectancy increases by Y”)?
#The slope means that for every one-unit increase in GDP, life expectancy is expected to change by the slopes average value.
What does the R² value tell you about how well GDP explains life expectancy?
Fit a multiple regression predicting LifeExpectancy from
GDP, Health, and Internet.
# Your code:
Linreg2 <- lm(LifeExpectancy ~ GDP + Health + Internet, data = countries)
summary(Linreg2)
##
## Call:
## lm(formula = LifeExpectancy ~ GDP + Health + Internet, data = countries)
##
## Residuals:
## Min 1Q Median 3Q Max
## -14.5662 -1.8227 0.4108 2.5422 9.4161
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 5.908e+01 8.149e-01 72.499 < 2e-16 ***
## GDP 2.367e-05 2.287e-05 1.035 0.302025
## Health 2.479e-01 6.619e-02 3.745 0.000247 ***
## Internet 1.903e-01 1.656e-02 11.490 < 2e-16 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 4.104 on 169 degrees of freedom
## (44 observations deleted due to missingness)
## Multiple R-squared: 0.7213, Adjusted R-squared: 0.7164
## F-statistic: 145.8 on 3 and 169 DF, p-value: < 2.2e-16
Interpret the coefficient on Health (controlling
for GDP and Internet).
#The Health coefficient represents how much life expectancy is expected to change for every one-unit increase in Health but maintaining GDP& Internet the same.
How does the adjusted R² compare to the simple model in Q1? What does that suggest about adding predictors?
#The adjusted R^2 model compres to the simple model as it accounts for more nuance within the facets of the research topic explored. It suggests the importance that accounting for all attributing factors to best explain the differences in life expectancy
For the simple model in Q1 (LifeExpectancy ~ GDP):
Briefly describe what you would CHECK to evaluate homoscedasticity and normality of residuals. What would an ideal outcome look like? #In regards to homoscedasticity I checked the residual plot to examine whether the points are randomly scattered or have a distinct pattern. In terms of normality I checked the QQ plot to see if the points follow the straight line. Only if the two can be determined then one can determine whether the assumptions are reasonably met.
Then code your check (residual plot + Q-Q plot of residuals) and reflect on what you see.
# Your code:
plot(Linreg, which = 1)
plot(Linreg, which = 2)
Your reflection: #The residual plot is not scattered as the points follow a curved pattern instead of being evenly scattered around zero. This signifies the relationship between GDP and life expectancy cannot not be seen as perfectly linear. The QQ plot mostly follows the line in the middle, but the points start to move away from the line at both ends. In analyzin the plots I make assertion that the assumptions are only partially met, making the model a moderate but not strong line of reasoning. —
For the multiple regression in Q2, calculate the RMSE (root mean squared error).
# Hint: sqrt(mean(residuals(model)^2))
sqrt(mean(residuals(Linreg2)^2))
## [1] 4.056417
What does the RMSE represent in the context of predicting life expectancy? How would large residuals for certain countries affect your confidence in the model?
Suppose you fit a regression predicting CO2 using both
Energy and Electricity. These two predictors
are highly correlated.
Explain in 2-3 sentences how this multicollinearity could affect (a) the interpretation of the coefficients and (b) the reliability of the model. #If Energy and Electricity are highly correlated, it becomes harder to tell which variable is actually affecting CO2 because they contain similar information. This can make the coefficients less reliable and cause the model estimates to change more than expected.
This part uses the Pima Indians Diabetes dataset (768 patients, binary outcome: 0 = no diabetes, 1 = diabetes).
Don’t change this chunk — it loads and cleans the data:
url <- "https://raw.githubusercontent.com/jbrownlee/Datasets/master/pima-indians-diabetes.data.csv"
data <- read.csv(url, header = FALSE)
colnames(data) <- c("Pregnancies", "Glucose", "BloodPressure", "SkinThickness",
"Insulin", "BMI", "DiabetesPedigreeFunction", "Age", "Outcome")
data$Outcome <- as.factor(data$Outcome)
# Replace impossible 0 values with NA
data$Glucose[data$Glucose == 0] <- NA
data$BloodPressure[data$BloodPressure == 0] <- NA
data$BMI[data$BMI == 0] <- NA
colSums(is.na(data))
## Pregnancies Glucose BloodPressure
## 0 5 35
## SkinThickness Insulin BMI
## 0 0 11
## DiabetesPedigreeFunction Age Outcome
## 0 0 0
Fit a logistic regression predicting Outcome from
Glucose, BMI, and Age.
# Hint: glm(Outcome ~ Glucose + BMI + Age, data = data, family = "binomial")
Linreg3 <- glm(Outcome ~ Glucose + BMI + Age,
data = data,
family = "binomial")
summary(Linreg3)
##
## Call:
## glm(formula = Outcome ~ Glucose + BMI + Age, family = "binomial",
## data = data)
##
## Coefficients:
## Estimate Std. Error z value Pr(>|z|)
## (Intercept) -9.032377 0.711037 -12.703 < 2e-16 ***
## Glucose 0.035548 0.003481 10.212 < 2e-16 ***
## BMI 0.089753 0.014377 6.243 4.3e-10 ***
## Age 0.028699 0.007809 3.675 0.000238 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## (Dispersion parameter for binomial family taken to be 1)
##
## Null deviance: 974.75 on 751 degrees of freedom
## Residual deviance: 724.96 on 748 degrees of freedom
## (16 observations deleted due to missingness)
## AIC: 732.96
##
## Number of Fisher Scoring iterations: 4
Get the summary of the model. For each predictor, does an increase RAISE or LOWER the odds of diabetes? Which predictors are significant (p < 0.05)?
#Glucose increase raises the odds of diabetes, BMI increase raises the odds of diabetes, and increase in Age.
#The statistically significant predictors are all three again, Glucose, BMI, and Age as they are all less than p < 0.05.
Use threshold 0.5 to convert predicted probabilities into 0/1 predictions, then build a confusion matrix.
# Hint:
# data$pred_prob <- predict(model, data, type = "response")
# data$pred_class <- ifelse(data$pred_prob > 0.5, 1, 0)
# table(Actual = data$Outcome, Predicted = data$pred_class)
data$pred_prob <- predict (Linreg3, data,
type = "response")
data$pred_class <- ifelse(data$pred_prob > 0.5, 1, 0)
table(Actual = data$Outcome,
Predicted = data$pred_class)
## Predicted
## Actual 0 1
## 0 429 59
## 1 114 150
Report the confusion matrix counts: TP, TN, FP, FN.
From your confusion matrix, calculate accuracy, precision, and recall.
# Your code:
cm <- table(Actual = data$Outcome, Predicted = data$pred_class)
TP <- cm[2,2]
TN <- cm[1,1]
FP <- cm[1,2]
FN <- cm[2,1]
accuracy <- (TP + TN) / sum(cm)
precision <- TP / (TP + FP)
recall <- TP / (TP + FN)
accuracy
## [1] 0.7699468
precision
## [1] 0.7177033
recall
## [1] 0.5681818
Report all three values. In a medical screening context, which is more important — precision or recall? Why? #[1] 0.7699468 #[2] 0.7177033 #[3] 0.5681818
#In a medical screening test, precision is more important than recall as making any error in collection of biometric data can jeapordize the integreity of the data used in conducting fair statisical analysis.
Plot the ROC curve and compute the AUC.
# install.packages("pROC") if needed
library(pROC)
## Type 'citation("pROC")' for a citation.
##
## Attaching package: 'pROC'
## The following objects are masked from 'package:stats':
##
## cov, smooth, var
# Your code:
roc_curve <- roc(data$Outcome, data$pred_prob)
## Setting levels: control = 0, case = 1
## Setting direction: controls < cases
plot(roc_curve)
auc(roc_curve)
## Area under the curve: 0.828
Report the AUC. Is your model closer to random guessing (AUC = 0.5) or perfect (AUC = 1)? Describe its overall performance in one sentence.
#The models AUC consists of how well the model separates people with and without diabetes. A value closer to 1 indicates the models perform notably well, while a value closer to 0.5 means it is as significant as a blind guess.