GMAT Quant: Mixture Problems — Complete Concept Notes

1. What Counts as a “Mixture Problem”

GMAT mixture problems fall into four families. Recognizing which one you’re facing is half the battle:

  1. Simple two-component mixing — combining two solutions/groups with different concentrations to get a target concentration (alligation problems)
  2. Replacement/dilution problems — repeatedly removing some mixture and replacing with pure solvent (or another substance)
  3. Weighted average problems — mixtures of prices, scores, speeds, or populations (same math as concentration, different dressing)
  4. Solid mixture/ratio problems — combining quantities of different items (nuts, coins, populations) to satisfy a ratio or cost constraint

All four reduce to the same core idea: a mixture’s overall property is a weighted average of its components’ properties, weighted by quantity.


2. The Core Formula (Master Equation)

For two components A and B mixed into mixture M:

(Quantity_A × Concentration_A) + (Quantity_B × Concentration_B) = Quantity_M × Concentration_M

Where Quantity_M = Quantity_A + Quantity_B.

This single equation solves nearly every basic mixture problem. Everything else (alligation, etc.) is a shortcut derived from this.


3. The Alligation Method (Fastest Tool — Learn This Cold)

Alligation is a shortcut for two-component mixture ratio problems. It avoids setting up algebra.

Setup:

    A          B
     \        /
      \      /
       Mix (M)
      /      \
     /        \
(B − M)      (M − A)

Rule: The ratio of quantities of A to B equals the ratio of the differences (cross-subtracted), taken so both differences are positive:

Quantity_A : Quantity_B = (Value_B − Value_M) : (Value_M − Value_A)

Example: Mix a 20% solution with a 50% solution to get a 30% solution. - A = 20, B = 50, M = 30 - Ratio A:B = (50−30) : (30−20) = 20:10 = 2:1 - So you need 2 parts of the 20% solution for every 1 part of the 50% solution.

Why it works: It’s just the master equation rearranged — alligation is algebra in disguise, but much faster under time pressure. This is the single highest-leverage technique for this topic; memorize the diagram, not just the formula.

Visual/intuitive check: The mixture’s value always sits closer to the component with more quantity — like a seesaw balancing around a fulcrum. If M is much closer to A than to B, then A makes up the bigger share.


4. Weighted Average Framing

Many “mixture” problems on GMAT aren’t chemistry at all — they’re disguised weighted averages: - Average price per item when buying at two different prices - Average score combining two class sections - Average speed for two legs of a trip (weighted by time, not distance — common trap) - Combined population/employee ratios (e.g., % of men in a combined company after merger)

Key insight: Whenever you see “X% of group 1 has property P, Y% of group 2 has property P, what % of the combined group has property P?” — this is alligation with concentrations P over each group’s size.

Common trap: For average speed, weighting is by time spent, not distance — unless equal distances are traveled, the simple average of two speeds is wrong. Use:

Average speed = Total distance / Total time

5. Mixture Replacement (Repeated Dilution) Problems

Setup: A container has volume V of pure liquid (or mixture). You repeatedly remove a fixed amount/fraction and replace it with water (or another substance), n times.

Key Formula:

Final amount of original substance = V × (1 − x/V)^n

where x = amount removed/replaced each time, n = number of repetitions.

Example: A 10-liter container is full of pure milk. Each time, 2 liters are removed and replaced with water, repeated 3 times. How much milk remains?

Milk remaining = 10 × (1 − 2/10)^3 = 10 × (0.8)^3 = 10 × 0.512 = 5.12 liters

Notes: - This formula only applies when the same fraction is removed each time (not necessarily the same absolute amount each time, but GMAT almost always uses constant amount + constant total volume, making fraction constant too). - If the problem only does this once, you don’t need the exponent formula — just track amounts directly; reserve the formula for 2+ iterations. - Always double check whether the question asks for the substance remaining or the substance removed/replaced (1 − remaining fraction).


6. Solid/Discrete Mixture Problems (Ratios & Costs)

These involve combining discrete items (not liquids) — e.g., “a bag has red and blue marbles in ratio 3:5, how many of each to add to change the ratio to 1:1.”

Approach: 1. Let original quantities be 3k and 5k (using the given ratio with a variable multiplier) 2. Set up an equation based on what’s added/removed 3. Solve for k, then answer the specific question

Cost-based version: “Coffee A costs $4/lb, Coffee B costs $6/lb. How many lbs of each to make 10 lbs worth $5.20/lb total?” - This is alligation again, with price as the “concentration”: - Ratio A:B = (6 − 5.20) : (5.20 − 4) = 0.8 : 1.2 = 2:3 - Total parts = 5, total weight = 10 lbs → A = 4 lbs, B = 6 lbs


7. Step-by-Step Problem-Solving Framework

  1. Identify the type: simple mix, replacement/dilution, weighted average, or solid ratio.
  2. Define variables for unknown quantities (use ratio variables like 3k, 5k when a ratio is given — this often avoids fractions).
  3. Choose the tool:
    • Two components, asked for ratio → Alligation
    • Two components, asked for absolute amounts → Master equation (weighted sum)
    • Repeated removal/replacement → Exponent formula
    • “% of combined group” → Alligation framing on group sizes
  4. Write one clean equation — resist the urge to track too many variables; mixture problems almost always reduce to a single linear equation if you set them up with ratio multipliers.
  5. Sanity-check the answer against the “seesaw” intuition: the mixture value must lie between the two component values, and the side with more quantity should pull the mixture value closer to itself.

8. Common GMAT Traps (Where Points Are Lost)

Trap Why it happens Fix
Averaging percentages directly Treating 20% and 50% mix as 35% regardless of quantity Only true if equal quantities — otherwise weighted average required
Speed mixtures averaged by distance instead of time Misapplying “average of two numbers” Use total distance ÷ total time
Forgetting “remaining” vs “removed” in dilution Question asks for amount removed, you compute amount remaining Re-read final question line carefully before bubbling answer
Applying exponent formula to a single removal Overcomplicating one-step problems Use exponent formula only for n ≥ 2 repeated replacements
Mixing up which difference goes with which quantity in alligation Cross-multiplication direction confusion Remember: quantity of A pairs with the farther difference (B − M), not (M − A)
Ratio problems where “parts” ≠ actual units Assuming k = 1 Always solve for k using a given total or given quantity before finalizing the answer

9. Quick Reference Card

  • Master equation: Q_A·C_A + Q_B·C_B = Q_M·C_M
  • Alligation ratio: Q_A : Q_B = (C_B − C_M) : (C_M − C_A)
  • Repeated replacement: Remaining = V(1 − x/V)^n
  • Average speed: Total distance ÷ Total time (NOT simple average of speeds)
  • Mixture value always lies between the two component values — use this to sanity-check every answer, including on Data Sufficiency questions where you don’t need an exact number, just a range check.

10. Why This Matters for Your Pacing Issue

Since your diagnosed bottleneck is end-of-section rushing rather than knowledge gaps, the highest-leverage move for mixture problems specifically is to default to alligation first before writing algebra — it’s typically 2-3 steps faster than setting up the master equation from scratch, which directly protects your pacing on Quant. Reserve full algebraic setup only for replacement/dilution problems or multi-component (3+) mixtures where alligation doesn’t directly apply.