Calculate descriptive statistics for \([1,8,5,4,7,5,6,3,6,4,7,5,7,5]\).
# install.packages("summarytools")
library(summarytools)
nums <- c(1,8,5,4,7,5,6,3,6,4,7,5,7,5)
descr(nums)
## Descriptive Statistics
## nums
## N: 14
##
## nums
## ----------------- --------
## Mean 5.21
## Std.Dev 1.85
## Min 1.00
## Q1 4.00
## Median 5.00
## Q3 7.00
## Max 8.00
## MAD 1.48
## IQR 2.50
## CV 0.35
## Skewness -0.56
## SE.Skewness 0.60
## Kurtosis -0.33
## N.Valid 14.00
## N 14.00
## Pct.Valid 100.00
Find the derivative of the function \(h(x) = \frac{\cos(x)}{\sin^2 (x)}\).
# install.packages("Deriv")
library(Deriv)
h <- function(x) {
cos(x) / ((sin(x))^2)
}
h_prime <- Deriv(h)
h_prime
## function (x)
## {
## .e1 <- sin(x)
## -((1 + 2 * (cos(x)^2/.e1^2))/.e1)
## }
Evaluate the following limit.
\[\lim_{x \to \infty} \frac{1}{x - 1}\]
# install.packages("Ryacas")
library(Ryacas)
## Warning: package 'Ryacas' was built under R version 4.5.2
##
## Attaching package: 'Ryacas'
## The following object is masked from 'package:stats':
##
## integrate
## The following objects are masked from 'package:base':
##
## %*%, det, diag, diag<-, lower.tri, upper.tri
x <- ysym("x")
f <- 1 / (x - 1)
result <- lim(f,x,Inf)
result
## y: 0
A special die is made in the shape of an octahedron. The die has 8 (equilateral) triangular faces marked with the numbers 1 to 8. The die is thrown 30 times. Run a Monte Carlo simulation to determine the probability that the number is prime.
# install.packages("pracma")
library(pracma) # for the isprime() function
die <- 1:8 # 1 to 8 inclusive - possible rolls
counter <- 0 # number of prime numbers
N <- 30 # 30 rolls
for (i in 1:N) {
roll <- sample(x = die,size = 1,replace = T)
if (isprime(roll) == TRUE) {
counter <- counter + 1
}
}
probability <- counter / N
cat("The probability of rolling a prime number is:",probability,"\n")
## The probability of rolling a prime number is: 0.4666667
The data frame below shows the number of days of sunshine at a popular resort for each month of last year. Construct a bar graph for the data and determine how many months had less than 15 days of sunshine.
q5_data <- data.frame(Month = month.name, # month.name: built-in R constant that has the months of the year as strings
Days = c(20,11,12,15,21,23,29,22,19,10,12,14))
q5_data
## Month Days
## 1 January 20
## 2 February 11
## 3 March 12
## 4 April 15
## 5 May 21
## 6 June 23
## 7 July 29
## 8 August 22
## 9 September 19
## 10 October 10
## 11 November 12
## 12 December 14
# install.packages("tidyverse")
library(tidyverse)
## Warning: package 'lubridate' was built under R version 4.5.2
## ── Attaching core tidyverse packages ──────────────────────── tidyverse 2.0.0 ──
## ✔ dplyr 1.1.4 ✔ readr 2.1.5
## ✔ forcats 1.0.1 ✔ stringr 1.5.2
## ✔ ggplot2 4.0.0 ✔ tibble 3.3.0
## ✔ lubridate 1.9.4 ✔ tidyr 1.3.1
## ✔ purrr 1.1.0
## ── Conflicts ────────────────────────────────────────── tidyverse_conflicts() ──
## ✖ purrr::cross() masks pracma::cross()
## ✖ dplyr::filter() masks stats::filter()
## ✖ dplyr::lag() masks stats::lag()
## ✖ purrr::simplify() masks Ryacas::simplify()
## ✖ tibble::view() masks summarytools::view()
## ℹ Use the conflicted package (<http://conflicted.r-lib.org/>) to force all conflicts to become errors
ggplot(q5_data,aes(x = factor(Month,levels = month.name),y = Days)) +
geom_col() +
labs(title = "Number of Days of Sunshine for the Resort",
x = "Month",
y = "Number of Days of Sunshine") +
theme_gray(base_size = 14) +
theme(axis.text.x = element_text(hjust = 1,angle = 45))
# install.packages("tidyverse")
library(tidyverse)
answer <- q5_data %>%
filter(Days < 15) %>%
nrow()
cat("There are",answer,"months with less than 15 days of sunshine.","\n")
## There are 5 months with less than 15 days of sunshine.