library(readxl)
library(ggpubr)
## Loading required package: ggplot2
library(dplyr)
##
## Attaching package: 'dplyr'
## The following objects are masked from 'package:stats':
##
## filter, lag
## The following objects are masked from 'package:base':
##
## intersect, setdiff, setequal, union
library(effectsize)
library(effsize)
library(rstatix)
##
## Attaching package: 'rstatix'
## The following objects are masked from 'package:effectsize':
##
## cohens_d, eta_squared
## The following object is masked from 'package:stats':
##
## filter
A6Q3_2 <- read_excel("C:/Users/Owner/Documents/Alida/A6Q3-2.xlsx")
A6Q3_2 %>%
group_by(Exercise) %>%
summarise(
Mean = mean(Weight, na.rm = TRUE),
Median = median(Weight, na.rm = TRUE),
SD = sd(Weight, na.rm = TRUE),
N = n()
)
## # A tibble: 2 × 5
## Exercise Mean Median SD N
## <chr> <dbl> <dbl> <dbl> <int>
## 1 cardio 74.7 73.3 7.57 25
## 2 nocardio 70.8 69.5 7.35 25
hist(A6Q3_2$Weight[A6Q3_2$Exercise == "cardio"],
main = "Histogram of cardio ",
xlab = "Value",
ylab = "Frequency",
col = "lightblue",
border = "black",
breaks = 10)

hist(A6Q3_2$Weight[A6Q3_2$Exercise == "nocardio"],
main = "Histogram of nocardio ",
xlab = "Value",
ylab = "Frequency",
col = "lightgreen",
border = "black",
breaks = 10)

#Group 1: cardio
#The first variable looks normally distributed.
#The data is positive skewed
#The data has a proper bell curve.
#Group 2: nocardio
#The second variable looks normally distributed.
#The data is negative skewed
#The data has a proper bell curve.
ggboxplot(A6Q3_2, x = "Exercise", y = "Weight",
color = "Exercise",
palette = "jco",
add = "jitter")

#Boxplot 1: cardio
#There are dot outside the boxplot.
#The dot are close to the whisker.
#The dots are not very far away from the whiskers.
#The outliers are balanced
#Based on these findings, the boxplot is normal.
#Boxplot 2: nocardio
#There are dots outside the boxplot.
#The dots are close to the whiskers.
#The dots are not very far away from the whiskers.
#The outliers are balanced.
#Based on these findings, the boxplot is normal.
shapiro.test(A6Q3_2$Weight[A6Q3_2$Exercise == "cardio"])
##
## Shapiro-Wilk normality test
##
## data: A6Q3_2$Weight[A6Q3_2$Exercise == "cardio"]
## W = 0.96745, p-value = 0.5812
shapiro.test(A6Q3_2$Weight[A6Q3_2$Exercise == "nocardio"])
##
## Shapiro-Wilk normality test
##
## data: A6Q3_2$Weight[A6Q3_2$Exercise == "nocardio"]
## W = 0.97686, p-value = 0.8166
#Group 1:cardio
#The first group is normally distributed, (p = .581).
#Group 2:nocardio
#The second group is normally distributed, (p = .816).
t.test(Weight ~ Exercise, data = A6Q3_2, var.equal = TRUE)
##
## Two Sample t-test
##
## data: Weight by Exercise
## t = 1.8552, df = 48, p-value = 0.06971
## alternative hypothesis: true difference in means between group cardio and group nocardio is not equal to 0
## 95 percent confidence interval:
## -0.3280454 8.1605622
## sample estimates:
## mean in group cardio mean in group nocardio
## 74.73336 70.81710
# An Independent T-Test was conducted to determine if there was a difference in Weight between nocardio and cardio groups.
#cardio scores (M = 74.7, SD = 7.57) were not significantly different from nocardio scores (M = 70.8, SD = 7.35), t(48) = 1.855, p= >.05