Introduction

In Part 1, we introduced the logistic model, the logit transformation, and the connection between logistic regression coefficients and odds ratios. We fit simple logistic regression models with single predictors and previewed multiple logistic regression.

In Part 2, we go deeper:

  1. Multiple logistic regression with adjusted odds ratios for confounder control
  2. Maximum likelihood estimation and the Wald and likelihood ratio tests
  3. Confidence intervals for adjusted odds ratios
  4. Interaction terms in logistic regression and effect modification
  5. Goodness-of-fit: deviance, Hosmer-Lemeshow test, pseudo-R²
  6. Model discrimination: ROC curves and the area under the curve (AUC)
  7. Diagnostics: residuals, influential observations, and linearity in the logit

Textbook reference: Kleinbaum et al., Chapter 22 (Sections 22.4 and 22.5)

Setup and Data

library(tidyverse)
library(knitr)
library(kableExtra)
library(broom)
library(gtsummary)
library(car)
library(ggeffects)
library(ResourceSelection)  # for Hosmer-Lemeshow
library(pROC)               # for ROC/AUC
library(performance)        # for model performance metrics
library(sjPlot)
library(modelsummary)

options(gtsummary.use_ftExtra = TRUE)
set_gtsummary_theme(theme_gtsummary_compact(set_theme = TRUE))
brfss_logistic <- readRDS(
  "C:/Users/tahia/OneDrive/Desktop/UAlbany PhD/Epi 553/Lab 12/brfss_logistic_2020.rds"
)

dim(brfss_logistic)
## [1] 5000   10

Outcome: fmd — Frequent Mental Distress (1 = 14+ mentally unhealthy days in past 30, 0 = otherwise).

Part 1: Multiple Logistic Regression

The Adjusted Model

We extend the simple model to include several predictors:

\[\text{logit}[\Pr(Y = 1)] = \beta_0 + \beta_1 X_1 + \beta_2 X_2 + \cdots + \beta_k X_k\]

Each coefficient \(\beta_j\) represents the change in log-odds for a one-unit increase in \(X_j\), holding all other predictors constant. Exponentiating gives the adjusted odds ratio:

\[\text{aOR}_j = e^{\beta_j}\]

mod_full <- glm(
  fmd ~ exercise + smoker + age + sex + sleep_hrs + income_cat + bmi + physhlth_days,
  data = brfss_logistic,
  family = binomial(link = "logit")
)

mod_full |>
  tbl_regression(
    exponentiate = TRUE,
    label = list(
      exercise      ~ "Exercise (past 30 days)",
      smoker        ~ "Smoking status",
      age           ~ "Age (per year)",
      sex           ~ "Sex",
      sleep_hrs     ~ "Sleep hours",
      income_cat    ~ "Income category (per unit)",
      bmi           ~ "BMI",
      physhlth_days ~ "Physically unhealthy days"
    )
  ) |>
  bold_labels() |>
  bold_p()
Characteristic OR 95% CI p-value
Exercise (past 30 days)


    No — —
    Yes 0.82 0.68, 0.99 0.041
Smoking status


    Former/Never — —
    Current 1.30 1.09, 1.56 0.004
Age (per year) 0.97 0.96, 0.97 <0.001
Sex


    Male — —
    Female 1.68 1.41, 1.98 <0.001
Sleep hours 0.86 0.81, 0.90 <0.001
Income category (per unit) 0.91 0.87, 0.95 <0.001
BMI 1.01 0.99, 1.02 0.4
Physically unhealthy days 1.06 1.06, 1.07 <0.001
Abbreviations: CI = Confidence Interval, OR = Odds Ratio

Interpretation: Each row gives the adjusted odds ratio (aOR) and 95% CI for one predictor, controlling for all others. For example, the aOR for current smoking compares the odds of frequent mental distress for current smokers vs. former/never smokers, after adjusting for age, sex, sleep, income, BMI, exercise, and physical health. An aOR > 1 indicates a risk factor; an aOR < 1 indicates a protective factor.

Scaling Continuous Predictors

A 1-year change in age or a 1-unit change in BMI is rarely the most clinically meaningful comparison. We can rescale to improve interpretation:

mod_scaled <- glm(
  fmd ~ exercise + smoker + I(age/10) + sex + sleep_hrs +
        income_cat + I(bmi/5) + physhlth_days,
  data = brfss_logistic,
  family = binomial
)

mod_scaled |>
  tbl_regression(
    exponentiate = TRUE,
    label = list(
      "I(age/10)"  ~ "Age (per 10 years)",
      "I(bmi/5)"   ~ "BMI (per 5 units)"
    )
  ) |>
  bold_labels()
Characteristic OR 95% CI p-value
exercise


    No — —
    Yes 0.82 0.68, 0.99 0.041
smoker


    Former/Never — —
    Current 1.30 1.09, 1.56 0.004
Age (per 10 years) 0.73 0.69, 0.77 <0.001
sex


    Male — —
    Female 1.68 1.41, 1.98 <0.001
sleep_hrs 0.86 0.81, 0.90 <0.001
income_cat 0.91 0.87, 0.95 <0.001
BMI (per 5 units) 1.03 0.97, 1.10 0.4
physhlth_days 1.06 1.06, 1.07 <0.001
Abbreviations: CI = Confidence Interval, OR = Odds Ratio

Interpretation: Now the aOR for age compares two individuals 10 years apart, and the aOR for BMI compares two individuals 5 BMI units apart, both more clinically interpretable.

Part 2: Maximum Likelihood Estimation and Hypothesis Tests

Maximum Likelihood Estimation (ML)

Unlike linear regression, which uses ordinary least squares, logistic regression coefficients are estimated by maximum likelihood. The algorithm finds the values of \(\beta_0, \beta_1, \ldots, \beta_k\) that maximize the likelihood of observing the data.

The likelihood function for \(n\) independent binary observations is:

\[L(\boldsymbol{\beta}) = \prod_{i=1}^{n} p_i^{y_i}(1 - p_i)^{1 - y_i}\]

where \(p_i = \Pr(Y_i = 1 \mid X_i)\) is the predicted probability for observation \(i\). Taking the log gives the log-likelihood:

\[\ln L(\boldsymbol{\beta}) = \sum_{i=1}^{n} \left[y_i \ln p_i + (1 - y_i) \ln(1 - p_i)\right]\]

The ML estimates \(\hat{\beta}\) are obtained iteratively (typically by Newton-Raphson). We never compute these by hand, but it is important to know that R’s glm() reports Deviance \(= -2 \ln \hat{L}\), which is the foundation for hypothesis testing.

Wald Test (z-test for individual coefficients)

The Wald test is the default test reported by summary() and tidy(). For each coefficient \(\beta_j\):

\[z = \frac{\hat{\beta}_j}{\text{SE}(\hat{\beta}_j)} \sim N(0, 1) \text{ under } H_0: \beta_j = 0\]

The p-value tests whether the coefficient is significantly different from zero, equivalently whether the OR is significantly different from 1.

tidy(mod_full, conf.int = TRUE, exponentiate = TRUE) |>
  mutate(across(c(estimate, std.error, statistic, conf.low, conf.high),
                \(x) round(x, 3)),
         p.value = format.pval(p.value, digits = 3)) |>
  kable(caption = "Wald Tests for Each Coefficient (Exponentiated)") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
Wald Tests for Each Coefficient (Exponentiated)
term estimate std.error statistic p.value conf.low conf.high
(Intercept) 2.198 0.356 2.215 0.02675 1.095 4.414
exerciseYes 0.820 0.097 -2.044 0.04095 0.679 0.993
smokerCurrent 1.301 0.091 2.890 0.00386 1.088 1.555
age 0.969 0.003 -11.225 < 2e-16 0.963 0.974
sexFemale 1.675 0.086 5.975 2.30e-09 1.415 1.985
sleep_hrs 0.857 0.027 -5.643 1.67e-08 0.812 0.904
income_cat 0.909 0.020 -4.703 2.56e-06 0.873 0.946
bmi 1.006 0.006 0.932 0.35113 0.993 1.018
physhlth_days 1.065 0.004 15.634 < 2e-16 1.057 1.073

Caveat: The Wald test can be unreliable when sample sizes are small or when coefficients are large. The likelihood ratio test is generally preferred for these situations.

Likelihood Ratio Test (LR test)

The likelihood ratio test compares two nested models: a “full” model and a “reduced” model that drops one or more predictors. The test statistic is:

\[\text{LR} = -2(\ln \hat{L}_{\text{reduced}} - \ln \hat{L}_{\text{full}}) = D_{\text{reduced}} - D_{\text{full}}\]

Under \(H_0\) that the dropped predictors have no effect, LR follows a \(\chi^2\) distribution with degrees of freedom equal to the number of parameters dropped.

Example: Test the joint contribution of smoking and exercise

mod_reduced <- glm(
  fmd ~ age + sex + sleep_hrs + income_cat + bmi + physhlth_days,
  data = brfss_logistic,
  family = binomial
)

anova(mod_reduced, mod_full, test = "LRT") |>
  kable(digits = 3,
        caption = "LR Test: Does adding exercise + smoker improve the model?") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
LR Test: Does adding exercise + smoker improve the model?
Resid. Df Resid. Dev Df Deviance Pr(>Chi)
4993 3641.913 NA NA NA
4991 3628.474 2 13.439 0.001

Interpretation: The LR test gives a \(\chi^2\) statistic on 3 degrees of freedom (1 for exercise, 2 for smoker — but smoker has 2 levels so 1 dummy variable is created, making df = 2 here actually). A small p-value means the dropped variables jointly contribute to model fit.

Wald vs. LR test in practice

Aspect Wald test LR test
What it tests Single coefficient or vector Nested model comparison
Computational cost Very fast Requires fitting two models
Reliability with small samples Less reliable Generally preferred
Reported by R summary(model) anova(m1, m2, test = "LRT")

In large samples (like ours with n = 5,000), the two tests usually agree. In smaller samples or with extreme estimates, prefer the LR test.

Part 3: Confidence Intervals for Adjusted Odds Ratios

For the OR of a single coefficient, the 95% CI is computed on the log-odds scale and then exponentiated:

\[95\% \text{ CI for } e^{\beta_j} = \exp\left(\hat{\beta}_j \pm 1.96 \cdot \text{SE}(\hat{\beta}_j)\right)\]

This is the default approach used by confint() and tidy(..., conf.int = TRUE).

ci_table <- tidy(mod_full, conf.int = TRUE, exponentiate = TRUE) |>
  filter(term != "(Intercept)") |>
  dplyr::select(term, estimate, conf.low, conf.high) |>
  mutate(across(c(estimate, conf.low, conf.high), \(x) round(x, 3)))

ci_table |>
  kable(col.names = c("Predictor", "aOR", "95% CI Lower", "95% CI Upper"),
        caption = "Adjusted Odds Ratios with 95% CIs") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
Adjusted Odds Ratios with 95% CIs
Predictor aOR 95% CI Lower 95% CI Upper
exerciseYes 0.820 0.679 0.993
smokerCurrent 1.301 1.088 1.555
age 0.969 0.963 0.974
sexFemale 1.675 1.415 1.985
sleep_hrs 0.857 0.812 0.904
income_cat 0.909 0.873 0.946
bmi 1.006 0.993 1.018
physhlth_days 1.065 1.057 1.073

Forest Plot of Adjusted ORs

A forest plot is the standard way to visualize multiple ORs and their CIs:

ci_table |>
  ggplot(aes(x = estimate, y = reorder(term, estimate))) +
  geom_vline(xintercept = 1, linetype = "dashed", color = "red") +
  geom_point(size = 3, color = "steelblue") +
  geom_errorbarh(aes(xmin = conf.low, xmax = conf.high), height = 0.2,
                 color = "steelblue") +
  scale_x_log10() +
  labs(title = "Forest Plot of Adjusted Odds Ratios for Frequent Mental Distress",
       subtitle = "Reference line at OR = 1; log-scale x-axis",
       x = "Adjusted Odds Ratio (95% CI)", y = NULL) +
  theme_minimal()

Interpretation: Predictors whose CIs do not cross the dashed line at OR = 1 are statistically significantly associated with FMD at the 0.05 level. The log-scale x-axis ensures that ORs of 0.5 and 2.0 (which represent equally strong associations in opposite directions) appear equidistant from 1.

Part 4: Interaction (Effect Modification)

What Is Interaction in Logistic Regression?

Interaction (effect modification) occurs when the effect of one predictor on the outcome depends on the value of another predictor. In logistic regression, interaction is modeled by including a product term:

\[\text{logit}[\Pr(Y=1)] = \beta_0 + \beta_1 X_1 + \beta_2 X_2 + \beta_3 (X_1 \cdot X_2)\]

If \(\beta_3 \neq 0\), the OR for \(X_1\) depends on the value of \(X_2\).

Example: Does the effect of exercise differ by sex?

mod_interact <- glm(
  fmd ~ exercise * sex + age + smoker + sleep_hrs + income_cat,
  data = brfss_logistic,
  family = binomial
)

mod_interact |>
  tbl_regression(exponentiate = TRUE) |>
  bold_labels() |>
  bold_p()
Characteristic OR 95% CI p-value
exercise


    No — —
    Yes 0.61 0.47, 0.79 <0.001
sex


    Male — —
    Female 1.66 1.26, 2.21 <0.001
IMPUTED AGE VALUE COLLAPSED ABOVE 80 0.97 0.97, 0.98 <0.001
smoker


    Former/Never — —
    Current 1.25 1.05, 1.48 0.012
sleep_hrs 0.81 0.77, 0.86 <0.001
income_cat 0.85 0.82, 0.89 <0.001
exercise * sex


    Yes * Female 1.00 0.71, 1.41 >0.9
Abbreviations: CI = Confidence Interval, OR = Odds Ratio

Testing the Interaction

mod_no_interact <- glm(
  fmd ~ exercise + sex + age + smoker + sleep_hrs + income_cat,
  data = brfss_logistic,
  family = binomial
)

anova(mod_no_interact, mod_interact, test = "LRT") |>
  kable(digits = 3,
        caption = "LR Test for Exercise × Sex Interaction") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
LR Test for Exercise × Sex Interaction
Resid. Df Resid. Dev Df Deviance Pr(>Chi)
4993 3870.197 NA NA NA
4992 3870.197 1 0 0.987

Interpretation: If the p-value for the LR test is small (< 0.05), the interaction is statistically significant: the effect of exercise differs by sex. If not, we can drop the interaction term and use the simpler main-effects model.

Visualizing the Interaction

ggpredict(mod_interact, terms = c("exercise", "sex")) |>
  plot() +
  labs(title = "Predicted Probability of FMD by Exercise and Sex",
       x = "Exercise", y = "Predicted Probability of FMD",
       color = "Sex") +
  theme_minimal()

Interpretation: If the lines are parallel, there is no interaction. If they cross or diverge, the effect of exercise differs across sex.

Stratified Odds Ratios

When an interaction is present, we report stratum-specific odds ratios rather than a single overall OR:

# Stratum-specific ORs from the interaction model
ggpredict(mod_interact, terms = c("exercise", "sex")) |>
  as_tibble() |>
  pivot_wider(id_cols = group, names_from = x, values_from = predicted) |>
  mutate(OR_yes_vs_no = (Yes / (1 - Yes)) / (No / (1 - No))) |>
  dplyr::select(Sex = group, OR_yes_vs_no) |>
  kable(digits = 3,
        col.names = c("Sex", "OR (Exercise: Yes vs. No)"),
        caption = "Stratum-Specific Odds Ratios for Exercise") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
Stratum-Specific Odds Ratios for Exercise
Sex OR (Exercise: Yes vs. No)
Male 0.612
Female 0.614

Part 5: Goodness-of-Fit

Deviance

The deviance of a logistic model is:

\[D = -2 \ln \hat{L}\]

It is analogous to the residual sum of squares in linear regression: smaller is better. By itself, the deviance is hard to interpret, but differences in deviance between nested models follow a \(\chi^2\) distribution and form the basis of the LR test.

glance(mod_full) |>
  dplyr::select(null.deviance, df.null, deviance, df.residual, AIC, BIC) |>
  kable(digits = 1, caption = "Model Fit Statistics") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
Model Fit Statistics
null.deviance df.null deviance df.residual AIC BIC
4251.3 4999 3628.5 4991 3646.5 3705.1

Quick check: The difference between null.deviance and deviance represents the improvement from adding all predictors to an intercept-only model. We can test this with an LR test on df.null - df.residual degrees of freedom.

Pseudo-R²

There is no exact analog of \(R^2\) for logistic regression, but several “pseudo-R²” measures exist. The most common is McFadden’s R²:

\[R^2_{\text{McFadden}} = 1 - \frac{\ln \hat{L}_{\text{full}}}{\ln \hat{L}_{\text{null}}}\]

Values between 0.2 and 0.4 are considered excellent fit.

performance::r2_mcfadden(mod_full)
## # R2 for Generalized Linear Regression
##        R2: 0.147
##   adj. R2: 0.146

Interpretation: McFadden’s R² should not be interpreted on the same scale as linear regression R². Values are typically much smaller (e.g., 0.1 may indicate a reasonable fit).

Hosmer-Lemeshow Test

The Hosmer-Lemeshow test assesses the agreement between predicted and observed event rates within deciles of predicted probability. A non-significant p-value indicates adequate fit.

hl_test <- hoslem.test(
  x = as.numeric(brfss_logistic$fmd) - 1,
  y = fitted(mod_full),
  g = 10
)

hl_test
## 
##  Hosmer and Lemeshow goodness of fit (GOF) test
## 
## data:  as.numeric(brfss_logistic$fmd) - 1, fitted(mod_full)
## X-squared = 8.9639, df = 8, p-value = 0.3453

Interpretation: A small p-value (< 0.05) suggests that the model does not fit well in some regions of predicted probability. With large samples (like ours), the Hosmer-Lemeshow test can be over-powered and detect trivial misfit. Always pair it with a calibration plot.

Calibration Plot

brfss_logistic |>
  mutate(pred_prob = fitted(mod_full),
         obs_outcome = as.numeric(fmd) - 1,
         decile = ntile(pred_prob, 10)) |>
  group_by(decile) |>
  summarise(
    mean_pred = mean(pred_prob),
    mean_obs  = mean(obs_outcome),
    .groups = "drop"
  ) |>
  ggplot(aes(x = mean_pred, y = mean_obs)) +
  geom_abline(slope = 1, intercept = 0, color = "red", linetype = "dashed") +
  geom_point(size = 3, color = "steelblue") +
  geom_line(color = "steelblue") +
  labs(title = "Calibration Plot: Observed vs. Predicted Probability of FMD",
       subtitle = "Points should fall on the dashed line for perfect calibration",
       x = "Mean Predicted Probability (within decile)",
       y = "Observed Proportion (within decile)") +
  theme_minimal()

Interpretation: A well-calibrated model has points lying close to the 45-degree line. Systematic departures suggest miscalibration: points above the line indicate the model under-predicts; points below indicate over-prediction.

Part 6: Discrimination — ROC Curve and AUC

While calibration assesses how well predicted probabilities match observed rates, discrimination assesses how well the model separates events from non-events.

The ROC curve plots sensitivity (true positive rate) against 1 − specificity (false positive rate) across all possible probability cutoffs.

The AUC (area under the ROC curve) summarizes discrimination:

AUC Discrimination
0.5 No discrimination (chance)
0.6-0.7 Poor
0.7-0.8 Acceptable
0.8-0.9 Excellent
> 0.9 Outstanding 
roc_obj <- roc(
  response = brfss_logistic$fmd,
  predictor = fitted(mod_full),
  levels = c("No", "Yes"),
  direction = "<"
)

auc_value <- auc(roc_obj)

ggroc(roc_obj, color = "steelblue", linewidth = 1.2) +
  geom_abline(slope = 1, intercept = 1, linetype = "dashed", color = "red") +
  labs(title = "ROC Curve for Frequent Mental Distress Model",
       subtitle = paste0("AUC = ", round(auc_value, 3)),
       x = "Specificity", y = "Sensitivity") +
  theme_minimal()

Interpretation: An AUC of approximately 0.75-0.80 indicates acceptable to excellent discrimination, meaning the model can distinguish between individuals with and without FMD reasonably well. Note that calibration and discrimination are distinct concepts: a model can have good discrimination but poor calibration, or vice versa.

Part 7: Diagnostics for Logistic Regression

Linearity in the Logit (for continuous predictors)

For continuous predictors, logistic regression assumes a linear relationship between the predictor and the log-odds. We can check this with a smoothed plot of the logit against the predictor.

brfss_logistic |>
  mutate(logit_pred = predict(mod_full, type = "link")) |>
  ggplot(aes(x = age, y = logit_pred)) +
  geom_point(alpha = 0.2, color = "steelblue") +
  geom_smooth(method = "loess", se = FALSE, color = "darkorange") +
  labs(title = "Linearity in the Logit: Age",
       x = "Age (years)", y = "Predicted Log-Odds (logit)") +
  theme_minimal()

Interpretation: A roughly linear loess curve supports the linearity assumption. A clearly curved pattern suggests we should add a quadratic term or use a spline.

Influential Observations

Cook’s distance and standardized residuals from logistic regression can be examined the same way as in linear regression:

brfss_logistic |>
  mutate(cooks_d = cooks.distance(mod_full),
         row_id = row_number()) |>
  ggplot(aes(x = row_id, y = cooks_d)) +
  geom_point(alpha = 0.4, color = "steelblue") +
  geom_hline(yintercept = 4 / nrow(brfss_logistic),
             linetype = "dashed", color = "red") +
  labs(title = "Cook's Distance for Logistic Regression Model",
       subtitle = "Red line: 4/n threshold",
       x = "Observation Index", y = "Cook's Distance") +
  theme_minimal()

Multicollinearity

VIFs work the same way as in linear regression:

vif(mod_full) |>
  as.data.frame() |>
  rownames_to_column("Predictor") |>
  kable(digits = 2, caption = "Variance Inflation Factors") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
Variance Inflation Factors
Predictor vif(mod_full)
exercise 1.13
smoker 1.12
age 1.17
sex 1.01
sleep_hrs 1.02
income_cat 1.14
bmi 1.03
physhlth_days 1.20

Rule of thumb: VIF > 5 (or 10) indicates problematic multicollinearity.

Part 8: Reporting Logistic Regression Results

A publication-quality logistic regression table should include:

  1. Sample size and number of events
  2. Adjusted odds ratios with 95% CIs
  3. p-values for each coefficient
  4. Model fit statistics (AIC or pseudo-R²) - (may declutter)
  5. Discrimination metric (AUC) - (methodological purposes)
mod_full |>
  tbl_regression(
    exponentiate = TRUE,
    label = list(
      exercise      ~ "Exercise (past 30 days)",
      smoker        ~ "Smoking status",
      age           ~ "Age",
      sex           ~ "Sex",
      sleep_hrs     ~ "Sleep hours",
      income_cat    ~ "Income category",
      bmi           ~ "BMI",
      physhlth_days ~ "Physically unhealthy days"
    )
  ) |>
  add_glance_source_note(
    #include = c(nobs, AIC, BIC),
    include = everything(),
    label = list(nobs ~ "N", AIC ~ "AIC", BIC ~ "BIC")
  ) |>
  bold_labels() |>
  bold_p() |>
  modify_caption("**Adjusted Odds Ratios for Frequent Mental Distress, BRFSS 2020**")
Adjusted Odds Ratios for Frequent Mental Distress, BRFSS 2020
Characteristic OR 95% CI p-value
Exercise (past 30 days)


    No — —
    Yes 0.82 0.68, 0.99 0.041
Smoking status


    Former/Never — —
    Current 1.30 1.09, 1.56 0.004
Age 0.97 0.96, 0.97 <0.001
Sex


    Male — —
    Female 1.68 1.41, 1.98 <0.001
Sleep hours 0.86 0.81, 0.90 <0.001
Income category 0.91 0.87, 0.95 <0.001
BMI 1.01 0.99, 1.02 0.4
Physically unhealthy days 1.06 1.06, 1.07 <0.001
Abbreviations: CI = Confidence Interval, OR = Odds Ratio
Null deviance = 4,251; Null df = 4,999; Log-likelihood = -1,814; AIC = 3,646; BIC = 3,705; Deviance = 3,628; Residual df = 4,991; N = 5,000

Summary

Concept Tool / R function
Multiple logistic regression glm(y ~ x1 + x2 + ..., family = binomial)
Adjusted odds ratios tidy(model, exponentiate = TRUE)
Wald test Default in summary() and tidy()
Likelihood ratio test anova(reduced, full, test = "LRT")
Confidence intervals confint(model) (profile CI) or tidy(..., conf.int = TRUE)
Interaction glm(y ~ x1 * x2, ...); test with LR test
Pseudo-R² performance::r2_mcfadden()
Hosmer-Lemeshow ResourceSelection::hoslem.test()
Calibration plot Decile-based observed vs. predicted
ROC curve / AUC pROC::roc() and pROC::auc()
Diagnostics cooks.distance(), vif(), linearity plots
Publication table gtsummary::tbl_regression()

Next Lecture (April 16)

  • Polytomous logistic regression: outcomes with > 2 nominal categories
  • Ordinal logistic regression: outcomes with > 2 ordered categories
  • Proportional odds assumption and how to test it

References

  • Kleinbaum, D. G., Kupper, L. L., Nizam, A., & Rosenberg, E. S. (2013). Applied Regression Analysis and Other Multivariable Methods (5th ed.), Chapter 22.
  • Hosmer, D. W., Lemeshow, S., & Sturdivant, R. X. (2013). Applied Logistic Regression (3rd ed.). Wiley.
  • Steyerberg, E. W. (2019). Clinical Prediction Models (2nd ed.). Springer.

Part 9: In-Class Lab Activity

EPI 553 — Logistic Regression Part 2 Lab Due: End of class, April 14, 2026

Instructions

In this lab, you will build a multiple logistic regression model, conduct hypothesis tests, examine an interaction, and assess goodness-of-fit and discrimination. Use the same BRFSS 2020 logistic dataset from Part 1. Work through each task systematically. You may discuss concepts with classmates, but your written answers and R code must be your own.

Submission: Knit your .Rmd to HTML and upload to Brightspace by end of class.

Data for the Lab

Variable Description Type
fmd Frequent mental distress (No/Yes) Factor (outcome)
menthlth_days Mentally unhealthy days (0–30) Numeric
physhlth_days Physically unhealthy days (0–30) Numeric
sleep_hrs Sleep hours per night (1–14) Numeric
age Age in years (capped at 80) Numeric
sex Sex (Male/Female) Factor
bmi Body mass index Numeric
exercise Exercised in past 30 days (No/Yes) Factor
income_cat Household income category (1–8) Numeric
smoker Former/Never vs. Current Factor 
library(tidyverse)
library(broom)
library(knitr)
library(kableExtra)
library(gtsummary)
library(car)
library(ggeffects)
library(ResourceSelection)
library(pROC)
library(performance)

brfss_logistic <- readRDS(
  "C:/Users/tahia/OneDrive/Desktop/UAlbany PhD/Epi 553/Lab 12/brfss_logistic_2020.rds"
)

Task 1: Build a Multiple Logistic Regression Model (15 points)

1a. (5 pts) Fit a multiple logistic regression model predicting fmd from at least 5 predictors of your choice.

1b. (5 pts) Report the adjusted ORs with 95% CIs in a publication-quality table using tbl_regression().

1c. (5 pts) Interpret the adjusted OR for two predictors of your choice in 1-2 sentences each. Make sure to mention what the OR represents (per unit change for continuous; reference category for categorical).

1c Ans The results show that several factors are significantly associated with the outcome. Individuals who exercised in the past 30 days had 47% lower odds of the outcome compared to those who did not exercise (OR = 0.53, 95% CI: 0.45–0.63, p < 0.001). Age was also associated with lower odds, with a 3% decrease in odds for each additional year (OR = 0.97, 95% CI: 0.97–0.98, p < 0.001). Females had 78% higher odds compared to males (OR = 1.78, 95% CI: 1.52–2.10, p < 0.001). Additionally, each additional hour of sleep was associated with a 20% reduction in the odds of the outcome (OR = 0.80, 95% CI: 0.76–0.85, p < 0.001). BMI was not significantly associated with the outcome (OR = 1.01, 95% CI: 1.00–1.02, p = 0.11).

mod_new <- glm(
  fmd ~ exercise + age + sex + sleep_hrs + bmi,
  data = brfss_logistic,
  family = binomial(link = "logit")
)

mod_new |>
  tbl_regression(
    exponentiate = TRUE,
    label = list(
      exercise      ~ "Exercise (past 30 days)",
      age           ~ "Age (per year)",
      sex           ~ "Sex",
      sleep_hrs     ~ "Sleep hours",
      bmi           ~ "BMI"
    )
  ) |>
  bold_labels() |>
  bold_p()
Characteristic OR 95% CI p-value
Exercise (past 30 days)


    No — —
    Yes 0.53 0.45, 0.63 <0.001
Age (per year) 0.97 0.97, 0.98 <0.001
Sex


    Male — —
    Female 1.78 1.52, 2.10 <0.001
Sleep hours 0.80 0.76, 0.85 <0.001
BMI 1.01 1.00, 1.02 0.11
Abbreviations: CI = Confidence Interval, OR = Odds Ratio

Task 2: Wald and Likelihood Ratio Tests (15 points)

2a. (5 pts) Identify the Wald p-value for each predictor in your model from the tidy() or summary() output.

2b. (5 pts) Fit a reduced model that drops one predictor of your choice. Perform a likelihood ratio test comparing the full and reduced models using anova(reduced, full, test = "LRT").

2c. (5 pts) Compare the conclusions from the Wald test (for the dropped predictor) and the LR test. Do they agree? In 2-3 sentences, explain when the two tests might disagree.

2c Ans The Wald tests show that most predictors are significantly associated with the outcome. Exercise is associated with lower odds (OR = 0.53, 95% CI: 0.45–0.63, p < 0.001), while age also shows a small but significant decrease in odds (OR = 0.97, 95% CI: 0.97–0.98, p < 0.001). Females have significantly higher odds compared to males (OR = 1.78, 95% CI: 1.52–2.10, p < 0.001), and each additional hour of sleep reduces the odds by about 20% (OR = 0.80, 95% CI: 0.76–0.85, p < 0.001). BMI is not statistically significant (OR = 1.01, 95% CI: 1.00–1.02, p = 0.11). The likelihood ratio test comparing models with and without sex is highly significant (Deviance = 50.08, p < 0.001), indicating that adding sex significantly improves the model fit.

# 2a Wald p-value for each predictor
tidy(mod_new, conf.int = TRUE, exponentiate = TRUE) |>
  mutate(across(c(estimate, std.error, statistic, conf.low, conf.high),
                \(x) round(x, 3)),
         p.value = format.pval(p.value, digits = 3)) |>
  kable(caption = "Wald Tests for Each Coefficient (Exponentiated)") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
Wald Tests for Each Coefficient (Exponentiated)
term estimate std.error statistic p.value conf.low conf.high
(Intercept) 2.954 0.303 3.574 0.000351 1.632 5.357
exerciseYes 0.530 0.088 -7.180 6.95e-13 0.446 0.631
age 0.974 0.003 -10.276 < 2e-16 0.969 0.979
sexFemale 1.782 0.082 7.027 2.11e-12 1.518 2.095
sleep_hrs 0.801 0.028 -8.058 7.77e-16 0.758 0.845
bmi 1.010 0.006 1.602 0.109199 0.998 1.022 
# 2b reduced model that droping one predictor

mod_red <- glm(
  fmd ~ exercise + age + sleep_hrs + bmi,
  data = brfss_logistic,
  family = binomial
)

anova(mod_red, mod_new, test = "LRT") |>
  kable(digits = 3,
        caption = "LR Test: Does adding sex improve the model?") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
LR Test: Does adding sex improve the model?
Resid. Df Resid. Dev Df Deviance Pr(>Chi)
4995 4004.568 NA NA NA
4994 3954.489 1 50.078 0

Task 3: Test an Interaction (20 points)

3a. (5 pts) Fit a model that includes an interaction between two predictors of your choice (e.g., exercise * sex or smoker * age).

3b. (5 pts) Perform a likelihood ratio test comparing the model with the interaction to the model without it.

3c. (5 pts) Create a visualization of the interaction using ggpredict() and plot().

3d. (5 pts) In 3-4 sentences, interpret the interaction. Does the effect of one predictor differ across levels of the other? If statistically significant, report the stratum-specific odds ratios.

3d Ans The results show that exercise, sex, age, and sleep are significantly associated with the outcome, while BMI is not. Individuals who exercised had 46% lower odds of the outcome compared to those who did not (OR = 0.54, 95% CI: 0.42–0.70, p < 0.001). Females had higher odds than males (OR = 1.82, 95% CI: 1.38–2.41, p < 0.001). Increasing age and sleep were both associated with lower odds (age OR = 0.97, sleep OR = 0.80, both p < 0.001), while BMI was not significant (p = 0.11). The interaction between exercise and sex was not statistically significant (OR = 0.97, 95% CI: 0.69–1.36, p = 0.80), and the likelihood ratio test also confirmed no improvement in model fit when adding the interaction (Deviance = 0.036, p = 0.849). This suggests that the effect of exercise on the outcome does not differ by sex.

#3a model that includes an interaction

mod_intrct <- glm(
  fmd ~ exercise * sex + age + sleep_hrs + bmi,
  data = brfss_logistic,
  family = binomial
)

mod_intrct |>
  tbl_regression(exponentiate = TRUE) |>
  bold_labels() |>
  bold_p()
Characteristic OR 95% CI p-value
exercise


    No — —
    Yes 0.54 0.42, 0.70 <0.001
sex


    Male — —
    Female 1.82 1.38, 2.41 <0.001
IMPUTED AGE VALUE COLLAPSED ABOVE 80 0.97 0.97, 0.98 <0.001
sleep_hrs 0.80 0.76, 0.85 <0.001
bmi 1.01 1.00, 1.02 0.11
exercise * sex


    Yes * Female 0.97 0.69, 1.36 0.8
Abbreviations: CI = Confidence Interval, OR = Odds Ratio 
#3b likelihood ratio test comparing the models

anova(mod_new, mod_intrct, test = "LRT") |>
  kable(digits = 3,
        caption = "LR Test for Exercise × Sex Interaction") |>
  kable_styling(bootstrap_options = "striped", full_width = FALSE)
LR Test for Exercise × Sex Interaction
Resid. Df Resid. Dev Df Deviance Pr(>Chi)
4994 3954.489 NA NA NA
4993 3954.453 1 0.036 0.849 
#3c visualization of the interaction

ggpredict(mod_intrct, terms = c("exercise", "sex")) |>
  plot() +
  labs(title = "Predicted Probability of FMD by Exercise and Sex",
       x = "Exercise", y = "Predicted Probability of FMD",
       color = "Sex") +
  theme_minimal()

Task 4: Goodness-of-Fit and Discrimination (25 points)

4a. (5 pts) Compute McFadden’s pseudo-R² for your full model using performance::r2_mcfadden().

4b. (5 pts) Perform the Hosmer-Lemeshow goodness-of-fit test using ResourceSelection::hoslem.test(). Report the test statistic and p-value. Comment on the interpretation given your sample size.

4c. (5 pts) Create a calibration plot showing observed vs. predicted probabilities by decile. Comment on whether the model appears well calibrated.

4d. (10 pts) Compute and plot the ROC curve using pROC::roc(). Report the AUC. Based on the AUC value, how would you describe the model’s discrimination ability (poor, acceptable, excellent, outstanding)?

4d Ans The model shows moderate predictive performance. The ROC curve has an AUC of 0.688, indicating acceptable but not strong discrimination, meaning the model can somewhat distinguish between individuals with and without the outcome. McFadden’s pseudo-R² is 0.070 (adjusted R² = 0.069), suggesting that the model explains a relatively small proportion of the variability in the outcome. However, the Hosmer-Lemeshow test is not statistically significant (χ² = 11.33, df = 8, p = 0.184), indicating good model calibration and that the predicted probabilities fit the observed data well.

#4a McFadden's pseudo-R²

performance::r2_mcfadden(mod_new)
## # R2 for Generalized Linear Regression
##        R2: 0.070
##   adj. R2: 0.069
#4b Hosmer-Lemeshow goodness-of-fit test

hl_test1 <- hoslem.test(
  x = as.numeric(brfss_logistic$fmd) - 1,
  y = fitted(mod_new),
  g = 10
)

hl_test1
## 
##  Hosmer and Lemeshow goodness of fit (GOF) test
## 
## data:  as.numeric(brfss_logistic$fmd) - 1, fitted(mod_new)
## X-squared = 11.331, df = 8, p-value = 0.1836
#4c calibration plot showing observed vs. predicted probabilities

brfss_logistic |>
  mutate(pred_prob = fitted(mod_new),
         obs_outcome = as.numeric(fmd) - 1,
         decile = ntile(pred_prob, 10)) |>
  group_by(decile) |>
  summarise(
    mean_pred = mean(pred_prob),
    mean_obs  = mean(obs_outcome),
    .groups = "drop"
  ) |>
  ggplot(aes(x = mean_pred, y = mean_obs)) +
  geom_abline(slope = 1, intercept = 0, color = "red", linetype = "dashed") +
  geom_point(size = 3, color = "steelblue") +
  geom_line(color = "steelblue") +
  labs(title = "Calibration Plot: Observed vs. Predicted Probability of FMD",
       subtitle = "Points should fall on the dashed line for perfect calibration",
       x = "Mean Predicted Probability (within decile)",
       y = "Observed Proportion (within decile)") +
  theme_minimal()

#4d Compute and plot the ROC curve

roc_obj1 <- roc(
  response = brfss_logistic$fmd,
  predictor = fitted(mod_new),
  levels = c("No", "Yes"),
  direction = "<"
)

auc_value1 <- auc(roc_obj1)

ggroc(roc_obj1, color = "steelblue", linewidth = 1.2) +
  geom_abline(slope = 1, intercept = 1, linetype = "dashed", color = "red") +
  labs(title = "ROC Curve for Frequent Mental Distress Model",
       subtitle = paste0("AUC = ", round(auc_value1, 3)),
       x = "Specificity", y = "Sensitivity") +
  theme_minimal()

End of Lab Activity