Solución practica para Matrices

Solucion ejercicio 1

mi_matriz<-matrix(data = c(1,2,3,4,
                           5,6,7,8,
                           9,10,11,12),nrow = 3,byrow = TRUE)
print(mi_matriz)
##      [,1] [,2] [,3] [,4]
## [1,]    1    2    3    4
## [2,]    5    6    7    8
## [3,]    9   10   11   12
mi_matriz2<-matrix(data = c(1,2,3,4,
                           5,6,7,8,
                           9,10,11,12),nrow = 3,byrow = FALSE) |> print()
##      [,1] [,2] [,3] [,4]
## [1,]    1    4    7   10
## [2,]    2    5    8   11
## [3,]    3    6    9   12

Solucion ejercicio 2

ana <- c(10, 20, 30)  
beto <- c(15, 25, 35)
unir_filas<- rbind(ana, beto)  |> print() 
##      [,1] [,2] [,3]
## ana    10   20   30
## beto   15   25   35
unir_columnas<-cbind(ana, beto) |> print()
##      ana beto
## [1,]  10   15
## [2,]  20   25
## [3,]  30   35
row.names(unir_filas)<-c("Maria","Jose")
unir_filas
##       [,1] [,2] [,3]
## Maria   10   20   30
## Jose    15   25   35
colnames(unir_filas)<-c("examen 1","examen 2","examen 3")
unir_filas
##       examen 1 examen 2 examen 3
## Maria       10       20       30
## Jose        15       25       35

Solucion ejercicio 3

# Creacion de la matriz:
set.seed(50)
(mi_matriz_aleatoria <- matrix(data = sample(x = 1:100, size = 9),
                              nrow = 3, byrow = TRUE)) |> print()
##      [,1] [,2] [,3]
## [1,]   11   52   95
## [2,]   98   46   67
## [3,]    8   16   18
# Calcula la traspuesta:
# Sin guardar:
mi_matriz_aleatoria |> t()
##      [,1] [,2] [,3]
## [1,]   11   98    8
## [2,]   52   46   16
## [3,]   95   67   18
# Con guardar:
transpuesta_mi_matriz_aleatoria<- t(mi_matriz_aleatoria) |> print() 
##      [,1] [,2] [,3]
## [1,]   11   98    8
## [2,]   52   46   16
## [3,]   95   67   18
#se crea y se muestra el objeto.

# Extrayendo el elemento 2,3

transpuesta_mi_matriz_aleatoria[2,3] |> print()
## [1] 16
#multiplicando la matriz por escalar:

10*transpuesta_mi_matriz_aleatoria |> print()
##      [,1] [,2] [,3]
## [1,]   11   98    8
## [2,]   52   46   16
## [3,]   95   67   18
##      [,1] [,2] [,3]
## [1,]  110  980   80
## [2,]  520  460  160
## [3,]  950  670  180

Solucion ejercicio 4

# Creando una matriz identidad:

matriz_identidad<-diag(x= 1, nrow = 3, ncol = 3) |> print()
##      [,1] [,2] [,3]
## [1,]    1    0    0
## [2,]    0    1    0
## [3,]    0    0    1
# Creando una matriz diagonal con elementos c(5, 10, 15) en la diagonal principal.

matriz_identidad<- diag(x = c(5, 10, 15), nrow = 3) |> print()
##      [,1] [,2] [,3]
## [1,]    5    0    0
## [2,]    0   10    0
## [3,]    0    0   15

Solucion ejercicio 5

# Ingreso de la matriz

m <- matrix(data = c(1,2,
                     3,4),nrow = 2, byrow = TRUE) |> print()
##      [,1] [,2]
## [1,]    1    2
## [2,]    3    4
# Calculando la inversa 

m_inversa <- solve(m) |> print() 
##      [,1] [,2]
## [1,] -2.0  1.0
## [2,]  1.5 -0.5
# Verificación

m %*% m_inversa |> round(digits = 0) |>   print()
##      [,1] [,2]
## [1,]    1    0
## [2,]    0    1

Solucion ejercicio 6

library(matlib)
fila1<-c(2,3,5,6) 
fila2<-c(0,8,1,-7) 
fila3<-fila1+fila2
(matriz_para_rango<-matrix(data = c(fila1,
                                   fila2,
                                   fila3),nrow = 3,byrow = TRUE)) |> print()
##      [,1] [,2] [,3] [,4]
## [1,]    2    3    5    6
## [2,]    0    8    1   -7
## [3,]    2   11    6   -1
rango<-matlib::R(X = matriz_para_rango) |> print()
## [1] 2

Solucion ejercicio 7

Autovalores y autovectores (Eigenvalues)

#Creando la matriz simetríca
S<-matrix(data = c(2,1,
                   1,2), nrow = 2, byrow = TRUE) |> print()
##      [,1] [,2]
## [1,]    2    1
## [2,]    1    2
#Calcular autoValores (y tambien autoVectores)
Resultado<-eigen(S)
#autovalores
Resultado$values
## [1] 3 1
#verificar autovalores
## verificando el primer autovalor
det(S-Resultado$values[1]*diag(x = 1,2))
## [1] 0
## Verificando el segundo autovalor
det(S-Resultado$values[2]*diag(x = 1,2))
## [1] 0

Solucion ejercicio 8

library(matlib)
A<-matrix(data = c(2,3,1,
                   1,-2,4,
                   3,1,-1),nrow = 3,byrow = TRUE) |> print()
##      [,1] [,2] [,3]
## [1,]    2    3    1
## [2,]    1   -2    4
## [3,]    3    1   -1
B<-matrix(data = c(1,-3,4),ncol = 1,byrow = TRUE) |> print()
##      [,1]
## [1,]    1
## [2,]   -3
## [3,]    4
#matriz aumentada S
S<-cbind(A,B) |> print()
##      [,1] [,2] [,3] [,4]
## [1,]    2    3    1    1
## [2,]    1   -2    4   -3
## [3,]    3    1   -1    4
#Teorema de Rouche Frobenius.
matlib::R(S)==matlib::R(A) 
## [1] TRUE
#Resolver el sistema:
solucion<-solve(A,B) |> print()
##      [,1]
## [1,]    1
## [2,]    0
## [3,]   -1
#Verificación
A%*%solucion-B
##      [,1]
## [1,]    0
## [2,]    0
## [3,]    0

Solucion ejercicio 9

library(matlib)
matlib::gaussianElimination(A,B, verbose = TRUE, fractions = TRUE)
## 
## Initial matrix:
##      [,1] [,2] [,3] [,4]
## [1,]  2    3    1    1  
## [2,]  1   -2    4   -3  
## [3,]  3    1   -1    4  
## 
## row: 1 
## 
##  exchange rows 1 and 3
##      [,1] [,2] [,3] [,4]
## [1,]  3    1   -1    4  
## [2,]  1   -2    4   -3  
## [3,]  2    3    1    1  
## 
##  multiply row 1 by 1/3
##      [,1] [,2] [,3] [,4]
## [1,]    1  1/3 -1/3  4/3
## [2,]    1   -2    4   -3
## [3,]    2    3    1    1
## 
##  subtract row 1 from row 2
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1   1/3  -1/3   4/3
## [2,]     0  -7/3  13/3 -13/3
## [3,]     2     3     1     1
## 
##  multiply row 1 by 2 and subtract from row 3
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1   1/3  -1/3   4/3
## [2,]     0  -7/3  13/3 -13/3
## [3,]     0   7/3   5/3  -5/3
## 
## row: 2 
## 
##  multiply row 2 by -3/7
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1   1/3  -1/3   4/3
## [2,]     0     1 -13/7  13/7
## [3,]     0   7/3   5/3  -5/3
## 
##  multiply row 2 by 1/3 and subtract from row 1
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1     0   2/7   5/7
## [2,]     0     1 -13/7  13/7
## [3,]     0   7/3   5/3  -5/3
## 
##  multiply row 2 by 7/3 and subtract from row 3
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1     0   2/7   5/7
## [2,]     0     1 -13/7  13/7
## [3,]     0     0     6    -6
## 
## row: 3 
## 
##  multiply row 3 by 1/6
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1     0   2/7   5/7
## [2,]     0     1 -13/7  13/7
## [3,]     0     0     1    -1
## 
##  multiply row 3 by 2/7 and subtract from row 1
##      [,1]  [,2]  [,3]  [,4] 
## [1,]     1     0     0     1
## [2,]     0     1 -13/7  13/7
## [3,]     0     0     1    -1
## 
##  multiply row 3 by 13/7 and add to row 2
##      [,1] [,2] [,3] [,4]
## [1,]  1    0    0    1  
## [2,]  0    1    0    0  
## [3,]  0    0    1   -1