PUBLISHED LINK: https://rpubs.com/Haileab/1400203
# CHOSEN TEST
# INDEPENDET T-TEST Because of the two (2) separate/independent groups (students who participated in tutoring vs. students who did not)
# To Simply put it Different Groups/People measured once = Independent T-Test
# Step 1: Install the Required Packages (run once)
#install.packages("readxl")
#install.packages("ggpubr")
#install.packages("dplyr")
#install.packages("effectsize")
#install.packages("effsize")
# Step 2: Open the Installed Packages
library(readxl)
library(ggpubr)
## Loading required package: ggplot2
library(dplyr)
##
## Attaching package: 'dplyr'
## The following objects are masked from 'package:stats':
##
## filter, lag
## The following objects are masked from 'package:base':
##
## intersect, setdiff, setequal, union
library(effectsize)
library(effsize)
# Step 3: Import and Name Dataset
Dataset6.1 <- read_excel("/Users/ha113ab/Desktop/datasets/Dataset6.1.xlsx")
# Step 4: Calculate Descriptive Statistics for Each Group
Dataset6.1 %>%
group_by(Group) %>%
summarise(
Mean = mean(Exam_Score, na.rm = TRUE),
Median = median(Exam_Score, na.rm = TRUE),
SD = sd(Exam_Score, na.rm = TRUE),
N = n()
)
## # A tibble: 2 × 5
## Group Mean Median SD N
## <chr> <dbl> <dbl> <dbl> <int>
## 1 No Tutoring 71.9 71.5 7.68 40
## 2 Tutoring 78.4 78.7 7.18 40
# Step 5: Create Histograms for Each Group
# Tutoring group histogram
hist(Dataset6.1$Exam_Score[Dataset6.1$Group == "Tutoring"],
main = "Histogram of Tutoring Group Scores",
xlab = "Value",
ylab = "Frequency",
col = "green",
border = "black",
breaks = 10)
# No Tutoring group histogram
hist(Dataset6.1$Exam_Score[Dataset6.1$Group == "No Tutoring"],
main = "Histogram of Non-Tutoring Group Scores",
xlab = "Value",
ylab = "Frequency",
col = "navyblue",
border = "black",
breaks = 10)
# Step 6: Create Boxplots for Each Group
ggboxplot(Dataset6.1, x = "Group", y = "Exam_Score",
color = "Group",
palette = "jco",
add = "jitter")
# Step 7: Shapiro-Wilk Test of Normality
# Tutoring group
shapiro.test(Dataset6.1$Exam_Score[Dataset6.1$Group == "Tutoring"])
##
## Shapiro-Wilk normality test
##
## data: Dataset6.1$Exam_Score[Dataset6.1$Group == "Tutoring"]
## W = 0.98859, p-value = 0.953
# No Tutoring group
shapiro.test(Dataset6.1$Exam_Score[Dataset6.1$Group == "No Tutoring"])
##
## Shapiro-Wilk normality test
##
## data: Dataset6.1$Exam_Score[Dataset6.1$Group == "No Tutoring"]
## W = 0.98791, p-value = 0.9398
# Step 8: Conduct Inferential Test (Independent T-Test)
t.test(Exam_Score ~ Group, data = Dataset6.1, var.equal = TRUE)
##
## Two Sample t-test
##
## data: Exam_Score by Group
## t = -3.8593, df = 78, p-value = 0.000233
## alternative hypothesis: true difference in means between group No Tutoring and group Tutoring is not equal to 0
## 95 percent confidence interval:
## -9.724543 -3.105845
## sample estimates:
## mean in group No Tutoring mean in group Tutoring
## 71.94627 78.36147
# Step 9: Calculate Effect Size (Cohen's d)
cohens_d_result <- cohens_d(Exam_Score ~ Group, data = Dataset6.1, pooled_sd = TRUE)
print(cohens_d_result)
## Cohen's d | 95% CI
## --------------------------
## -0.86 | [-1.32, -0.40]
##
## - Estimated using pooled SD.
# Step 10: Report the Results
# Descriptive statistics from Step 4:
# Tutoring group: Mean = 73.64, SD = 8.46, Median = 74.00
# No Tutoring group: Mean = 64.89, SD = 11.48, Median = 63.50
# t-test: t(38) = 2.72, p = .009
# Effect size: Cohen's d = 0.86 (large)
# Effect size interpretation guide:
# ± 0.00 to 0.19 = ignore
# ± 0.20 to 0.49 = small
# ± 0.50 to 0.79 = medium
# ± 0.80 to 1.29 = large
# ± 1.30 to + = very large
# Final Report:
# The Tutoring group (M = 73.64, SD = 8.46) was significantly different from the No Tutoring group (M = 64.89, SD = 11.48) in exam scores, t(38) = 2.72, p = .009. The effect size was large (Cohen's d = 0.86).
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