Time: ~30 minutes
Goal: Practice one-way ANOVA analysis from start to finish using real public health data
Learning Objectives:
Structure:
Submission: Upload your completed .Rmd file and published to Brightspace by the end of class.
Why ANOVA? We have one continuous outcome (SBP) and one categorical predictor with THREE groups (BMI category). Using multiple t-tests would inflate our Type I error rate.
# Load necessary libraries
library(tidyverse) # For data manipulation and visualization
library(knitr) # For nice tables
library(car) # For Levene's test
library(NHANES) # NHANES dataset
# Load the NHANES data
data(NHANES)Create analysis dataset:
# Set seed for reproducibility
set.seed(553)
# Create BMI categories and prepare data
bp_bmi_data <- NHANES %>%
filter(Age >= 18 & Age <= 65) %>% # Adults 18-65
filter(!is.na(BPSysAve) & !is.na(BMI)) %>%
mutate(
bmi_category = case_when(
BMI < 25 ~ "Normal",
BMI >= 25 & BMI < 30 ~ "Overweight",
BMI >= 30 ~ "Obese",
TRUE ~ NA_character_
),
bmi_category = factor(bmi_category,
levels = c("Normal", "Overweight", "Obese"))
) %>%
filter(!is.na(bmi_category)) %>%
select(ID, Age, Gender, BPSysAve, BMI, bmi_category)
# Display first few rows
head(bp_bmi_data) %>%
kable(caption = "Blood Pressure and BMI Dataset (first 6 rows)")| ID | Age | Gender | BPSysAve | BMI | bmi_category |
|---|---|---|---|---|---|
| 51624 | 34 | male | 113 | 32.22 | Obese |
| 51624 | 34 | male | 113 | 32.22 | Obese |
| 51624 | 34 | male | 113 | 32.22 | Obese |
| 51630 | 49 | female | 112 | 30.57 | Obese |
| 51647 | 45 | female | 118 | 27.24 | Overweight |
| 51647 | 45 | female | 118 | 27.24 | Overweight |
##
## Normal Overweight Obese
## 1939 1937 2150
Interpretation: We have 6026 adults with complete BP and BMI data across three BMI categories.
# Calculate summary statistics by BMI category
summary_stats <- bp_bmi_data %>%
group_by(bmi_category) %>%
summarise(
n = n(),
Mean = mean(BPSysAve),
SD = sd(BPSysAve),
Median = median(BPSysAve),
Min = min(BPSysAve),
Max = max(BPSysAve)
)
summary_stats %>%
kable(digits = 2,
caption = "Descriptive Statistics: Systolic BP by BMI Category")| bmi_category | n | Mean | SD | Median | Min | Max |
|---|---|---|---|---|---|---|
| Normal | 1939 | 114.23 | 15.01 | 113 | 78 | 221 |
| Overweight | 1937 | 118.74 | 13.86 | 117 | 83 | 186 |
| Obese | 2150 | 121.62 | 15.27 | 120 | 82 | 226 |
Observation: The mean SBP appears to increase from Normal (114.2) to Overweight (118.7) to Obese (121.6).
# Create boxplots with individual points
ggplot(bp_bmi_data,
aes(x = bmi_category, y = BPSysAve, fill = bmi_category)) +
geom_boxplot(alpha = 0.7, outlier.shape = NA) +
geom_jitter(width = 0.2, alpha = 0.1, size = 0.5) +
scale_fill_brewer(palette = "Set2") +
labs(
title = "Systolic Blood Pressure by BMI Category",
subtitle = "NHANES Data, Adults aged 18-65",
x = "BMI Category",
y = "Systolic Blood Pressure (mmHg)",
fill = "BMI Category"
) +
theme_minimal(base_size = 12) +
theme(legend.position = "none")What the plot tells us:
Null Hypothesis (H₀): μ_Normal = μ_Overweight =
μ_Obese
(All three population means are equal)
Alternative Hypothesis (H₁): At least one population mean differs from the others
Significance level: α = 0.05
# Fit the one-way ANOVA model
anova_model <- aov(BPSysAve ~ bmi_category, data = bp_bmi_data)
# Display the ANOVA table
summary(anova_model)## Df Sum Sq Mean Sq F value Pr(>F)
## bmi_category 2 56212 28106 129.2 <2e-16 ***
## Residuals 6023 1309859 217
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Interpretation:
Why do we need this? The F-test tells us that groups differ, but not which groups differ. Tukey’s Honest Significant Difference controls the family-wise error rate for multiple pairwise comparisons.
## Tukey multiple comparisons of means
## 95% family-wise confidence level
##
## Fit: aov(formula = BPSysAve ~ bmi_category, data = bp_bmi_data)
##
## $bmi_category
## diff lwr upr p adj
## Overweight-Normal 4.507724 3.397134 5.618314 0
## Obese-Normal 7.391744 6.309024 8.474464 0
## Obese-Overweight 2.884019 1.801006 3.967033 0
Interpretation:
| Comparison | Mean Diff | 95% CI | p-value | Significant? |
|---|---|---|---|---|
| Overweight - Normal | 4.51 | [3.4, 5.62] | 1.98e-13 | Yes |
| Obese - Normal | 7.39 | [6.31, 8.47] | < 0.001 | Yes |
| Obese - Overweight | 2.88 | [1.8, 3.97] | 1.38e-09 | Yes |
Conclusion: All three pairwise comparisons are statistically significant. Obese adults have higher SBP than overweight adults, who in turn have higher SBP than normal-weight adults.
# Extract sum of squares from ANOVA table
anova_summary <- summary(anova_model)[[1]]
ss_treatment <- anova_summary$`Sum Sq`[1]
ss_total <- sum(anova_summary$`Sum Sq`)
# Calculate eta-squared
eta_squared <- ss_treatment / ss_total
cat("Eta-squared (η²):", round(eta_squared, 4), "\n")## Eta-squared (η²): 0.0411
## Percentage of variance explained: 4.11 %
Interpretation: BMI category explains 4.11% of the variance in systolic BP.
While statistically significant, the practical effect is modest—BMI category alone doesn’t explain most of the variation in blood pressure.
ANOVA Assumptions:
Diagnostic Plot Interpretation:
# Levene's test for homogeneity of variance
levene_test <- leveneTest(BPSysAve ~ bmi_category, data = bp_bmi_data)
print(levene_test)## Levene's Test for Homogeneity of Variance (center = median)
## Df F value Pr(>F)
## group 2 2.7615 0.06328 .
## 6023
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Levene’s Test Interpretation:
Overall Assessment: With n > 2000, ANOVA is robust to minor violations. Our assumptions are reasonably satisfied.
Example Results Section:
We conducted a one-way ANOVA to examine whether mean systolic blood pressure (SBP) differs across BMI categories (Normal, Overweight, Obese) among 6,026 adults aged 18-65 from NHANES. Descriptive statistics showed mean SBP of 114.2 mmHg (SD = 15) for normal weight, 118.7 mmHg (SD = 13.9) for overweight, and 121.6 mmHg (SD = 15.3) for obese individuals.
The ANOVA revealed a statistically significant difference in mean SBP across BMI categories, F(2, 6023) = 129.24, p < 0.001. Tukey’s HSD post-hoc tests indicated that all pairwise comparisons were significant (p < 0.05): obese adults had on average 7.4 mmHg higher SBP than normal-weight adults, and 2.9 mmHg higher than overweight adults.
The effect size (η² = 0.041) indicates that BMI category explains 4.1% of the variance in systolic blood pressure, representing a small practical effect. These findings support the well-established relationship between higher BMI and elevated blood pressure, though other factors account for most of the variation in SBP.
Your Task: Complete the same 9-step analysis workflow you just practiced, but now on a different outcome and predictor.
# Prepare the dataset
set.seed(553)
mental_health_data <- NHANES %>%
filter(Age >= 18) %>%
filter(!is.na(DaysMentHlthBad) & !is.na(PhysActive)) %>%
mutate(
activity_level = case_when(
PhysActive == "No" ~ "None",
PhysActive == "Yes" & !is.na(PhysActiveDays) & PhysActiveDays < 3 ~ "Moderate",
PhysActive == "Yes" & !is.na(PhysActiveDays) & PhysActiveDays >= 3 ~ "Vigorous",
TRUE ~ NA_character_
),
activity_level = factor(activity_level,
levels = c("None", "Moderate", "Vigorous"))
) %>%
filter(!is.na(activity_level)) %>%
select(ID, Age, Gender, DaysMentHlthBad, PhysActive, activity_level)
# YOUR TURN: Display the first 6 rows and check sample sizes
head(mental_health_data)## # A tibble: 6 × 6
## ID Age Gender DaysMentHlthBad PhysActive activity_level
## <int> <int> <fct> <int> <fct> <fct>
## 1 51624 34 male 15 No None
## 2 51624 34 male 15 No None
## 3 51624 34 male 15 No None
## 4 51630 49 female 10 No None
## 5 51647 45 female 3 Yes Vigorous
## 6 51647 45 female 3 Yes Vigorous
##
## None Moderate Vigorous
## 3139 768 1850
## # A tibble: 3 × 2
## activity_level n
## <fct> <int>
## 1 None 3139
## 2 Moderate 768
## 3 Vigorous 1850
YOUR TURN - Answer these questions:
# YOUR TURN: Calculate summary statistics by activity level
# Hint: Follow the same structure as the guided example
# Variables to summarize: n, Mean, SD, Median, Min, Max
#Calculate summary statistics by activity level
summary_stats <- mental_health_data %>%
group_by(activity_level) %>%
summarise(
n = n(),
Mean = mean(DaysMentHlthBad, na.rm = TRUE),
SD = sd(DaysMentHlthBad, na.rm = TRUE),
Median = median(DaysMentHlthBad, na.rm = TRUE),
Min = min(DaysMentHlthBad, na.rm = TRUE),
Max = max(DaysMentHlthBad, na.rm = TRUE)
)
summary_stats %>%
kable(
digits = 2,
caption = "Summary statistics by physical activity level"
)| activity_level | n | Mean | SD | Median | Min | Max |
|---|---|---|---|---|---|---|
| None | 3139 | 5.08 | 9.01 | 0 | 0 | 30 |
| Moderate | 768 | 3.81 | 6.87 | 0 | 0 | 30 |
| Vigorous | 1850 | 3.54 | 7.17 | 0 | 0 | 30 |
YOUR TURN - Interpret:
Which group has the highest mean number of bad mental health days? The None physical activity group (Mean = 5.08 days)
Which group has the lowest? The Vigorous physical activity group (Mean = 3.54 days) —
# YOUR TURN: Create boxplots comparing DaysMentHlthBad across activity levels
# Hint: Use the same ggplot code structure as the example
# Change variable names and labels appropriately
# Create boxplots with individual points
ggplot(mental_health_data,
aes(x = activity_level, y = DaysMentHlthBad, fill = activity_level)) +
geom_boxplot(alpha = 0.7, outlier.shape = NA) +
geom_jitter(width = 0.2, alpha = 0.1, size = 0.5) +
scale_fill_brewer(palette = "Set2") +
labs(
title = "Days of Poor Mental Health by Physical Activity Level",
subtitle = "NHANES Data, Adults aged 18+",
x = "Physical Activity Level",
y = "Days of Poor Mental Health (past 30 days)",
fill = "Activity Level"
) +
theme_minimal(base_size = 12) +
theme(legend.position = "none")YOUR TURN - Describe what you see:
Do the groups appear to differ? Yes. Adults with no physical activity tend to report more days of poor mental health on average, while those with vigorous activity report the fewest days. The moderate group falls in between.
Are the variances similar across groups? Not exactly. The no-activity group shows slightly higher variability, while the moderate and vigorous groups have somewhat smaller spreads. Variances are not perfectly equal across groups.
YOUR TURN - Write the hypotheses:
Null Hypothesis (H₀): Mean days of poor mental health are equal across all physical activity levels.
Alternative Hypothesis (H₁):At least one physical activity group has a different mean number of poor mental health days.
Significance level: α = 0.05
# YOUR TURN: Fit the ANOVA model
# Outcome: DaysMentHlthBad
# Predictor: activity_level
# One-way ANOVA: Days of poor mental health by activity level
anova_model <- aov(DaysMentHlthBad ~ activity_level, data = mental_health_data)
# Display the ANOVA table
summary(anova_model)## Df Sum Sq Mean Sq F value Pr(>F)
## activity_level 2 3109 1554.6 23.17 9.52e-11 ***
## Residuals 5754 386089 67.1
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
YOUR TURN - Extract and interpret the results:
# YOUR TURN: Conduct Tukey HSD test
# Only if your ANOVA p-value < 0.05
# Conduct Tukey HSD test for pairwise comparisons
tukey_results <- TukeyHSD(anova_model)
# Print the results
print(tukey_results)## Tukey multiple comparisons of means
## 95% family-wise confidence level
##
## Fit: aov(formula = DaysMentHlthBad ~ activity_level, data = mental_health_data)
##
## $activity_level
## diff lwr upr p adj
## Moderate-None -1.2725867 -2.045657 -0.4995169 0.0003386
## Vigorous-None -1.5464873 -2.109345 -0.9836298 0.0000000
## Vigorous-Moderate -0.2739006 -1.098213 0.5504114 0.7159887
YOUR TURN - Complete the table:
| Comparison | Mean Difference | 95% CI Lower | 95% CI Upper | p-value | Significant? |
|---|---|---|---|---|---|
| Moderate - None | -1.2725867 | -2.045657 | -0.4995169 | 0.0003386 | yes |
| Vigorous - None | -1.5464873 | -2.109345 | -0.9836298 | 0.0000000 | yes |
| Vigorous - Moderate | -0.2739006 | -1.098213 | 0.5504114 | 0.7159887 | no |
Interpretation:
Which specific groups differ significantly? The Moderate vs Vigorous comparison is not significant, so these two groups do not differ from each other.
# YOUR TURN: Calculate eta-squared
# Hint: Extract Sum Sq from the ANOVA summary
# Extract sum of squares from ANOVA table
anova_summary <- summary(anova_model)[[1]]
ss_treatment <- anova_summary$`Sum Sq`[1]
ss_total <- sum(anova_summary$`Sum Sq`)
# Calculate eta-squared
eta_squared <- ss_treatment / ss_total
cat("Eta-squared (η²):", round(eta_squared, 4), "\n")## Eta-squared (η²): 0.008
## Percentage of variance explained: 0.8 %
YOUR TURN - Interpret:
# YOUR TURN: Create diagnostic plots
# Create diagnostic plots
par(mfrow = c(2, 2))
plot(anova_model)YOUR TURN - Evaluate each plot:
Residuals vs Fitted: random scatter around 0, no clear pattern - the linearity assumption is reasonably met
Q-Q Plot: points falling roughly along the diagonal line, indicating some deviation from normality
Scale-Location: horizontal band, similar spread across fitted values - the pattern is not severe
Residuals vs Leverage: influential points far right with large residuals, no single observation overly influences the model.
# YOUR TURN: Conduct Levene's test
# Levene's test for homogeneity of variance
levene_test <- leveneTest(DaysMentHlthBad ~ activity_level, data = mental_health_data)
print(levene_test)## Levene's Test for Homogeneity of Variance (center = median)
## Df F value Pr(>F)
## group 2 23.168 9.517e-11 ***
## 5754
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
YOUR TURN - Overall assessment:
Are assumptions reasonably met? Yes, the assumptions are generally met, with only minor deviations.
Do any violations threaten your conclusions? No, the minor violations are unlikely to affect the results given the large sample size.
YOUR TURN - Write a complete 2-3 paragraph results section:
Include: 1. Sample description and descriptive statistics 2. F-test results 3. Post-hoc comparisons (if applicable) 4. Effect size interpretation 5. Public health significance
Your Results Section:
<The sample included 5,757 adults aged 18+, with 3,139 reporting no physical activity, 768 moderate, and 1,850 vigorous activity. Mean days of poor mental health were highest in the no-activity group (5.08 ± 9.01), lower in moderate (3.81 ± 6.87), and lowest in vigorous (3.54 ± 7.17). Medians were zero in all groups, reflecting a right-skewed distribution.
ANOVA showed significant differences across activity levels (F(2, 5754) = 23.17, p < 0.001). Tukey HSD tests indicated that the no-activity group had significantly more poor mental health days than both moderate (diff = 1.27, p < 0.001) and vigorous (diff = 1.55, p < 0.001) groups; moderate and vigorous groups did not differ.
Effect size was small (η² = 0.008), meaning physical activity explained only 0.8% of the variance. Despite the small effect, promoting physical activity may yield meaningful population-level benefits for mental health.>
1. How does the effect size help you understand the practical vs. statistical significance?
<The small effect size suggests that, on an individual level, physical activity makes a modest difference in mental health days. However, because physical inactivity is common, even small reductions can have meaningful benefits at the population level, which is important for public health planning.>
2. Why is it important to check ANOVA assumptions? What might happen if they’re violated?
<To ensure results are valid; violations can lead to incorrect p-values and misleading conclusions. Type I or II errors may increase, and effect estimates may be biased.>
3. In public health practice, when might you choose to use ANOVA?
<To compare means of a continuous outcome across three or more groups (example: mental health days by activity level).>
4. What was the most challenging part of this lab activity?
<Interpreting skewed data and understanding effect size versus statistical significance.>
Before submitting, verify you have:
To submit: Upload both your .Rmd file and the HTML output to Brightspace.
Lab completed on: February 05, 2026
Total Points: 15
| Category | Criteria | Points | Notes |
|---|---|---|---|
| Code Execution | All code chunks run without errors | 4 | - Deduct 1 pt per major error - Deduct 0.5 pt per minor warning |
| Completion | All “YOUR TURN” sections attempted | 4 | - Part B Steps 1-9 completed - All fill-in-the-blank answered - Tukey table filled in |
| Interpretation | Correct statistical interpretation | 4 | - Hypotheses correctly stated (1 pt) - ANOVA results interpreted (1 pt) - Post-hoc results interpreted (1 pt) - Assumptions evaluated (1 pt) |
| Results Section | Professional, complete write-up | 3 | - Includes descriptive stats (1 pt) - Reports F-test & post-hoc (1 pt) - Effect size & significance (1 pt) |
Code Execution (4 points):
Completion (4 points):
Interpretation (4 points):
Results Section (3 points):