In previous grades, we focused on ungrouped data. In Form Three, we analyze data organized into frequency distributions (grouped data).
The mean for grouped data is calculated by finding the midpoint (\(x\)) of each class, multiplying it by the frequency (\(f\)), and dividing the sum by the total frequency.
Formula: \[\bar{x} = \frac{\sum fx}{\sum f}\]
The median is the value that separates the higher half from the lower half of the data.
Formula: \[\text{Median} = L_m + \left( \frac{\frac{n}{2} - c}{f} \right) \cdot h\] Where: * \(L_m\): Lower boundary of the median class. * \(n\): Total frequency. * \(c\): Cumulative frequency of the class preceding the median class. * \(f\): Frequency of the median class. * \(h\): Class width.
The mode is the value with the highest frequency.
Formula: \[\text{Mode} = L_m + \left( \frac{f_m - f_1}{(f_m - f_1) + (f_m - f_2)} \right) \cdot h\] Where \(f_m\) is the modal frequency, \(f_1\) is the frequency before it, and \(f_2\) is the frequency after it.
Correlation measures the strength and direction of the relationship between two variables.
Figure 1: Positive Correlation between Study Hours and Scores
Types of Correlation: 1. Strong Positive: Points lie close to a line rising from left to right. 2. Strong Negative: Points lie close to a line falling from left to right. 3. No Correlation: Points are scattered randomly.
Exercise 8A: Grouped Mean The table below shows the marks of 50 students in a math test. Calculate the mean mark.
| Marks | Frequency (\(f\)) | Midpoint (\(x\)) | \(fx\) |
|---|---|---|---|
| 21-30 | 2 | 25.5 | 51 |
| 31-40 | 5 | 35.5 | 177.5 |
| 41-50 | 7 | 45.5 | 318.5 |
| 51-60 | 9 | 55.5 | 499.5 |
| 61-70 | 11 | 65.5 | 720.5 |
Exercise 8B: Correlation A farmer records the amount of fertilizer used (kg) and the crop yield (tonnes). 1. Plot a scatter diagram for the data: (10, 2), (20, 4), (30, 5), (40, 7), (50, 8). 2. Describe the relationship between fertilizer and yield.
The probability of an event \(E\) is: \[P(E) = \frac{n(E)}{n(S)} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}}\]
Properties: * \(0 \le P(E) \le 1\) * \(P(E) = 0\) (Impossible event) * \(P(E) = 1\) (Certain event)
For two events \(A\) and \(B\): \[P(A \cup B) = P(A) + P(B) - P(A \cap B)\] If \(A\) and \(B\) are mutually exclusive (cannot happen together), then \(P(A \cap B) = 0\).
For independent events: \[P(A \cap B) = P(A) \cdot P(B)\]
The probability of \(B\) occurring given that \(A\) has already occurred: \[P(B|A) = \frac{P(A \cap B)}{P(A)}\]
When rolling two dice, the sample space consists of \(6 \times 6 = 36\) outcomes.
## Die1 Die2 Sum
## 1 1 1 2
## 2 2 1 3
## 3 3 1 4
## 4 4 1 5
## 5 5 1 6
## 6 6 1 7
## 7 1 2 3
## 8 2 2 4
## 9 3 2 5
## 10 4 2 6
Exercise 9A: Basic Probability A bag contains 5 blue, 5 green, 6 white, and 4 red discs. If one disc is picked at random, find the probability that it is: 1. Green 2. Blue or Red 3. Not White
Exercise 9B: Independent Events A coin is tossed and a six-sided die is rolled. What is the probability of getting a “Head” and a “6”?
Exercise 9C: Dependent Events A bag contains 3 red and 5 white balls. Two balls are picked one after the other without replacement. 1. What is the probability that both are red? 2. What is the probability of picking a red ball then a white ball?
Exercise 9D: Real-Life Application In a survey of 200 men, 142 like camel milk, while 58 dislike it. 1. What is the probability that a man chosen at random likes camel milk? 2. If two men are chosen, what is the probability they both dislike camel milk?
| Concept | Statistics (Ch 8) | Probability (Ch 9) |
|---|---|---|
| Focus | Analyzing past/collected data | Predicting future outcomes |
| Key Tool | Mean, Median, Mode | Sample Space, Rules of Addition |
| Visual | Scatter Plots, Histograms | Tree Diagrams, Venn Diagrams |
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