Unit 2: Some Math Basics
2025-07-31
{width=80%}
123,456,789.001
3.14159
1,001
2,210.55
1,000,001.01
Please excuse my dear Aunt Sally!
\[3^2 - 8/2 + 4^2\] \[\sqrt{5^2 - 4^2} + 7(5-4)^2\]
\[a+b = b+a;\quad a\cdot b= b\cdot a\] - associative: regrouping of adding and multiplication is possible
\[a+(b+c) = (a+b)+c\ ; \quad a\cdot(b\cdot c) = (a\cdot b) \cdot c\]
\[a(b+ c) = ab + ac\]
\[a - a = 0\ ;\quad a\frac{1}{a} = 1\]
\[ a + 0 = a\ ;\quad a\cdot 1 = a\]
\[\frac{n^5}{n^3} = \left\{n^5\cdot n^{-3}\strut=n^2 \atop\strut \frac{n\cdot n\cdot n\cdot n\cdot n}{n\cdot n\cdot n }=n\cdot n\right\}= n^2\]
Given a mathematical expression, simplify it using the order of operations.
\[\eqalign{ 3x -2y + x -3y -7\\ 2r -5(3-r)+4\\ 12 / (36/9) + 6\\ 2 + 8 \times 7 / 4\\ -25/5^2 - 7\\ }\]
Fred earns $40 at the community garden. He spends $10 on a streaming subscription, puts half of what is left in a savings account, and gets another $5 for walking his neighbor’s dog.
Write the expression that represents the number of dollars Fred keeps (and does not put in his savings account). Remember the order of operations.
How much money does Fred keep?
equation is a mathematical statement indicating that two expressions are equal.
formula is an equation expressing a relationship between constant and variable quantities.
\[x^3\cdot x^2= x^{3+2} = x^5\]
\[x^4\cdot x^3\cdot x^2= x^{4+3+2} = x^9\]
\[\frac{x^7}{x^{3}} = x^7\cdot x^{-3} = x^{7-3} = x^4\]
\[(x^2)^3=x^{2\cdot 3} = x^6\]
\[\frac{x^3}{x^3} = x^{(3-3)} = x^0 = 1\]
\[x^{-3} = \frac{1}{x^3}\]
\[\frac{x^2 x^{1/2}}{x^3}= x^{2.5} x^{-3} = x^{(2.5 -3)}=x^{-\frac{1}{2}} =\frac{1}{\sqrt{x}}\]
\[\frac{(j^2k)^4}{(j^2k)(j^2k)^3}\]
\[0.0000065 = 6.5 \times 10^{-6}\] \[128,333,222 = 1.28333222\times 10^8\]
\[\eqalign{12,345 \times 1214 &=& 14986830\\ &=& 1.2345 \times 10^4 \times 1.214\times 10^3\\ &=&1.4986830 \times 10^7\\ }\]
\[\eqalign{\sqrt{2}\cdot \sqrt{2} &=& 2^{\frac{1}{2}}\cdot 2^{\frac{1}{2}}=2^\frac{2}{2}=2^1= 2\\ \sqrt[3]{2}\cdot \sqrt[3]{2} \cdot \sqrt[3]{2}&=&2^{\frac{1}{3}}\cdot 2^{\frac{1}{3}}\cdot 2^{\frac{1}{3}} = 2^\frac{3}{3} = 2^1 = 2\\ \sqrt[4]{2}\cdot \sqrt[4]{2}\cdot \sqrt[4]{2} \cdot \sqrt[4]{2}&=&\left\{\eqalign{ 2^{\frac{1}{4}}\cdot 2^{\frac{1}{4}}\cdot 2^{\frac{1}{4}}\cdot 2^{\frac{1}{4}}\ =\ 2^\frac{4}{4}\\ 2^{\frac{2}{4}}\cdot 2^{\frac{2}{4}}= 2^{\frac{1}{2}}\cdot 2^{\frac{1}{2}}=2^\frac{2}{2}\\ }\right.\\&=& 2^1 = 2\\}\]
\[\eqalign{\frac{3}{1-\sqrt{2}}&=&\frac{3}{\left(1-\sqrt{2}\right)}\frac{\left(1+\sqrt{2}\right)}{\left(1+\sqrt{2}\right)}\\&=&\frac{3+3\sqrt{2}}{1-2}=\frac{3\left(1+\sqrt{2}\right)}{-1}\\&=&-3 + 3\sqrt{2}\\&=&3\sqrt{2} -3\\}\]
\[\sqrt{\frac{4}{9}}=\left\{\eqalign{\frac{\sqrt{4}}{\sqrt{9}}\quad \\ \\ \sqrt{\frac{2\cdot 2}{3\cdot 3}}}\right\}=\frac{2}{3}\]
\[(a+b)(a+b) = a^2 + ab + ab + b^2 = a^2 + 2ab + b^2\]
\[(a-b)(a+b)=a^2+ab-ab- b^2= a^2 - b^2\]
IT103