| Category | Proportion (%) | Type |
|---|---|---|
| SummerGroup | 53.1 | Birth Group |
| WinterGroup | 46.9 | Birth Group |
| Summer | 28.7 | Birth Season |
| Autumn | 24.4 | Birth Season |
| Winter | 23.8 | Birth Season |
| Spring | 23.1 | Birth Season |
| WinterGroup | 75.0 | Preferred Group |
| SummerGroup | 25.0 | Preferred Group |
| Winter | 54.4 | Preferred Season |
| Spring | 20.6 | Preferred Season |
| Autumn | 13.8 | Preferred Season |
| Summer | 11.2 | Preferred Season |
Opposite Season Preference Analysis
Process the data
Binomial test for preference of opposite group
Exact binomial test
data: successes_2 and n_2
number of successes = 83, number of trials = 160, p-value = 0.3464
alternative hypothesis: true probability of success is greater than 0.5
95 percent confidence interval:
0.450805 1.000000
sample estimates:
probability of success
0.51875
Out of 160 people, 83 (about 51.9%) preferred a season opposite to the one they were born in. Although this is slightly more than half, the result is not statistically significant (p = 0.346), meaning it could easily be due to random chance. The 95% confidence interval ranges from about 45.1% to 100%, so we cannot confidently say that people generally prefer opposite seasons.
Association Tests
Pearson's Chi-squared test
data: chi_table_4
X-squared = 5.6844, df = 9, p-value = 0.771
[1] "Cramer's V: 0.11"
The chi-square test showed no significant association between birth season and preferred season (p = 0.771), meaning the pattern of preferences could be due to chance. The Cramer’s V value of 0.11 indicates a very weak relationship, suggesting that birth season has little to no meaningful influence on preferred season in this dataset.
Correlation / Rank Agreement
Spearman's rank correlation rho
data: processed_data$birth_season_num and processed_data$preferred_season_num
S = 657770, p-value = 0.6474
alternative hypothesis: true rho is not equal to 0
sample estimates:
rho
0.03643167
Kendall's rank correlation tau
data: processed_data$birth_season_num and processed_data$preferred_season_num
z = 0.45019, p-value = 0.6526
alternative hypothesis: true tau is not equal to 0
sample estimates:
tau
0.03049365
Cohen's Kappa for 2 Raters (Weights: unweighted)
Subjects = 160
Raters = 2
Kappa = 0.0344
z = 0.839
p-value = 0.401