speed dist
Min. : 4.0 Min. : 2.00
1st Qu.:12.0 1st Qu.: 26.00
Median :15.0 Median : 36.00
Mean :15.4 Mean : 42.98
3rd Qu.:19.0 3rd Qu.: 56.00
Max. :25.0 Max. :120.00
covariance_speed_dist <-cov(cars$speed, cars$dist)# Calculate the variance of speedvariance_speed <-var(cars$speed)# Calculate the slope parameter using the formulabeta1_calculated <- covariance_speed_dist / variance_speed# Print the calculated slopeprint(beta1_calculated)
[1] 3.932409
# Run the linear regression model# The formula is dist ~ speedmodel <-lm(dist ~ speed, data = cars)# Print the summary of the model to see the regression coefficientssummary(model)
Call:
lm(formula = dist ~ speed, data = cars)
Residuals:
Min 1Q Median 3Q Max
-29.069 -9.525 -2.272 9.215 43.201
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) -17.5791 6.7584 -2.601 0.0123 *
speed 3.9324 0.4155 9.464 1.49e-12 ***
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Residual standard error: 15.38 on 48 degrees of freedom
Multiple R-squared: 0.6511, Adjusted R-squared: 0.6438
F-statistic: 89.57 on 1 and 48 DF, p-value: 1.49e-12
# Extract the slope coefficient from the model summary# The slope for speed is labeled as "speed" in the coefficients tablebeta1_regression <-coef(model)["speed"]# Print the slope from the regression modelprint(beta1_regression)
speed
3.932409
# Check if the two calculated values are equalare_equal <-all.equal(beta1_calculated, as.numeric(beta1_regression))print(paste("The slope calculated by cov(speed,dist)/var(speed) is:", beta1_calculated))
[1] "The slope calculated by cov(speed,dist)/var(speed) is: 3.93240875912409"
print(paste("The slope from the lm() function is:", as.numeric(beta1_regression)))
[1] "The slope from the lm() function is: 3.93240875912409"
print(paste("Are the two values equal?", are_equal))