A computer system is shared by 2 users who work independently. At any given moment, either user can:
The number of users can be 0, 1, or 2, forming a Markov chain with 3 states. The task is to simulate 10,000 transitions of this Markov chain and determine what percentage of the time the system is in each of the 3 states.
## [1] 0 0 1 0 0 0 0 1 0 2 0 0 0 1 1 1 1 1 1 0 1 1 1 0 0 0 1 0 1 0 1 1 1 0 0 0 0 0
## [39] 0 2 1 1 0 1 1 1 0 0 1 0
## State Frequency
## 1 0 5071
## 2 1 4112
## 3 2 817
## State Percentage
## 1 0 50.71
## 2 1 41.12
## 3 2 8.17
Based on the frequency table and bar graph of the simulated data, it appears that from the 10,000 generated transitions:
From this data, we can conclude that at any given time, the probability of having 0 users connected (state 0) is the highest at 51.85%, and the probability of having 2 users connected (state 2) is the lowest at 7.88%.