\(\lambda\)=4.5
\(P(x\leq 3)\)
#4.5 breakdowns per day
#P(x=3)
ppois(3, lambda = 4.5)
## [1] 0.342296
I used this formula since I am working with cumulative values.
\(P(T<2)=1-e^{-0.5625*2}\)
#time between less than 2 hours
pexp(2, rate=.5625)
## [1] 0.6753475
In general to find this I would use exponential distribution
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