Replace “Your Name” with your actual name.
This lab will focus on conducting multiple regression analyses and interpreting the coefficients (main effects) with a special emphasis on handling categorical variables using effect coding. You will work with various datasets to predict different outcomes, interpret the results, and understand how effect coding influences the interpretation of categorical variables.
Dataset: You are given a dataset with variables
Work_Hours
, Job_Complexity
,
Salary
, and Job_Satisfaction
. Your task is to
predict Job_Satisfaction
based on the other three
predictors.
Dataset Creation:
# Create the dataset
set.seed(100)
data_ex1 <- data.frame(
Work_Hours = c(40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41, 40, 35, 45, 50, 38, 42, 48, 37, 44, 41),
Job_Complexity = c(7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8, 7, 6, 8, 9, 5, 7, 8, 6, 7, 8),
Salary = c(50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500, 50000, 48000, 52000, 55000, 47000, 51000, 53000, 46000, 54000, 49500),
Job_Satisfaction = c(78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76, 78, 72, 85, 80, 70, 82, 79, 75, 81, 76)
)
# View the first few rows of the dataset
head(data_ex1)
## Work_Hours Job_Complexity Salary Job_Satisfaction
## 1 40 7 50000 78
## 2 35 6 48000 72
## 3 45 8 52000 85
## 4 50 9 55000 80
## 5 38 5 47000 70
## 6 42 7 51000 82
Task:
1. Conduct a multiple regression analysis to predict
Job_Satisfaction
using Work_Hours
,
Job_Complexity
, and Salary
as predictors. Be
sure to use the data
argument in the lm()
function.
2. Interpret the main effects of each predictor. What does each
coefficient tell you about its relationship with
Job_Satisfaction
?
# Fit the multiple regression model
model <- lm(Job_Satisfaction ~ Work_Hours + Job_Complexity + Salary, data = data_ex1)
# Summary of the model
summary(model)
##
## Call:
## lm(formula = Job_Satisfaction ~ Work_Hours + Job_Complexity +
## Salary, data = data_ex1)
##
## Residuals:
## Min 1Q Median 3Q Max
## -3.367 -2.304 -0.491 2.131 5.056
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 28.3102797 7.1988322 3.933 0.000159 ***
## Work_Hours -0.1148592 0.1737588 -0.661 0.510179
## Job_Complexity 1.3367244 0.4796182 2.787 0.006411 **
## Salary 0.0008867 0.0002455 3.612 0.000485 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 2.852 on 96 degrees of freedom
## Multiple R-squared: 0.5925, Adjusted R-squared: 0.5798
## F-statistic: 46.53 on 3 and 96 DF, p-value: < 2.2e-16
Work_Hours
: Coefficient: 0.30Interpretation: For each additional hour worked per week, Job
Satisfaction increases by 0.30 units, assuming other variables are held
constant. - Job_Complexity
: Coefficient: 2.00
Interpretation: For each one-unit increase in job complexity, Job
Satisfaction increases by 2.00 units, holding other variables constant.
- Salary
: Coefficient: 0.0005
Interpretation: For every $1 increase in salary, Job Satisfaction increases by 0.0005 units. For every $1,000 increase, satisfaction goes up by 0.5 units.
Dataset: You are provided with a dataset containing
Study_Hours
, Attendance
,
Parent_Education_Level
, and GPA
. Your task is
to predict GPA
based on the other predictors.
Dataset Creation:
# Create the dataset with a larger sample size
set.seed(200)
data_ex2 <- data.frame(
Study_Hours = c(15, 12, 20, 18, 14, 17, 16, 13, 19, 14, 18, 16, 21, 13, 15, 20, 19, 18, 17, 16, 12, 14, 13, 20, 21, 22, 17, 19, 15, 16),
Attendance = c(90, 85, 95, 92, 88, 91, 89, 87, 93, 86, 91, 89, 95, 87, 90, 96, 94, 93, 89, 90, 85, 88, 87, 95, 96, 97, 92, 94, 88, 89),
Parent_Education_Level = factor(rep(c("High School", "College"), 15))
)
# Effect coding for Parent_Education_Level: -1 for High School, 1 for College
data_ex2$Parent_Education_Level <- ifelse(data_ex2$Parent_Education_Level == "High School", -1, 1)
# Create GPA with stronger relationships to predictors for significance
data_ex2$GPA <- 2.5 + 0.07 * data_ex2$Study_Hours + 0.03 * data_ex2$Attendance + 0.4 * data_ex2$Parent_Education_Level + rnorm(30, 0, 0.1)
# View the first few rows of the dataset
head(data_ex2)
## Study_Hours Attendance Parent_Education_Level GPA
## 1 15 90 -1 5.858476
## 2 12 85 1 6.312646
## 3 20 95 -1 6.393256
## 4 18 92 1 6.975807
## 5 14 88 -1 5.725976
## 6 17 91 1 6.808536
Task:
1. Conduct a multiple regression analysis to predict GPA
using Study_Hours
, Attendance
, and
Parent_Education_Level
(coded as -1 for “High School” and 1
for “College”) as predictors.
2. Interpret the main effects. How does each predictor contribute to predicting GPA?
# Fit the regression model
model2 <- lm(GPA ~ Study_Hours + Attendance + Parent_Education_Level, data = data_ex2)
# Show summary
summary(model2)
##
## Call:
## lm(formula = GPA ~ Study_Hours + Attendance + Parent_Education_Level,
## data = data_ex2)
##
## Residuals:
## Min 1Q Median 3Q Max
## -0.208221 -0.058093 -0.001553 0.040198 0.143841
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 1.79220 1.32615 1.351 0.1882
## Study_Hours 0.04868 0.02267 2.147 0.0413 *
## Attendance 0.04170 0.01862 2.239 0.0339 *
## Parent_Education_Level 0.40410 0.01574 25.669 <2e-16 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.08593 on 26 degrees of freedom
## Multiple R-squared: 0.9731, Adjusted R-squared: 0.97
## F-statistic: 313.4 on 3 and 26 DF, p-value: < 2.2e-16
Study_Hours
: Coefficient: 0.07 Interpretation: Each
additional hour of study per week is associated with a 0.07 increase in
GPA, controlling for other variables.Attendance
: Coefficient: 0.03 Interpretation: For each
1% increase in attendance, GPA increases by 0.03, holding other
variables constant.Parent_Education_Level
: Coefficient: 0.40 (effect
coded: -1 = High School, 1 = College) Interpretation: Students with
college-educated parents score, on average, 0.40 GPA points higher than
those whose parents only finished high school.Dataset: You are provided with a dataset containing
Exercise_Frequency
, Diet_Quality
,
Sleep_Duration
, and Health_Index
. Your task is
to predict Health_Index
based on the other predictors.
Dataset Creation:
# Create the dataset with a larger sample size
set.seed(300)
data_ex3 <- data.frame(
Exercise_Frequency = c(4, 5, 3, 6, 2, 5, 4, 3, 5, 4, 6, 7, 3, 6, 2, 5, 7, 8, 4, 5, 3, 6, 7, 2, 4, 5, 6, 3, 7, 8),
Diet_Quality = c(8, 7, 9, 6, 5, 8, 7, 6, 8, 7, 9, 8, 6, 7, 5, 8, 9, 7, 8, 7, 9, 6, 8, 5, 7, 6, 9, 8, 7, 6),
Sleep_Duration = c(7, 8, 6, 7, 5, 8, 7, 6, 7, 7, 8, 7, 6, 7, 5, 8, 7, 8, 6, 7, 6, 7, 8, 5, 7, 8, 7, 6, 7, 8)
)
# Create Health_Index with stronger relationships to predictors for significance
data_ex3$Health_Index <- 50 + 2 * data_ex3$Exercise_Frequency + 1.5 * data_ex3$Diet_Quality + 1 * data_ex3$Sleep_Duration + rnorm(30, 0, 2)
# View the first few rows of the dataset
head(data_ex3)
## Exercise_Frequency Diet_Quality Sleep_Duration Health_Index
## 1 4 8 7 79.74758
## 2 5 7 8 80.22421
## 3 3 9 6 76.44698
## 4 6 6 7 79.40253
## 5 2 5 5 66.32989
## 6 5 8 8 83.13740
Task:
1. Conduct a multiple regression analysis to predict
Health_Index
using Exercise_Frequency
,
Diet_Quality
, and Sleep_Duration
as
predictors.
2. How do the coefficients inform you about the relative importance of each predictor in determining health outcomes?
# Fit the model
model3 <- lm(Health_Index ~ Exercise_Frequency + Diet_Quality + Sleep_Duration, data = data_ex3)
# Show the summary
summary(model3)
##
## Call:
## lm(formula = Health_Index ~ Exercise_Frequency + Diet_Quality +
## Sleep_Duration, data = data_ex3)
##
## Residuals:
## Min 1Q Median 3Q Max
## -3.11901 -1.17265 0.03783 1.31807 2.86568
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 46.3914 2.9595 15.675 9.15e-15 ***
## Exercise_Frequency 1.8387 0.2829 6.500 6.87e-07 ***
## Diet_Quality 1.8522 0.2685 6.898 2.53e-07 ***
## Sleep_Duration 1.3717 0.5448 2.518 0.0183 *
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 1.684 on 26 degrees of freedom
## Multiple R-squared: 0.9225, Adjusted R-squared: 0.9136
## F-statistic: 103.2 on 3 and 26 DF, p-value: 1.467e-14
Diet_Quality: For each one-point improvement in diet quality, Health_Index increases by 1.5 points.
Sleep_Duration: Each additional hour of sleep adds 1 point to the Health_Index.
Dataset: You have a dataset with variables
Work_Experience
, Education_Level
,
Gender
, and Salary
. The Gender
variable is categorical with levels “Male” and “Female”.
Dataset Creation:
# Create the dataset with a larger sample size
set.seed(400)
data_ex4 <- data.frame(
Work_Experience = c(5, 7, 3, 6, 8, 4, 9, 6, 7, 5, 8, 9, 4, 6, 7, 5, 9, 10, 6, 7, 4, 5, 7, 6, 8, 9, 10, 5, 6, 8),
Education_Level = c(12, 14, 10, 16, 13, 15, 17, 12, 16, 14, 18, 19, 11, 14, 15, 13, 18, 20, 14, 15, 11, 13, 15, 14, 17, 18, 19, 13, 15, 17),
Gender = factor(rep(c("Male", "Female"), 15))
)
# Effect coding for Gender: 1 for Male, 1 for Female
data_ex4$Gender_Effect <- ifelse(data_ex4$Gender == "Male", -1, 1)
# Create Salary with stronger relationships to predictors for significance
data_ex4$Salary <- 30000 + 3000 * data_ex4$Work_Experience + 1500 * data_ex4$Education_Level + 5000 * data_ex4$Gender_Effect + rnorm(30, 0, 2000)
# View the first few rows of the dataset
head(data_ex4)
## Work_Experience Education_Level Gender Gender_Effect Salary
## 1 5 12 Male -1 55926.90
## 2 7 14 Female 1 78230.57
## 3 3 10 Male -1 51945.87
## 4 6 16 Female 1 75634.63
## 5 8 13 Male -1 67296.32
## 6 4 15 Female 1 66794.78
Task:
1. Conduct a multiple regression analysis to predict
Salary
using Work_Experience
,
Education_Level
, and Gender_Effect
as
predictors.
2. Interpret the coefficients, especially focusing on the effect of
Gender_Effect
.
3. Discuss how effect coding impacts the interpretation of the
Gender_Effect
variable.
# Fit the model using effect coding for Gender
model4 <- lm(Salary ~ Work_Experience + Education_Level + Gender_Effect, data = data_ex4)
# Show the summary
summary(model4)
##
## Call:
## lm(formula = Salary ~ Work_Experience + Education_Level + Gender_Effect,
## data = data_ex4)
##
## Residuals:
## Min 1Q Median 3Q Max
## -4401.7 -1568.7 165.7 1265.8 3439.3
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 30426.2 2574.8 11.817 5.89e-12 ***
## Work_Experience 3501.8 434.2 8.064 1.52e-08 ***
## Education_Level 1239.9 317.0 3.912 0.000588 ***
## Gender_Effect 4823.7 384.0 12.563 1.51e-12 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 2025 on 26 degrees of freedom
## Multiple R-squared: 0.9688, Adjusted R-squared: 0.9652
## F-statistic: 269 on 3 and 26 DF, p-value: < 2.2e-16
Work_Experience: Each additional year of experience adds $3,000 to salary.
Education_Level: Each additional year of education adds $1,500.
Gender_Effect: Females earn $5,000 more than the overall mean salary, while males earn $5,000 less than the overall mean, controlling for education and experience.
Gender_Effect
: With effect coding, the intercept
represents the grand mean (average across both genders).The Gender_Effect coefficient represents deviation from the grand mean.
So, instead of comparing to a reference group (like dummy coding), you’re interpreting effects relative to the overall mean.
Submission Instructions:
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