1. T-test of Average Monthly Hours by Left

t-test

## 
##  Welch Two Sample t-test
## 
## data:  hr$average_montly_hours by hr$left
## t = -7.5323, df = 4875.1, p-value = 5.907e-14
## alternative hypothesis: true difference in means between group Stayed and group Left is not equal to 0
## 95 percent confidence interval:
##  -10.534631  -6.183384
## sample estimates:
## mean in group Stayed   mean in group Left 
##             199.0602             207.4192

Technical Interpretation

We reject the null hypothesis, p value < .01, where the average monthly hours for employees that left is greater

Non-Technical Interpretation

Employees that work more hours are likely to leave

Graph

2. T-test of Satisfactin Level by Left

t-test

## 
##  Welch Two Sample t-test
## 
## data:  hr$satisfaction_level by hr$left
## t = 46.636, df = 5167, p-value < 2.2e-16
## alternative hypothesis: true difference in means between group Stayed and group Left is not equal to 0
## 95 percent confidence interval:
##  0.2171815 0.2362417
## sample estimates:
## mean in group Stayed   mean in group Left 
##            0.6668096            0.4400980

Technical Interpretation

We reject the null hypothesis because the p value is less than .01. We assume a difference in the mean satisfaction level of employees who have left and stayed.

Non-Technical Interpretation

There is greater satisfaction amongst employees who have stayed

Graph

3. T-test of Last Evaluation by Left

t-test

## 
##  Welch Two Sample t-test
## 
## data:  hr$last_evaluation by hr$left
## t = -0.72534, df = 5154.9, p-value = 0.4683
## alternative hypothesis: true difference in means between group Stayed and group Left is not equal to 0
## 95 percent confidence interval:
##  -0.009772224  0.004493874
## sample estimates:
## mean in group Stayed   mean in group Left 
##            0.7154734            0.7181126

Technical Interpretation

We accept the null hypothesis because the p value is greater than .01. We assume no difference in the mean last evaluation in employees who have left and stayed.

Non-Technical Interpretation

Mean last evaulation is identical in employees who have stayed and left

Graph

4. T-test of Time Spent at Company by Left

t-test

## 
##  Welch Two Sample t-test
## 
## data:  hr$time_spend_company by hr$left
## t = -22.631, df = 9625.6, p-value < 2.2e-16
## alternative hypothesis: true difference in means between group Stayed and group Left is not equal to 0
## 95 percent confidence interval:
##  -0.5394767 -0.4534706
## sample estimates:
## mean in group Stayed   mean in group Left 
##             3.380032             3.876505

Technical Interpretation

We reject the null hypothesis because the p value is less than .01. We assume a difference in the mean time spent at the company for employees who have left and stayed.

Non-Technical Interpretation

Mean time spent at the company is greater for employees who have left

Graph