##
## Welch Two Sample t-test
##
## data: hr$satisfaction_level by hr$left
## t = 46.636, df = 5167, p-value < 2.2e-16
## alternative hypothesis: true difference in means between group 0 and group 1 is not equal to 0
## 95 percent confidence interval:
## 0.2171815 0.2362417
## sample estimates:
## mean in group 0 mean in group 1
## 0.6668096 0.4400980Technical interpretation: The p-value is less than 0.001, meaning the difference in satisfaction levels between employees who left and those who stayed is statistically significant.
Non technical interpretation: Employees who left the company were less satisfied than those who stayed.
##
## Welch Two Sample t-test
##
## data: hr$average_montly_hours by hr$left
## t = -7.5323, df = 4875.1, p-value = 5.907e-14
## alternative hypothesis: true difference in means between group 0 and group 1 is not equal to 0
## 95 percent confidence interval:
## -10.534631 -6.183384
## sample estimates:
## mean in group 0 mean in group 1
## 199.0602 207.4192Technical interpretation: The p-value is very small (5.91e-14), so the difference in average monthly hours is statistically significant.
Non-Technical Interpretation:Employees who left the company worked more hours per month than those who stayed.
##
## Welch Two Sample t-test
##
## data: hr$last_evaluation by hr$left
## t = -0.72534, df = 5154.9, p-value = 0.4683
## alternative hypothesis: true difference in means between group 0 and group 1 is not equal to 0
## 95 percent confidence interval:
## -0.009772224 0.004493874
## sample estimates:
## mean in group 0 mean in group 1
## 0.7154734 0.7181126Technical interpretation: The p-value is 0.4683, so the difference in last evaluation scores is not statistically significant.
Non-Technical Interpretation:Employees who left the company had nearly the same performance evaluations as those who stayed.
##
## Welch Two Sample t-test
##
## data: hr$number_project by hr$left
## t = -2.1663, df = 4236.5, p-value = 0.03034
## alternative hypothesis: true difference in means between group 0 and group 1 is not equal to 0
## 95 percent confidence interval:
## -0.131136535 -0.006540119
## sample estimates:
## mean in group 0 mean in group 1
## 3.786664 3.855503Technical interpretation:The p-value is 0.0303, which means the difference in number of projects is statistically significant at the 5% level.
Non-Technical Interpretation:Employees who left the company were assigned slightly more projects than those who stayed.