# install any packages you have not previously used, then comment them back out.
#install.packages("car")
#install.packages("effsize")
library(psych) # for the describe() command
## Warning: package 'psych' was built under R version 4.4.3
library(car) # for the leveneTest() command
## Warning: package 'car' was built under R version 4.4.3
## Loading required package: carData
## Warning: package 'carData' was built under R version 4.4.3
##
## Attaching package: 'car'
## The following object is masked from 'package:psych':
##
## logit
library(effsize) # for the cohen.d() command
## Warning: package 'effsize' was built under R version 4.4.3
##
## Attaching package: 'effsize'
## The following object is masked from 'package:psych':
##
## cohen.d
d <- read.csv(file="Data/projectdata.csv", header=T)
# For the HW, you will import the project dataset you cleaned previously
# This will be the dataset you'll use for HWs throughout the rest of the semester
We predict that females will report significantly higher levels of perceived stress than males.
Note: Perceived Stress was measured using the Perceived Stress Scale in this dataset.
# you **only** need to check the variables you're using in the current analysis
## Checking the Categorical variable (IV)
str(d)
## 'data.frame': 1185 obs. of 7 variables:
## $ X : int 1 321 401 520 1390 1422 1849 2183 2247 2526 ...
## $ gender : chr "female" "male" "female" "female" ...
## $ trans : chr "no" "no" "no" "no" ...
## $ pas_covid: num 3.22 2.33 4 3 2.89 ...
## $ pss : num 3.25 2.25 2.25 2.75 2.75 4.75 3.25 3.5 2.25 3.5 ...
## $ gad : num 1.86 1 2.14 1.14 1 ...
## $ swemws : num 2.86 3.86 3.71 3 2.57 ...
# if the categorical variable you're using is showing as a "chr" (character), you must change it to be a ** factor ** -- using the next line of code (as.factor)
d$gender <- as.factor(d$gender)
str(d)
## 'data.frame': 1185 obs. of 7 variables:
## $ X : int 1 321 401 520 1390 1422 1849 2183 2247 2526 ...
## $ gender : Factor w/ 4 levels "female","I use another term",..: 1 3 1 1 3 1 1 1 1 1 ...
## $ trans : chr "no" "no" "no" "no" ...
## $ pas_covid: num 3.22 2.33 4 3 2.89 ...
## $ pss : num 3.25 2.25 2.25 2.75 2.75 4.75 3.25 3.5 2.25 3.5 ...
## $ gad : num 1.86 1 2.14 1.14 1 ...
## $ swemws : num 2.86 3.86 3.71 3 2.57 ...
table(d$gender, useNA = "always")
##
## female I use another term male Prefer not to say
## 951 31 185 18
## <NA>
## 0
## Checking the Continuous variable (DV)
# you can use the describe() command on an entire dataframe (d) or just on a single variable within your dataframe -- which we will do here
describe(d$pss)
## vars n mean sd median trimmed mad min max range skew kurtosis se
## X1 1 1185 2.91 0.95 3 2.9 1.11 1 5 4 0.1 -0.75 0.03
# also use a histogram to visualize your continuous variable
hist(d$pss)
# use the describeBy() command to view the means and standard deviations by group
# it's very similar to the describe() command but splits the dataframe according to the 'group' variable
describeBy(d$pss, group=d$gender)
##
## Descriptive statistics by group
## group: female
## vars n mean sd median trimmed mad min max range skew kurtosis se
## X1 1 951 2.93 0.94 3 2.93 1.11 1 5 4 0.07 -0.74 0.03
## ------------------------------------------------------------
## group: I use another term
## vars n mean sd median trimmed mad min max range skew kurtosis se
## X1 1 31 3.74 0.68 4 3.78 0.74 2 5 3 -0.5 -0.32 0.12
## ------------------------------------------------------------
## group: male
## vars n mean sd median trimmed mad min max range skew kurtosis se
## X1 1 185 2.62 0.91 2.5 2.57 0.74 1 5 4 0.51 -0.21 0.07
## ------------------------------------------------------------
## group: Prefer not to say
## vars n mean sd median trimmed mad min max range skew kurtosis se
## X1 1 18 3.32 0.92 3.5 3.33 1.11 1.75 4.75 3 -0.26 -1.32 0.22
# lastly, use a boxplot to examine your chosen continuous (first) and categorical variables together
boxplot(d$pss~d$gender)
# If the IV has more than 2 levels, you must DROP any additional levels in order to meet the first assumption of a t-test.
## NOTE: This is a FOUR STEP process!
##Dropping I use another term
d <- subset(d, gender!= "I use another term") # use subset() to remove all participants from the additional level
table(d$gender, useNA = "always") # verify that now there are ZERO participants in the additional level
##
## female I use another term male Prefer not to say
## 951 0 185 18
## <NA>
## 0
d$gender <- droplevels(d$gender) # use droplevels() to drop the empty factor
table(d$gender, useNA = "always") # verify that now the entire factor level is removed
##
## female male Prefer not to say <NA>
## 951 185 18 0
## Repeat ALL THE STEPS ABOVE if your IV has more levels that need to be DROPPED. Copy the 4 lines of code, and replace the level name in the subset() command.
## Dropping Prefer not to say
d <- subset(d, gender!= "Prefer not to say") # use subset() to remove all participants from the additional level
table(d$gender, useNA = "always") # verify that now there are ZERO participants in the additional level
##
## female male Prefer not to say <NA>
## 951 185 0 0
d$gender <- droplevels(d$gender) # use droplevels() to drop the empty factor
table(d$gender, useNA = "always") # verify that now the entire factor level is removed
##
## female male <NA>
## 951 185 0
We can test whether the variances of our two groups are equal using Levene’s test. The NULL hypothesis is that the variance between the two groups is equal, which is the result we WANT. So when running Levene’s test we’re hoping for a NON-SIGNIFICANT result!
# use the leveneTest() command from the car package to test homogeneity of variance
# it uses the same 'formula' setup that we'll use for our t-test: formula is y~x, where y is our DV and x is our IV
leveneTest(pss~gender, data =d)
## Levene's Test for Homogeneity of Variance (center = median)
## Df F value Pr(>F)
## group 1 1.9949 0.1581
## 1134
Levene’s test revealed that our data does not have significantly different variances between the two comparison groups, male and female, on their levels of perceived stress. (F=1.99, Pr=0.15)
When running a t-test, we can account for heterogeneity in our variance by using the Welch’s t-test, which does not have the same assumption about variance as the Student’s t-test (the general default type of t-test in statistics). R defaults to using Welch’s t-test so this doesn’t require any changes on our part! Even if your data has no issues with homogeneity of variance, you’ll still use Welch’s t-test – it handles the potential issues around variance well and there are no real downsides. We’re using Levene’s test here to get into the habit of checking the homogeneity of our variance, even if we already have the solution for any potential problems.
My independent variable has more than two levels. To proceed with this analysis, I will drop the participants who use another term aside from male or female, and participants who preferred not to say from my sample. I will make a note to discuss this issue in my Methods section write-up and in my Discussion section as a limitation of my study.
My data does not have an issue regarding homogeneity of variance, as Levene’s test was insignificant. Regardless, I will use Welch’s t-test instead of Student’s t-test in my analysis.
# Very simple! we use the same formula of y~x, where y is our DV and x is our IV
t_output <- t.test(d$pss~d$gender) # t_output will now show in your Global Environment
t_output
##
## Welch Two Sample t-test
##
## data: d$pss by d$gender
## t = 4.2664, df = 266.46, p-value = 2.763e-05
## alternative hypothesis: true difference in means between group female and group male is not equal to 0
## 95 percent confidence interval:
## 0.1692576 0.4593610
## sample estimates:
## mean in group female mean in group male
## 2.933228 2.618919
# once again, we use the same formula, y~x, to calculate cohen's d
# We **only** calculate effect size if the test is SIG!
d_output <- cohen.d(d$pss~d$gender) # d_output will now show in your Global Environment
d_output
##
## Cohen's d
##
## d estimate: 0.3349334 (small)
## 95 percent confidence interval:
## lower upper
## 0.1766705 0.4931962
## Remember to always take the ABSOLUTE VALUE of the effect size value (i.e., it will never be negative)
To test our hypothesis that females in our sample would report significantly higher levels of perceived stress than males, we used an independent samples t-test. This required us to drop our participants who used another term, and participants who preferred not to say from our sample, as we are limited to a two-group comparison when using this test. We tested the homogeneity of variance with Levene’s test and found insignificant heterogeneity of variance. Regardless, we used Welch’s t-test. Our data met all other assumptions of an independent samples t-test.
As predicted, we found that females (M = 2.93, SD = 0.94) reported significantly higher levels of stress than males (M = 2.62, SD = 0.91); t(266.46) = 4.27, p < .001 (see Figure 1). The effect size was calculated using Cohen’s d, with a value of 0.33 (small effect; Cohen, 1988).
References
Cohen J. (1988). Statistical Power Analysis for the Behavioral Sciences. New York, NY: Routledge Academic.