1+1
[1] 2
7-8
[1] -1
#Complex Numbers
(2+5i)+(3-1i)
[1] 5+4i
4/2
[1] 2
6/12
[1] 0.5
2^2
[1] 4
2^5
[1] 32
sqrt(25)
[1] 5
sqrt(16)
[1] 4
sqrt(144)
[1] 12
#Natural Log
log(2)
[1] 0.6931472
log(10)
[1] 2.302585
log(2.72)
[1] 1.000632
# Natural Log
log10(10)
[1] 1
Question 1: Compute the Log base 5 of 10 and the log of 10
# Answers: Question 1
#Log of 10, Base 5
log(10,5)
[1] 1.430677
#Log of 10, Base 10
log(10,10)
[1] 1
#Log of 100, Base 4
log(100,4)
[1] 3.321928
#Batting Average=(No. of Hits)/(No. of At Bats)
#What is the batting average of a player that bats 29 hits in 112 at bats?
BA=(129)/(412)
BA
[1] 0.3131068
#Alternative Solution
N_Hits=129
At_Bats=412
BA<-N_Hits/At_Bats
BA
[1] 0.3131068
Batting_Average=round(BA,digits = 3)
Batting_Average
[1] 0.313
Question 2: What is the batting average of a player that bats 42 hits in 212 at bats?
# Answers
N_Hits=42
At_Bats1=212
Bat_Average<-N_Hits/At_Bats1
BattingAverage=round(Bat_Average, digits = 3)
BattingAverage
[1] 0.198
#On Base Percentage
#OBP=(H+BB+HBP)/(At Bats+BB+HBP+SF)
#Let us compute the OBP for a player with the following general stats
# AB=515, H=172, BB=88, HBP=5, SF=6
OBP=(172+84+5)/(515+84+5+6)
OBP
[1] 0.4278689
OBP_Adj=round(OBP, digits = 3)
OBP_Adj
[1] 0.428
Question_3: Compute the OBP for a player with the following general stats:
#AB=565, H=156, BB=65, HBP=3, SF=7
OBP=(156+65+3)/(565+65+3+156+7)
OBP_ad=round(OBP, digits = 3)
OBP_ad
[1] 0.281
Often you will want to test whether something is less than, greater than, or equal to something.
3==8
[1] FALSE
2==3
[1] FALSE
1==1
[1] TRUE
3>=1
[1] TRUE
3>=9
[1] FALSE
7<=10
[1] TRUE
7<=6
[1] FALSE
3!=4
[1] TRUE
#Logical Disjunction (or)
FALSE | FALSE # False OR False
[1] FALSE
FALSE | TRUE # False OR True
[1] TRUE
TRUE & FALSE # True AND False
[1] FALSE
!TRUE
[1] FALSE
!FALSE
[1] TRUE
# Combination of statements
2 < 3 | 1 == 5 # 2<3 is True, 1==5 is False, True OR False is True
[1] TRUE
2<1|2==3
[1] FALSE
total_bases<-7+4
total_bases*4
[1] 44
rm(total_bases)
ls()
[1] "At_Bats" "At_Bats1"
[3] "BA" "Bat_Average"
[5] "Batting_Average" "BattingAverage"
[7] "N_Hits" "OBP"
[9] "OBP_ad" "OBP_Adj"
[11] "pitches_by_innings" "player_positions"
[13] "strikes_by_innings"
Vectors
pitches_by_innings<-c(12,15,10,20,10)
pitches_by_innings
[1] 12 15 10 20 10
strikes_by_innings<-c(9,12,6,14,9)
strikes_by_innings
[1] 9 12 6 14 9
rep(2,5)
[1] 2 2 2 2 2
rep(3,3)
[1] 3 3 3
1:6
[1] 1 2 3 4 5 6
2:7
[1] 2 3 4 5 6 7
seq(1,10,by=3)
[1] 1 4 7 10
pitches_by_innings+strikes_by_innings
[1] 21 27 16 34 19
#addition operator
#compare two vectors
pitches_by_innings
[1] 12 15 10 20 10
strikes_by_innings
[1] 9 12 6 14 9
pitches_by_innings==strikes_by_innings
[1] FALSE FALSE FALSE FALSE FALSE
length(pitches_by_innings)
[1] 5
min(pitches_by_innings)
[1] 10
mean(pitches_by_innings)
[1] 13.4
pitches_by_innings[1]
[1] 12
pitches_by_innings[length(pitches_by_innings)]
[1] 10
pitches_by_innings
[1] 12 15 10 20 10
pitches_by_innings[c(1:3)]
[1] 12 15 10
player_positions<-c("catcher", "pitcher", "infielders", "outfielders")
player_positions
[1] "catcher" "pitcher" "infielders"
[4] "outfielders"
Data Frames
data.frame(bonus=c(2,3,1), active_roster=c("yes", "no", "yes"), salary=c(1.5, 2.5, 1))
Using Tables
x<-c("Yes", "No","No","Yes","Yes")
table(x)
x
No Yes
2 3
Numerical measures and center of spread
ceo_salaries<-c(12,.4,2,15,8,3,1,4,.25)
mean(ceo_salaries)
[1] 5.072222
var(ceo_salaries)
[1] 28.95944
sd(ceo_salaries)
[1] 5.381398
median(ceo_salaries)
[1] 3
fivenum(ceo_salaries)
[1] 0.25 1.00 3.00 8.00 15.00
getMode<-function(x) {
ux<-unique(x)
ux[which.max(tabulate(match(x,ux)))]
}
pitches_by_innings
[1] 12 15 10 20 10
getMode(pitches_by_innings)
[1] 10
strikes_by_innings
getMode(strikes_by_innings)
game_day<-c("Saturday","Saturday","Sunday","Monday","Saturday","Tuesday","Sunday","Friday","Friday","Monday")
table(game_day)
game_day
Friday Monday Saturday Sunday Tuesday
2 2 3 2 1
getMode(game_day)
[1] "Saturday"