Part 1: Linear Regression
Understanding Regression
getwd()
[1] "/cloud/project"
# Load dataset
launch <- read.csv("challenger2.csv")
# Estimate beta manually
b <- cov(launch$temperature, launch$distress_ct) / var(launch$temperature)
b
[1] -0.03364796
# Estimate alpha manually
a <- mean(launch$distress_ct) - b * mean(launch$temperature)
a
[1] 2.814585
# Calculate the correlation of launch data
r <- cov(launch$temperature, launch$distress_ct) / (sd(launch$temperature) * sd(launch$distress_ct))
r
[1] -0.3359996
# Confirm correlation using cor function
cor(launch$temperature, launch$distress_ct)
[1] -0.3359996
# Compute the slope using correlation
slope <- r * (sd(launch$distress_ct) / sd(launch$temperature))
slope
[1] -0.03364796
# Regression model using lm function
model <- lm(distress_ct ~ temperature, data = launch)
summary(model)
Call:
lm(formula = distress_ct ~ temperature, data = launch)
Residuals:
Min 1Q Median 3Q Max
-1.0649 -0.4929 -0.2573 0.3052 1.7090
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 2.81458 1.24629 2.258 0.0322 *
temperature -0.03365 0.01815 -1.854 0.0747 .
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.7076 on 27 degrees of freedom
Multiple R-squared: 0.1129, Adjusted R-squared: 0.08004
F-statistic: 3.436 on 1 and 27 DF, p-value: 0.07474
# Predicting values and plotting the regression line
plot(launch$temperature, launch$distress_ct, main="Temperature vs. Distress Count")
abline(model, col="red")

Multiple Regression
# Define custom regression function
reg <- function(y, x) {
x <- as.matrix(x)
x <- cbind(Intercept = 1, x)
b <- solve(t(x) %*% x) %*% t(x) %*% y
colnames(b) <- "estimate"
print(b)
}
# Examine launch data structure
str(launch)
'data.frame': 29 obs. of 4 variables:
$ distress_ct : int 0 1 0 0 0 0 0 0 1 1 ...
$ temperature : int 66 70 69 68 67 72 73 70 57 63 ...
$ field_check_pressure: int 50 50 50 50 50 50 100 100 200 200 ...
$ flight_num : int 1 2 3 4 5 6 7 8 9 10 ...
# Test simple linear regression model
reg(y = launch$distress_ct, x = launch[2])
estimate
Intercept 2.81458456
temperature -0.03364796
# Test multiple regression model
reg(y = launch$distress_ct, x = launch[2:4])
estimate
Intercept 2.239817e+00
temperature -3.124185e-02
field_check_pressure -2.586765e-05
flight_num 2.762455e-02
# Confirm multiple regression using lm function
model <- lm(distress_ct ~ temperature + field_check_pressure + flight_num, data = launch)
summary(model)
Call:
lm(formula = distress_ct ~ temperature + field_check_pressure +
flight_num, data = launch)
Residuals:
Min 1Q Median 3Q Max
-1.2744 -0.3335 -0.1657 0.2975 1.5284
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 2.240e+00 1.267e+00 1.767 0.0894 .
temperature -3.124e-02 1.787e-02 -1.748 0.0927 .
field_check_pressure -2.587e-05 2.383e-03 -0.011 0.9914
flight_num 2.762e-02 1.798e-02 1.537 0.1369
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.6926 on 25 degrees of freedom
Multiple R-squared: 0.2132, Adjusted R-squared: 0.1188
F-statistic: 2.259 on 3 and 25 DF, p-value: 0.1063
Predicting Medical Expenses
# Load insurance dataset
insurance <- read.csv("insurance.csv", stringsAsFactors = TRUE)
str(insurance)
'data.frame': 1338 obs. of 7 variables:
$ age : int 19 18 28 33 32 31 46 37 37 60 ...
$ sex : Factor w/ 2 levels "female","male": 1 2 2 2 2 1 1 1 2 1 ...
$ bmi : num 27.9 33.8 33 22.7 28.9 25.7 33.4 27.7 29.8 25.8 ...
$ children: int 0 1 3 0 0 0 1 3 2 0 ...
$ smoker : Factor w/ 2 levels "no","yes": 2 1 1 1 1 1 1 1 1 1 ...
$ region : Factor w/ 4 levels "northeast","northwest",..: 4 3 3 2 2 3 3 2 1 2 ...
$ expenses: num 16885 1726 4449 21984 3867 ...
# Summarize expenses variable
summary(insurance$expenses)
Min. 1st Qu. Median Mean 3rd Qu. Max.
1122 4740 9382 13270 16640 63770
# Histogram of insurance expenses
hist(insurance$expenses)

# Table of region
table(insurance$region)
northeast northwest southeast southwest
324 325 364 325
# Correlation matrix of selected variables
cor(insurance[c("age", "bmi", "children", "expenses")])
age bmi children expenses
age 1.0000000 0.10934101 0.04246900 0.29900819
bmi 0.1093410 1.00000000 0.01264471 0.19857626
children 0.0424690 0.01264471 1.00000000 0.06799823
expenses 0.2990082 0.19857626 0.06799823 1.00000000
# Scatterplot matrix of selected variables
pairs(insurance[c("age", "bmi", "children", "expenses")])

Training and Evaluating a Model
# Train linear regression model
ins_model <- lm(expenses ~ age + children + bmi + sex + smoker + region, data = insurance)
ins_model <- lm(expenses ~ ., data = insurance) # Equivalent shorthand
# Model summary
summary(ins_model)
Call:
lm(formula = expenses ~ ., data = insurance)
Residuals:
Min 1Q Median 3Q Max
-11302.7 -2850.9 -979.6 1383.9 29981.7
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) -11941.6 987.8 -12.089 < 2e-16 ***
age 256.8 11.9 21.586 < 2e-16 ***
sexmale -131.3 332.9 -0.395 0.693255
bmi 339.3 28.6 11.864 < 2e-16 ***
children 475.7 137.8 3.452 0.000574 ***
smokeryes 23847.5 413.1 57.723 < 2e-16 ***
regionnorthwest -352.8 476.3 -0.741 0.458976
regionsoutheast -1035.6 478.7 -2.163 0.030685 *
regionsouthwest -959.3 477.9 -2.007 0.044921 *
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 6062 on 1329 degrees of freedom
Multiple R-squared: 0.7509, Adjusted R-squared: 0.7494
F-statistic: 500.9 on 8 and 1329 DF, p-value: < 2.2e-16
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