Việc 1. Đọc file

df = read.csv("E:\\DataScience\\SIS\\DULIEUDINHKEMBAITAP\\Bone data.csv")

Việc 2 Phân tích tương quan

library(lessR)
## 
## lessR 4.3.9                         feedback: gerbing@pdx.edu 
## --------------------------------------------------------------
## > d <- Read("")   Read text, Excel, SPSS, SAS, or R data file
##   d is default data frame, data= in analysis routines optional
## 
## Many examples of reading, writing, and manipulating data, 
## graphics, testing means and proportions, regression, factor analysis,
## customization, and descriptive statistics from pivot tables
##   Enter: browseVignettes("lessR")
## 
## View lessR updates, now including time series forecasting
##   Enter: news(package="lessR")
## 
## Interactive data analysis
##   Enter: interact()
## 
## Attaching package: 'lessR'
## The following object is masked from 'package:base':
## 
##     sort_by
Correlation(weight, fnbmd, data = df)
## Correlation Analysis for Variables weight and fnbmd 
##   
## 
## >>> Pearson's product-moment correlation 
##  
## Number of paired values with neither missing, n = 2121 
## Number of cases (rows of data) deleted: 41 
## 
## Sample Covariance: s = 1.269 
##  
## Sample Correlation: r = 0.581 
## 
## Hypothesis Test of 0 Correlation:  t = 32.882,  df = 2119,  p-value = 0.000 
## 95% Confidence Interval for Correlation:  0.552 to 0.609

Có mối liên quan giữa cân nặng và mật độ xương, với độ tương quan r = 0.581 (mức độ vừa, từ 0.6 - 0.8 mức độ trung bình, > 0.8 là mức độ tương quan cao). Khoảng tin cậy 95% dao động từ 0.552 đến 0.609.

Việc 3. Đánh giá mối tương quan đa biến

vars = df[, c("sex", "age", "weight", "height", "fnbmd")]
library (GGally)
## Loading required package: ggplot2
## Registered S3 method overwritten by 'GGally':
##   method from   
##   +.gg   ggplot2
ggpairs(data = vars, mapping = aes (color = sex))
## `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
## `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
## `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
## `stat_bin()` using `bins = 30`. Pick better value with `binwidth`.

Tất cả đều phân bố chuẩn, do cỡ mẫu lớn. Chỉ áp dụng các biến định lượng.

Việc 4. Thực hành về hồi quy tuyến tính

ob = read.csv("E:\\DataScience\\SIS\\DULIEUDINHKEMBAITAP\\Obesity data.csv")

So sánh tỉ trọng mỡ giữa nam và nữ

Sử dụng kiểm định t

library(lessR)
ttest(pcfat ~ gender, data = ob)
## 
## Compare pcfat across gender with levels F and M 
## Grouping Variable:  gender
## Response Variable:  pcfat
## 
## 
## ------ Describe ------
## 
## pcfat for gender F:  n.miss = 0,  n = 862,  mean = 34.672,  sd = 5.187
## pcfat for gender M:  n.miss = 0,  n = 355,  mean = 24.156,  sd = 5.764
## 
## Mean Difference of pcfat:  10.516
## 
## Weighted Average Standard Deviation:   5.362 
## 
## 
## ------ Assumptions ------
## 
## Note: These hypothesis tests can perform poorly, and the 
##       t-test is typically robust to violations of assumptions. 
##       Use as heuristic guides instead of interpreting literally. 
## 
## Null hypothesis, for each group, is a normal distribution of pcfat.
## Group F: Sample mean assumed normal because n > 30, so no test needed.
## Group M: Sample mean assumed normal because n > 30, so no test needed.
## 
## Null hypothesis is equal variances of pcfat, homogeneous.
## Variance Ratio test:  F = 33.223/26.909 = 1.235,  df = 354;861,  p-value = 0.016
## Levene's test, Brown-Forsythe:  t = -2.232,  df = 1215,  p-value = 0.026
## 
## 
## ------ Infer ------
## 
## --- Assume equal population variances of pcfat for each gender 
## 
## t-cutoff for 95% range of variation: tcut =  1.962 
## Standard Error of Mean Difference: SE =  0.338 
## 
## Hypothesis Test of 0 Mean Diff:  t-value = 31.101,  df = 1215,  p-value = 0.000
## 
## Margin of Error for 95% Confidence Level:  0.663
## 95% Confidence Interval for Mean Difference:  9.853 to 11.180
## 
## 
## --- Do not assume equal population variances of pcfat for each gender 
## 
## t-cutoff: tcut =  1.964 
## Standard Error of Mean Difference: SE =  0.353 
## 
## Hypothesis Test of 0 Mean Diff:  t = 29.768,  df = 602.015, p-value = 0.000
## 
## Margin of Error for 95% Confidence Level:  0.694
## 95% Confidence Interval for Mean Difference:  9.823 to 11.210
## 
## 
## ------ Effect Size ------
## 
## --- Assume equal population variances of pcfat for each gender 
## 
## Standardized Mean Difference of pcfat, Cohen's d:  1.961
## 
## 
## ------ Practical Importance ------
## 
## Minimum Mean Difference of practical importance: mmd
## Minimum Standardized Mean Difference of practical importance: msmd
## Neither value specified, so no analysis
## 
## 
## ------ Graphics Smoothing Parameter ------
## 
## Density bandwidth for gender F: 1.475
## Density bandwidth for gender M: 1.867

Sự khác biệt trung bình chuẩn hóa 1.961 lần độ lệch chuẩn. Khác biệt rất có ý nghĩa.

m1 = lm(pcfat ~ gender, data = ob); summary(m1)
## 
## Call:
## lm(formula = pcfat ~ gender, data = ob)
## 
## Residuals:
##      Min       1Q   Median       3Q      Max 
## -20.0724  -3.2724   0.1484   3.6276  14.8439 
## 
## Coefficients:
##             Estimate Std. Error t value            Pr(>|t|)    
## (Intercept)  34.6724     0.1826   189.9 <0.0000000000000002 ***
## genderM     -10.5163     0.3381   -31.1 <0.0000000000000002 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## Residual standard error: 5.362 on 1215 degrees of freedom
## Multiple R-squared:  0.4432, Adjusted R-squared:  0.4428 
## F-statistic: 967.3 on 1 and 1215 DF,  p-value: < 0.00000000000000022
m1
## 
## Call:
## lm(formula = pcfat ~ gender, data = ob)
## 
## Coefficients:
## (Intercept)      genderM  
##       34.67       -10.52
plot(m1)

Dùng gói ggfortify

library(ggfortify)
autoplot(m1)

Sử dụng mô hình hồi quy tuyến tính

m3 = lm(pcfat ~ weight, data = ob)
summary (m3)
## 
## Call:
## lm(formula = pcfat ~ weight, data = ob)
## 
## Residuals:
##      Min       1Q   Median       3Q      Max 
## -22.3122  -4.5234   0.8902   5.2695  16.9742 
## 
## Coefficients:
##             Estimate Std. Error t value            Pr(>|t|)    
## (Intercept) 29.22295    1.22370  23.881 <0.0000000000000002 ***
## weight       0.04319    0.02188   1.975              0.0485 *  
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## Residual standard error: 7.174 on 1215 degrees of freedom
## Multiple R-squared:  0.003199,   Adjusted R-squared:  0.002378 
## F-statistic: 3.899 on 1 and 1215 DF,  p-value: 0.04855
autoplot (m3)

Hệ số hồi quy. Có mối liên quan giữa cân nặng và tỉ trọng mỡ. Hiểu là: Cho mỗi 1 kg cân nặng gia tăng thì khối mỡ là 4g. Phương trình: pcfat = 29.2 + 0.04*weight

Việc 7. Đánh giá mối liên quan độc lập giữa cân nặng và tỉ trọng mỡ

m4 = lm(pcfat ~ weight + age + gender + height, data = ob)
summary(m4)
## 
## Call:
## lm(formula = pcfat ~ weight + age + gender + height, data = ob)
## 
## Residuals:
##     Min      1Q  Median      3Q     Max 
## -18.208  -2.543   0.019   2.582  15.706 
## 
## Coefficients:
##               Estimate Std. Error t value             Pr(>|t|)    
## (Intercept)  48.368722   3.505431  13.798 < 0.0000000000000002 ***
## weight        0.439169   0.015594  28.163 < 0.0000000000000002 ***
## age           0.056166   0.007404   7.585   0.0000000000000658 ***
## genderM     -11.483254   0.344343 -33.348 < 0.0000000000000002 ***
## height       -0.257013   0.023768 -10.813 < 0.0000000000000002 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## Residual standard error: 3.974 on 1212 degrees of freedom
## Multiple R-squared:  0.695,  Adjusted R-squared:  0.694 
## F-statistic: 690.4 on 4 and 1212 DF,  p-value: < 0.00000000000000022

Viết câu liên quan giữa giới tính và tỉ trọng mỡ: Ở cùng 1 cân nặng, cùng 1 độ tuổi, cùng 1 chiều cao, trung bình tỉ trọng mỡ của nam ít hơn nữ là 11.5%.

Viết phương trình: pcfat = 48.4 + 0.44weight + 0.06age - 11.5gender - 0.26height

##Việc 8. Sử dụng phương pháp BMA

library(BMA)
## Loading required package: survival
## Loading required package: leaps
## Loading required package: robustbase
## 
## Attaching package: 'robustbase'
## The following object is masked from 'package:survival':
## 
##     heart
## Loading required package: inline
## Loading required package: rrcov
## Scalable Robust Estimators with High Breakdown Point (version 1.7-6)
yvar = ob[, c("pcfat")]
xvar = ob[, c("gender", "age", "height", "weight", "bmi")]
m.bma = bicreg(xvar, yvar, strict = FALSE, OR = 20)
summary(m.bma)
## 
## Call:
## bicreg(x = xvar, y = yvar, strict = FALSE, OR = 20)
## 
## 
##   3  models were selected
##  Best  3  models (cumulative posterior probability =  1 ): 
## 
##            p!=0    EV        SD        model 1      model 2      model 3    
## Intercept  100.0    5.26146  4.582901      7.95773     -0.79279      8.13735
## genderM    100.0  -11.25139  0.429659    -11.44430    -11.42764    -10.80625
## age        100.0    0.05259  0.008048      0.05497      0.05473      0.04715
## height      31.4    0.01759  0.028494        .          0.05598        .    
## weight      39.2    0.03102  0.042611      0.07921        .            .    
## bmi        100.0    1.01265  0.111625      0.89419      1.08852      1.08936
##                                                                             
## nVar                                         4            4            3    
## r2                                         0.697        0.696        0.695  
## BIC                                    -1423.06312  -1422.62198  -1422.49027
## post prob                                  0.392        0.314        0.294
imageplot.bma(m.bma)

Giải thích kết quả: Mô hình 1 có 4 biến số, gặp trong 39.2 trường hợp. Xác xuất hậu định (post prob) của mô hình 1 cao nhất, tối ưu nhất Có 4 yếu tố trong mô hình thì yếu tố nào quan trọng nhất ? Để trả lời câu hỏi này phải thực hiện lệnh bên dưới

library(relaimpo)
## Loading required package: MASS
## Loading required package: boot
## 
## Attaching package: 'boot'
## The following object is masked from 'package:robustbase':
## 
##     salinity
## The following object is masked from 'package:survival':
## 
##     aml
## Loading required package: survey
## Loading required package: grid
## Loading required package: Matrix
## 
## Attaching package: 'survey'
## The following object is masked from 'package:graphics':
## 
##     dotchart
## Loading required package: mitools
## This is the global version of package relaimpo.
## If you are a non-US user, a version with the interesting additional metric pmvd is available
## from Ulrike Groempings web site at prof.beuth-hochschule.de/groemping.
ob$sex = ifelse(ob$gender == "F", 1, 0)
m.bma2 = lm(pcfat ~ sex + age + weight + bmi, data = ob)
calc.relimp(m.bma2, type = "lmg", rela = TRUE, rank = TRUE)
## Response variable: pcfat 
## Total response variance: 51.5935 
## Analysis based on 1217 observations 
## 
## 4 Regressors: 
## sex age weight bmi 
## Proportion of variance explained by model: 69.66%
## Metrics are normalized to sum to 100% (rela=TRUE). 
## 
## Relative importance metrics: 
## 
##               lmg
## sex    0.59317775
## age    0.06893066
## weight 0.09175463
## bmi    0.24613695
## 
## Average coefficients for different model sizes: 
## 
##                 1X         2Xs         3Xs         4Xs
## sex    10.51634414 11.71834412 11.80453842 11.44430262
## age     0.12768705  0.10445197  0.05168496  0.05496623
## weight  0.04319324 -0.05539405 -0.06907993  0.07920690
## bmi     1.03619023  1.50631405  1.54278433  0.89419395

Biến số quan trọng nhất là Sex, kế đến là bmi, quan trọng thứ 3 là weight, cuối cùng là age.