It’s interesting to note that \(2025 = 1^3
+ 2^3 + ... + 9^3\)
( It is also equal to \((1 + 2 + ... +
9)^2\) )
You can verify it quickly with declaring R functions on the
prompt:
f <- function(k) {
sum((1:k)^3)
}
g <- function(k) {
sum(1:k)^2
}
paste("f(9) =", f(9)); paste("g(9) =", g(9))
[1] "f(9) = 2025"
[1] "g(9) = 2025"
The last time the year was expressed as one of these series was in
\(f(8) =1296\); next time will be in
\(f(10) =3025\) (which is \(f(9)+10^3\), i.e. \(2025 + 1000\)).
Interestingly, this generalizes to all integers, the following
expression is true for any N:
\[(1^3 + 2^3 + ... + N^3) = (1 + 2 + ... +
N)^2\]
or, in more formal mathematical notation:
\[
\sum_{i=1}^Ni^3 = \left(\sum_{i=1}^Ni\right)^2
\]
To prove it, I used a proof by induction (and the fact that \(1+2+..+N=\frac{N(N+1)}{2}\)).
Can you?
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