#Class Exercise 16: Chapter 17 Forecasting
Using the naive method (most recent value) as the forecast for the next week, compute measures of forecast accuracy.
weeks <- 1:6
values <- c(17, 13, 15, 11, 17, 14)
forecasts_a <- values[-length(values)] #exclude last value
actual_a <- values[-1] # exclude the first value
mse_a <- mean((actual_a - forecasts_a)^2)
mse_a
## [1] 16.2
mae_a <- mean(abs(actual_a - forecasts_a))
mae_a
## [1] 3.8
mape_a <- mean(abs((actual_a - forecasts_a) / actual_a)) * 100
mape_a
## [1] 27.43778
###Forecast Week 7 & Output accuracy measures
forecast_week_7_a <- tail(values, 1)
forecast_week_7_a
## [1] 14
list(
MSE_most_recent_value = mse_a,
MAE_most_recent_value = mae_a,
MAPE_most_recent_value = mape_a,
forecast_week_7_most_recent = forecast_week_7_a)
## $MSE_most_recent_value
## [1] 16.2
##
## $MAE_most_recent_value
## [1] 3.8
##
## $MAPE_most_recent_value
## [1] 27.43778
##
## $forecast_week_7_most_recent
## [1] 14
The values of Alabama building contracts (in $ millions) for a 12-month period is as follows: 240, 352, 230, 260, 280, 322, 220, 310, 240, 310, 240, 230.
# Intall packages
# install.packages("dplyr")
# install.packages("zoo")
library(dplyr) # helps work w moving averages / data manipulation
##
## Attaching package: 'dplyr'
## The following objects are masked from 'package:stats':
##
## filter, lag
## The following objects are masked from 'package:base':
##
## intersect, setdiff, setequal, union
library(zoo) # helps w time series
##
## Attaching package: 'zoo'
## The following objects are masked from 'package:base':
##
## as.Date, as.Date.numeric
df <- data.frame(month = c(1,2,3,4,5,6,7,8,9,10,11,12),
data = c(240, 352, 230, 260, 280, 322, 220, 310, 240, 310, 240, 230))
# Time Series Plot
plot(df$month, df$data, type = "o", col = "pink", xlab = "Month", ylab = "Alabama Building Contracts (in $ millions)",
main = "Monthly Value of Alabama Building Contracts")
Interpretation: The time series plot exhibits a horizontal pattern as it is stead on the mean
Compare the three-month moving average approach with the exponential smoothing approach for a = 0.2. Which provides more accurate forecasts using MSE as the measure of forecast accuracy?
# Three Month Moving Average
df$avg_contract <- c(NA, NA, NA,
(df$data[1] + df$data[2] + df$data[3]) / 3,
(df$data[2] + df$data[3] + df$data[4]) / 3,
(df$data[3] + df$data[4] + df$data[5]) / 3,
(df$data[4] + df$data[5] + df$data[6]) / 3,
(df$data[5] + df$data[6] + df$data[7]) / 3,
(df$data[6] + df$data[7] + df$data[8]) / 3,
(df$data[7] + df$data[8] + df$data[9]) / 3,
(df$data[8] + df$data[9] + df$data[10]) / 3,
(df$data[9] + df$data[10] + df$data[11]) / 3)
# Calculate the Squared Errors (only for months that moving average is available)
df <- df %>%
mutate(
squared_error = ifelse(is.na(avg_contract), NA, (data - avg_contract)^2)
)
# Compute MSE (excluding the initial months with NA)
mse <- mean(df$squared_error, na.rm = TRUE)
mse
## [1] 2040.444
# mse = 2040.444
# Exponantial Smoothing
alpha <- 0.2
exp_smooth <- rep(NA, length(df$data))
exp_smooth[1] <- df$data[1] # starting point
for(i in 2:length(df$data)) {
exp_smooth[i] <- alpha * df$data[i-1] + (1 - alpha) * exp_smooth[i-1]
}
mse_exp_smooth <- mean((df$data[2:12] - exp_smooth[2:12])^2)
mse_exp_smooth
## [1] 2593.762
# Compare
better_method <- ifelse(mse < mse_exp_smooth, "Three-month moving average",
"Exponantial Smoothing")
list(
MSE_moving_avg = mse,
MSE_exp_smoothing = mse_exp_smooth,
Better_Method = better_method
)
## $MSE_moving_avg
## [1] 2040.444
##
## $MSE_exp_smoothing
## [1] 2593.762
##
## $Better_Method
## [1] "Three-month moving average"
# Result: Better method - "Three-month moving average"
library(readxl)
library(ggplot2)
# Load the data
df <- read_excel("Mortgage.xlsx")
# Part A: Time Series Plot
plot(df$Year, df$Interest_Rate, type = "o", col = "purple", xlab = "Year", ylab = "Interest Rate (%)",
main = "Average interest rate (%) for a 30-year fixed-rate mortgage over a 20-year period")
ggplot(df, aes(x = Year, y = Interest_Rate)) +
geom_line(color = "lightblue") +
#geom_point(col = "purple") +
labs(title = "Skechers' Revenue",
x = "Year", y = "ARevenue (in millions $)") +
theme_minimal()
# Interpretation: We observe an decreasing pattern/trend in the time series plot
# until an abrupt and steep rise in interest rates after 2020
# Part B. Linear Trend Equation
model <- lm(Interest_Rate ~ Period, data = df)
summary(model)
##
## Call:
## lm(formula = Interest_Rate ~ Period, data = df)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.3622 -0.7212 -0.2823 0.5015 3.1847
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 6.69541 0.43776 15.295 3.32e-13 ***
## Period -0.12890 0.03064 -4.207 0.000364 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 1.039 on 22 degrees of freedom
## Multiple R-squared: 0.4459, Adjusted R-squared: 0.4207
## F-statistic: 17.7 on 1 and 22 DF, p-value: 0.0003637
# Part C. Revenue for Period 15 (2024)
forecast_period_25 <- predict(model, newdata = data.frame(Period = 25))
forecast_period_25
## 1
## 3.472942