#Question 1. Naive Approach

#Project Objective To forecast for the next week, using Naive method install.packages(“ggplot2”)

#Time Series Data ###Step 1 Input the data

week <- 1:6
values <- c(17,13,15,11,17,14)

###Step 2 Exclude the Last and First Value

forecast_a <- values[-length(values)]
actual_a <- values[-1]

###Step 3 Find the MSE (Mean Squared Error)

mse_a <- mean((actual_a - forecast_a)^2)
mse_a
## [1] 16.2
### Step 4. Forecast the sales for the week 7
forecast_week7_a <- tail(values, 1)
forecast_week7_a
## [1] 14

###Step 5 Find the MAE (Mean Absolute Error)

mae_a <- mean(abs(actual_a - forecast_a))
mae_a
## [1] 3.8

###Step 6 Find the Mean Absolute Percentage Error (MAPE)

mape_a <- mean(abs((actual_a - forecast_a) / actual_a)) * 100
mape_a
## [1] 27.43778

Question 2 Moving Average and Smoothing Exponential

#Project Objective To Determine which Forecast is better to use between Exponential Smoothing and Moving Average

#Part A Moving Average

###Step 1 Install and load the packages

#install.packages("dplyr")
#install.packages("zoo")

###Step 2 Load the Libraries

library(dplyr)
## 
## 載入套件:'dplyr'
## 下列物件被遮斷自 'package:stats':
## 
##     filter, lag
## 下列物件被遮斷自 'package:base':
## 
##     intersect, setdiff, setequal, union
library(zoo)
## Warning: 套件 'zoo' 是用 R 版本 4.4.2 來建造的
## 
## 載入套件:'zoo'
## 下列物件被遮斷自 'package:base':
## 
##     as.Date, as.Date.numeric

###Step 3 Import the data

df <- data.frame(month=c(1,2,3,4,5,6,7,8,9,10,11,12),
                 values=c(240,352,230,260,280,322,220,310,240,310,240,230))

###Step 4 Descriptive Statistics

summary(df)
##      month           values     
##  Min.   : 1.00   Min.   :220.0  
##  1st Qu.: 3.75   1st Qu.:237.5  
##  Median : 6.50   Median :250.0  
##  Mean   : 6.50   Mean   :269.5  
##  3rd Qu.: 9.25   3rd Qu.:310.0  
##  Max.   :12.00   Max.   :352.0

###Step 5 Time Series Plot

plot(df$month, df$values, type = "o", col = "green", xlab = "Month", ylab = "$ Millions",
     main = "Values of Alabama Building contracts for 12 months")

###Step 6 Manually calculate the Three-Month Moving Average

df$avg_values3 <- c(NA, NA, NA,
                    (df$values[1] + df$values[2] + df$values[3]) / 3,
                    (df$values[2] + df$values[3] + df$values[4]) / 3,
                    (df$values[3] + df$values[4] + df$values[5]) / 3,
                    (df$values[4] + df$values[5] + df$values[6]) / 3,
                    (df$values[5] + df$values[6] + df$values[7]) / 3,
                    (df$values[6] + df$values[7] + df$values[8]) / 3,
                    (df$values[7] + df$values[8] + df$values[9]) / 3,
                    (df$values[8] + df$values[9] + df$values[10]) / 3,
                    (df$values[9] + df$values[10] + df$values[11]) / 3)

###Step 7 Calculate the Squared Errors

df <- df %>%
  mutate(
    squared_error = ifelse(is.na(avg_values3), NA, (values - avg_values3)^2)
  )

###Step 8 Compute Mean Squared Error (MSE)

mse <- mean(df$squared_error, na.rm = TRUE)
mse
## [1] 2040.444

###Step 9 Input alpha value and Find the Mean Squared Error (MSE)

alpha <- 0.2
exp_smooth <- rep(NA, length(df$values))
exp_smooth[1] <- df$values[1]
for(i in 2: length(df$values)) {
  exp_smooth[i] <- alpha * df$values[i-1] + (1 - alpha) * exp_smooth[i-1]
}
mse_exp_smooth <- mean((df$values[2:12] - exp_smooth[2:12])^2)
mse_exp_smooth
## [1] 2593.762

###Step 10 Comparison

better_method <- ifelse(mse < mse_exp_smooth, "Three-Month Moving Average", "Exponential Smoothing")

#List the Result
list(
  MSE_Moving_Average = mse,
  MSE_Exponential_Smoothing = mse_exp_smooth,
  Better_Method = better_method
)
## $MSE_Moving_Average
## [1] 2040.444
## 
## $MSE_Exponential_Smoothing
## [1] 2593.762
## 
## $Better_Method
## [1] "Three-Month Moving Average"
#Interpretation: The Three-Month Moving Average provides more accurate forecasts than Exponential Smoothing because
#it has a lower MSE (2040.44 < 2593.76), making this a better method to minimize errors and forecast more accurately

Question 3 Construct Time Series Plot and define its pattern

###Step 1 Install and Load the packages

#install.packages("ggplot2")
#install.packages("readxl")
library(ggplot2)
library(readxl)
## Warning: 套件 'readxl' 是用 R 版本 4.4.2 來建造的

###Step 2 Import the data

df <- read_excel("Mortgage.xlsx")
df
## # A tibble: 24 × 3
##    Year                Period Interest_Rate
##    <dttm>               <dbl>         <dbl>
##  1 2000-01-01 00:00:00      1          8.05
##  2 2001-01-01 00:00:00      2          6.97
##  3 2002-01-01 00:00:00      3          6.54
##  4 2003-01-01 00:00:00      4          5.83
##  5 2004-01-01 00:00:00      5          5.84
##  6 2005-01-01 00:00:00      6          5.87
##  7 2006-01-01 00:00:00      7          6.41
##  8 2007-01-01 00:00:00      8          6.34
##  9 2008-01-01 00:00:00      9          6.03
## 10 2009-01-01 00:00:00     10          5.04
## # ℹ 14 more rows
colnames(df)
## [1] "Year"          "Period"        "Interest_Rate"

###Step 3 Descriptive Statistics

summary(df)
##       Year                         Period      Interest_Rate  
##  Min.   :2000-01-01 00:00:00   Min.   : 1.00   Min.   :2.958  
##  1st Qu.:2005-10-01 18:00:00   1st Qu.: 6.75   1st Qu.:3.966  
##  Median :2011-07-02 12:00:00   Median :12.50   Median :4.863  
##  Mean   :2011-07-02 18:00:00   Mean   :12.50   Mean   :5.084  
##  3rd Qu.:2017-04-02 06:00:00   3rd Qu.:18.25   3rd Qu.:6.105  
##  Max.   :2023-01-01 00:00:00   Max.   :24.00   Max.   :8.053

###Step 4 Construct a time series plot

ggplot(df, aes(x = Period, y = `Interest_Rate`)) +
  geom_line() +
  geom_point() +
  xlab("Period") +
  ylab("Interest Rate") +
  ggtitle("Interest Rate of Mortgage")

Question 4 Develop the linear trend equation for this time series

###Step 5 Devlop a linear trend equation

model <- lm(`Interest_Rate` ~ Period, data = df)
summary(model)
## 
## Call:
## lm(formula = Interest_Rate ~ Period, data = df)
## 
## Residuals:
##     Min      1Q  Median      3Q     Max 
## -1.3622 -0.7212 -0.2823  0.5015  3.1847 
## 
## Coefficients:
##             Estimate Std. Error t value Pr(>|t|)    
## (Intercept)  6.69541    0.43776  15.295 3.32e-13 ***
## Period      -0.12890    0.03064  -4.207 0.000364 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## Residual standard error: 1.039 on 22 degrees of freedom
## Multiple R-squared:  0.4459, Adjusted R-squared:  0.4207 
## F-statistic:  17.7 on 1 and 22 DF,  p-value: 0.0003637

Question 5 Forecast the Average interest rate for the period 25

###Step 6 To find the MSE and MAPE values

# Calculate the fitted values from the model
df$predicted_interest_rat <- predict(model)

# Calculate the residuals
df$residuals <- df$Interest_Rate - df$predicted_interest_rat

# Calculate the Mean Squared Error (MSE)
mse <- mean(df$residuals^2)
cat("Mean Squared Error (MSE):", mse, "\n")
## Mean Squared Error (MSE): 0.989475
# BONUS SECTION: Calculate Mean Absolute Percentage Error (MAPE)
df$percentage_error <- abs(df$residuals / df$Interest_Rate) * 100
mape <- mean(df$percentage_error)
cat("Mean Absolute Percentage Error (MAPE)", mape, "%\n")
## Mean Absolute Percentage Error (MAPE) 15.79088 %

###Step 7 Forecast the number of interest rate in Period 25 (i.e., period 25)

forecast_period_25 <- predict(model, newdata = data.frame(Period = 25))
forecast_period_25
##        1 
## 3.472942