Logistic Regression - Predicting Tire Purchase Behavior

Project Objective

To investigate the relationship between Wet and Noise ratings on the likelihood of a customer purchasing a tire again.

Question 1 & 2: Model and Predictor Significance

Step 1: Install and load required libraries

# install.packages("readxl")
# install.packages("pscl")
#if(!require(pROC)) install.packages("pROC")

library(readxl)  # Allows us to import Excel files
library(pscl)    # Pseudo R-squared package
## Classes and Methods for R originally developed in the
## Political Science Computational Laboratory
## Department of Political Science
## Stanford University (2002-2015),
## by and under the direction of Simon Jackman.
## hurdle and zeroinfl functions by Achim Zeileis.
library(pROC)    # AUC and ROC curve package
## Type 'citation("pROC")' for a citation.
## 
## Attaching package: 'pROC'
## The following objects are masked from 'package:stats':
## 
##     cov, smooth, var
library(Hmisc)   # Correlation Function
## 
## Attaching package: 'Hmisc'
## The following objects are masked from 'package:base':
## 
##     format.pval, units

Step 2: Import & clean the data

tire_data <- read_excel("TireRatings.xlsx")
tire_df <- tire_data[, c("Wet", "Noise", "Purchase")]  # Select relevant columns

Step 3: Summarize the data

head(tire_df)
## # A tibble: 6 × 3
##     Wet Noise Purchase
##   <dbl> <dbl>    <dbl>
## 1   8     7.2        0
## 2   8     7.2        1
## 3   7.6   7.5        1
## 4   6.6   5.4        0
## 5   5.8   6.3        0
## 6   6.3   5.7        0
Data Description
1. Wet: Average wet traction performance rating (1–10).
2. Noise: Average noise performance rating (1–10).
3. Purchase: Binary variable (1 = Will purchase again, 0 = Won't).
summary(tire_df)
##       Wet            Noise          Purchase     
##  Min.   :4.300   Min.   :3.600   Min.   :0.0000  
##  1st Qu.:6.450   1st Qu.:6.000   1st Qu.:0.0000  
##  Median :7.750   Median :7.100   Median :0.0000  
##  Mean   :7.315   Mean   :6.903   Mean   :0.4412  
##  3rd Qu.:8.225   3rd Qu.:7.925   3rd Qu.:1.0000  
##  Max.   :9.200   Max.   :8.900   Max.   :1.0000
Interpretation: The median Wet rating is 7.75, the median Noise rating is 7.1, and most respondents indicated they would not purchase the tire again (median Purchase = 0).

Step 4: Feature selection (correlation analysis)

corr <- rcorr(as.matrix(tire_df))
corr
##           Wet Noise Purchase
## Wet      1.00  0.76     0.74
## Noise    0.76  1.00     0.72
## Purchase 0.74  0.72     1.00
## 
## n= 68 
## 
## 
## P
##          Wet Noise Purchase
## Wet           0     0      
## Noise     0         0      
## Purchase  0   0
Interpretation: All predictors are significant with the target variable (Purchase).
There is no multicollinearity in the data.

Step 5: Build the logistic regression model

model <- glm(Purchase ~ Wet + Noise, data = tire_df, family = binomial)
summary(model)
## 
## Call:
## glm(formula = Purchase ~ Wet + Noise, family = binomial, data = tire_df)
## 
## Coefficients:
##             Estimate Std. Error z value Pr(>|z|)   
## (Intercept) -39.4982    12.4779  -3.165  0.00155 **
## Wet           3.3745     1.2641   2.670  0.00760 **
## Noise         1.8163     0.8312   2.185  0.02887 * 
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## (Dispersion parameter for binomial family taken to be 1)
## 
##     Null deviance: 93.325  on 67  degrees of freedom
## Residual deviance: 27.530  on 65  degrees of freedom
## AIC: 33.53
## 
## Number of Fisher Scoring iterations: 8
Interpretation: The model shows that both Wet and Noise ratings significantly increase the likelihood of purchasing a tire again.

Question 3: Overall Model Significance

Likelihood Ratio Test

null_model <- glm(Purchase ~ 1, data = tire_df, family = binomial)
anova(null_model, model, test = "Chisq")
## Analysis of Deviance Table
## 
## Model 1: Purchase ~ 1
## Model 2: Purchase ~ Wet + Noise
##   Resid. Df Resid. Dev Df Deviance  Pr(>Chi)    
## 1        67     93.325                          
## 2        65     27.530  2   65.795 5.162e-15 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Interpretation: The model with predictors (Wet and Noise) significantly predicts the likelihood of purchasing again compared to the null model.

Pseudo-R-squared

pR2(model)
## fitting null model for pseudo-r2
##         llh     llhNull          G2    McFadden        r2ML        r2CU 
## -13.7649516 -46.6623284  65.7947536   0.7050093   0.6199946   0.8305269
Interpretation: A McFadden R-squared of 0.71 indicates a very good model fit.

Area Under the Curve (AUC)

#Compute ROC Curve and the AUC score
roc_curve <- roc(tire_df$Purchase, fitted(model))
## Setting levels: control = 0, case = 1
## Setting direction: controls < cases
plot(roc_curve)

auc(roc_curve)
## Area under the curve: 0.9741
Interpretation: An AUC score of r round(auc(roc_curve), 2) indicates high model accuracy in predicting purchase behavior.

Question 4 & 5: Predicting with New Information

# Given new customer data
new_data1 <- data.frame(Wet = 8, Noise = 8)  # High performance ratings
new_data2 <- data.frame(Wet = 7, Noise = 7)  # Moderate performance ratings

# Predict probabilities
prob1 <- predict(model, newdata = new_data1, type = "response")
round(prob1 * 100, 2)  # 88.37%
##     1 
## 88.37
prob2 <- predict(model, newdata = new_data2, type = "response")
round(prob2 * 100, 2)  # 4.06%
##    1 
## 4.06
Interpretation:
1. 88.37% chance the customer will purchase again with high Wet and Noise ratings.
2. 4.06% chance the customer will purchase again with moderate Wet and Noise ratings.

Question 6: Odds Ratio

coefficients <- summary(model)$coefficients
odds_ratio_wet <- exp(coefficients["Wet", "Estimate"])
odds_ratio_noise <- exp(coefficients["Noise", "Estimate"])

odds_ratio_wet
## [1] 29.20949
odds_ratio_noise
## [1] 6.148919
Interpretation: Odds ratios of 29.21 for Wet and 6.15 for Noise indicate the increase in likelihood of purchase per unit increase in Wet and Noise ratings.