Predicting Consumer Tire Purchase Likelihood

Project Objective

Investigate weather tire performance factors will lead to buy again, and use logistic regression analysis to find appropriate marketing plans

Question 1 & 2: Develop a Model & Assess Predictor Significance

Step 1: Install and load required libraries

#install.packages("readxl")
#install.packages("Hmisc")
#install.packages("pscl")
#if(!require(pROC)) install.packages("pROC")

library(readxl)
## Warning: 套件 'readxl' 是用 R 版本 4.4.2 來建造的
library(Hmisc)
## Warning: 套件 'Hmisc' 是用 R 版本 4.4.2 來建造的
## 
## 載入套件:'Hmisc'
## 下列物件被遮斷自 'package:base':
## 
##     format.pval, units
library(pscl)
## Warning: 套件 'pscl' 是用 R 版本 4.4.2 來建造的
## Classes and Methods for R originally developed in the
## Political Science Computational Laboratory
## Department of Political Science
## Stanford University (2002-2015),
## by and under the direction of Simon Jackman.
## hurdle and zeroinfl functions by Achim Zeileis.
library(pROC)
## Warning: 套件 'pROC' 是用 R 版本 4.4.2 來建造的
## Type 'citation("pROC")' for a citation.
## 
## 載入套件:'pROC'
## 下列物件被遮斷自 'package:stats':
## 
##     cov, smooth, var

Step 2: Import &clean the data

data <- read_excel(file.choose())
data <- subset(data, select = -c(Tire))

Step 3: Summarize the data

head(data)
## # A tibble: 6 × 4
##     Wet Noise Buy_Again Purchase
##   <dbl> <dbl>     <dbl>    <dbl>
## 1   8     7.2       6.1        0
## 2   8     7.2       6.6        1
## 3   7.6   7.5       6.9        1
## 4   6.6   5.4       6.6        0
## 5   5.8   6.3       4          0
## 6   6.3   5.7       4.5        0
Data Description: A description of the features are presented in the table below
Variable     |Definition
-------------|--------
1. Wet       |Refers to the tire's traction performance on wet roads, with scores ranging from 1 to 10, with higher scores indicating better performance;
2. Noise     |Represents the level of noise when the tire is running, and the score range is also from 1 to 10. The higher the score, the less the noise.
3. Buy_Again |Reflects the consumer's willingness to buy the tire again, with a score from 1 to 10, where 10 means "definitely will buy it again" and the lower the score, the lower the willingness.
4. Purchase  |Converts the consumer's willingness to buy again into a binary variable. If the Buy Again score is 7 or above, it is recorded as 1 (indicating that it may or will definitely be purchased), and if it is lower than 7, it is recorded as 0 (indicating that it may or will definitely not be purchased). Buy)
summary(data)
##       Wet            Noise         Buy_Again        Purchase     
##  Min.   :4.300   Min.   :3.600   Min.   :1.400   Min.   :0.0000  
##  1st Qu.:6.450   1st Qu.:6.000   1st Qu.:3.850   1st Qu.:0.0000  
##  Median :7.750   Median :7.100   Median :6.150   Median :0.0000  
##  Mean   :7.315   Mean   :6.903   Mean   :5.657   Mean   :0.4412  
##  3rd Qu.:8.225   3rd Qu.:7.925   3rd Qu.:7.400   3rd Qu.:1.0000  
##  Max.   :9.200   Max.   :8.900   Max.   :8.900   Max.   :1.0000
Interpretation : The median Wet is 7.75, with a median of noise is 7.1 meaning that most tires perform well in terms of wet performance and noise control

Step 4: Feature selection (i.e., correlation analysis)

corr <- rcorr(as.matrix(data))
corr
##            Wet Noise Buy_Again Purchase
## Wet       1.00  0.76      0.91     0.74
## Noise     0.76  1.00      0.83     0.72
## Buy_Again 0.91  0.83      1.00     0.83
## Purchase  0.74  0.72      0.83     1.00
## 
## n= 68 
## 
## 
## P
##           Wet Noise Buy_Again Purchase
## Wet            0     0         0      
## Noise      0         0         0      
## Buy_Again  0   0               0      
## Purchase   0   0     0
Interpretation: All the predictors are significant with the target variable(i.e., Wet and Noise). There's no multicollinearity in the data.

Step 5: Build the logistic regression model

model <- glm(Purchase ~ Wet + Noise, data = data, family = binomial)
summary(model)
## 
## Call:
## glm(formula = Purchase ~ Wet + Noise, family = binomial, data = data)
## 
## Coefficients:
##             Estimate Std. Error z value Pr(>|z|)   
## (Intercept) -39.4982    12.4779  -3.165  0.00155 **
## Wet           3.3745     1.2641   2.670  0.00760 **
## Noise         1.8163     0.8312   2.185  0.02887 * 
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## (Dispersion parameter for binomial family taken to be 1)
## 
##     Null deviance: 93.325  on 67  degrees of freedom
## Residual deviance: 27.530  on 65  degrees of freedom
## AIC: 33.53
## 
## Number of Fisher Scoring iterations: 8
Interpretation: All the independent variables were significant (p-value < 0.05)

Question 3: Overall Model Significance

Likelihood Ratio Test

null_model <- glm(Purchase ~ 1, data = data, family = binomial)
anova(null_model, model, test = "Chisq")
## Analysis of Deviance Table
## 
## Model 1: Purchase ~ 1
## Model 2: Purchase ~ Wet + Noise
##   Resid. Df Resid. Dev Df Deviance  Pr(>Chi)    
## 1        67     93.325                          
## 2        65     27.530  2   65.795 5.162e-15 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Interpretation: The deviance table shows that adding Wet and Noise to the model significantly improves fit (p-value = 5.162e-15), reducing residual deviance from 93.325 to 27.530. This indicates both variables are strong, significant predictors of purchase likelihood.

Pseudo-R-squared

pR2(model)
## fitting null model for pseudo-r2
##         llh     llhNull          G2    McFadden        r2ML        r2CU 
## -13.7649516 -46.6623284  65.7947536   0.7050093   0.6199946   0.8305269
Interpretation: A McFadden R-squared of 0.705 means that our LR model explains about  the predictors Wet and Noise explain approximately 70.5% of the variation in the likelihood of a customer purchasing the tire again. This value is considered high for logistic regression models, further confirming the importance of these variables in predicting purchase decisions.

Question 4 & 5: Predicting with New Information

new_data1 <- data.frame(Wet = 8, Noise = 8)
new_data2 <- data.frame(Wet = 7, Noise = 7)

prob1 <- predict(model, newdata = new_data1, type = "response")
prob1 * 100
##        1 
## 88.36964
prob2 <- predict(model, newdata = new_data2, type = "response")
prob2 * 100
##        1 
## 4.058753
Interpretation
(1)For a Wet performance rating of 8 and a Noise performance rating of 8, the estimated probability that a customer will probably or definitely purchase the tire again is 88.37%.

(2)For a Wet performance rating of 7 and a Noise performance rating of 7, the estimated probability drops to 4.06%, indicating a much lower likelihood of purchase.