To investigate the relationship between the independent variables of Noise and Wet rating and purchases for tires.
#install.packages("readxl")
#install.packages("Hmisc")
#install.packages("pscl")
library("readxl")
## Warning: package 'readxl' was built under R version 4.4.2
library(pscl)
## Warning: package 'pscl' was built under R version 4.4.2
## Classes and Methods for R originally developed in the
## Political Science Computational Laboratory
## Department of Political Science
## Stanford University (2002-2015),
## by and under the direction of Simon Jackman.
## hurdle and zeroinfl functions by Achim Zeileis.
library(Hmisc)
## Warning: package 'Hmisc' was built under R version 4.4.2
##
## Attaching package: 'Hmisc'
## The following objects are masked from 'package:base':
##
## format.pval, units
data <- read_excel(file.choose())
df <- subset(data, select = -c(Tire)) #drop tire column
head(df)
## # A tibble: 6 × 4
## Wet Noise Buy_Again Purchase
## <dbl> <dbl> <dbl> <dbl>
## 1 8 7.2 6.1 0
## 2 8 7.2 6.6 1
## 3 7.6 7.5 6.9 1
## 4 6.6 5.4 6.6 0
## 5 5.8 6.3 4 0
## 6 6.3 5.7 4.5 0
summary(df)
## Wet Noise Buy_Again Purchase
## Min. :4.300 Min. :3.600 Min. :1.400 Min. :0.0000
## 1st Qu.:6.450 1st Qu.:6.000 1st Qu.:3.850 1st Qu.:0.0000
## Median :7.750 Median :7.100 Median :6.150 Median :0.0000
## Mean :7.315 Mean :6.903 Mean :5.657 Mean :0.4412
## 3rd Qu.:8.225 3rd Qu.:7.925 3rd Qu.:7.400 3rd Qu.:1.0000
## Max. :9.200 Max. :8.900 Max. :8.900 Max. :1.0000
corr <- rcorr(as.matrix(df))
corr
## Wet Noise Buy_Again Purchase
## Wet 1.00 0.76 0.91 0.74
## Noise 0.76 1.00 0.83 0.72
## Buy_Again 0.91 0.83 1.00 0.83
## Purchase 0.74 0.72 0.83 1.00
##
## n= 68
##
##
## P
## Wet Noise Buy_Again Purchase
## Wet 0 0 0
## Noise 0 0 0
## Buy_Again 0 0 0
## Purchase 0 0 0
Interpretation: All the predictors are significant with target variable(Purchase). There’s no multicollinearity to the data.
All
model <- glm(Purchase ~ Wet + Noise , data = df, family = binomial)
summary(model)
##
## Call:
## glm(formula = Purchase ~ Wet + Noise, family = binomial, data = df)
##
## Coefficients:
## Estimate Std. Error z value Pr(>|z|)
## (Intercept) -39.4982 12.4779 -3.165 0.00155 **
## Wet 3.3745 1.2641 2.670 0.00760 **
## Noise 1.8163 0.8312 2.185 0.02887 *
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## (Dispersion parameter for binomial family taken to be 1)
##
## Null deviance: 93.325 on 67 degrees of freedom
## Residual deviance: 27.530 on 65 degrees of freedom
## AIC: 33.53
##
## Number of Fisher Scoring iterations: 8
Interpretation: Wet and Noise rating variable were significant (p-value < 0.05)
###Likelihood Ratio Test
#Fit a null model
null_model <- glm(Purchase ~ 1, data = df, family = binomial)
null_model
##
## Call: glm(formula = Purchase ~ 1, family = binomial, data = df)
##
## Coefficients:
## (Intercept)
## -0.2364
##
## Degrees of Freedom: 67 Total (i.e. Null); 67 Residual
## Null Deviance: 93.32
## Residual Deviance: 93.32 AIC: 95.32
#Perform likelihood ratio test
anova(null_model, model, test = "Chisq")
## Analysis of Deviance Table
##
## Model 1: Purchase ~ 1
## Model 2: Purchase ~ Wet + Noise
## Resid. Df Resid. Dev Df Deviance Pr(>Chi)
## 1 67 93.325
## 2 65 27.530 2 65.795 5.162e-15 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
pR2(model)
## fitting null model for pseudo-r2
## llh llhNull G2 McFadden r2ML r2CU
## -13.7649516 -46.6623284 65.7947536 0.7050093 0.6199946 0.8305269
Interpretation: Under Mcfadden, an R-squared of 0.71 (rounded) means that our Logistics Regression model explains that 71% of the variability in the outcome relative to a model with no predictors. This is considered a good fit.
new_data1 <- data.frame(Wet = 7, Noise = 7, Purchase = 1)
new_data2 <- data.frame(Wet = 8, Noise = 8, Purchase = 1)
prob1 <- predict(model, newdata = new_data1, type = "response")
prob1 * 100
## 1
## 4.058753
prob2 <- predict(model, newdata = new_data2, type = "response")
prob2 * 100
## 1
## 88.36964
Interpretation:
Question 5: There is a 88.37% chance the customer would buy again if they rated their tires 8 for wet and noise.
Question 4: There is a 4.06% chance the customer would buy again if they rated their tires 7 for wet and noise.