library(readr)
library(dplyr)
## 
## Attaching package: 'dplyr'
## The following objects are masked from 'package:stats':
## 
##     filter, lag
## The following objects are masked from 'package:base':
## 
##     intersect, setdiff, setequal, union
library(plotly)
## Loading required package: ggplot2
## 
## Attaching package: 'plotly'
## The following object is masked from 'package:ggplot2':
## 
##     last_plot
## The following object is masked from 'package:stats':
## 
##     filter
## The following object is masked from 'package:graphics':
## 
##     layout
hr <- read_csv('https://raw.githubusercontent.com/aiplanethub/Datasets/refs/heads/master/HR_comma_sep.csv')
## Rows: 14999 Columns: 10
## ── Column specification ────────────────────────────────────────────────────────
## Delimiter: ","
## chr (2): Department, salary
## dbl (8): satisfaction_level, last_evaluation, number_project, average_montly...
## 
## ℹ Use `spec()` to retrieve the full column specification for this data.
## ℹ Specify the column types or set `show_col_types = FALSE` to quiet this message.
hr1 <- hr %>% 
  mutate(Employee_Status = ifelse(left == 0 , 'Stayed' , 'Left'))

First T-Test

t.test(hr1$average_montly_hours ~ hr1$Employee_Status)
## 
##  Welch Two Sample t-test
## 
## data:  hr1$average_montly_hours by hr1$Employee_Status
## t = 7.5323, df = 4875.1, p-value = 5.907e-14
## alternative hypothesis: true difference in means between group Left and group Stayed is not equal to 0
## 95 percent confidence interval:
##   6.183384 10.534631
## sample estimates:
##   mean in group Left mean in group Stayed 
##             207.4192             199.0602

There is a significant difference between means, where employees that

left work at least 6 more hours

Descriptive: employees that left on average work more hours, at least 3% more

Prescriptive: To reduce employee attrition, average monthly hours can be reduced by 3%, for those who work longer hours.

plot_ly(hr1 , 
        x = ~Employee_Status ,
        y = ~average_montly_hours ,
        type = 'box',
        color = ~Employee_Status,
        colors = c('red','blue'))%>%
  layout(title = 'Employees that left on average, work more hours, at least 3% more.')

Second T-Test

t.test(hr1$satisfaction_level ~ hr1$Employee_Status)
## 
##  Welch Two Sample t-test
## 
## data:  hr1$satisfaction_level by hr1$Employee_Status
## t = -46.636, df = 5167, p-value < 2.2e-16
## alternative hypothesis: true difference in means between group Left and group Stayed is not equal to 0
## 95 percent confidence interval:
##  -0.2362417 -0.2171815
## sample estimates:
##   mean in group Left mean in group Stayed 
##            0.4400980            0.6668096

There is a significant difference between the means, where employees that left are 22% less satisfied.

Descriptive: Employees that left on average, are less satisfied, 22% less.

plot_ly(hr1 , 
        x = ~Employee_Status ,
        y = ~satisfaction_level ,
        type = 'box',
        color = ~Employee_Status,
        colors = c('red','blue'))%>%
  layout(title = 'Employees that left on average, are less satisfied, 22% less.')

Third T-Test

t.test(hr1$last_evaluation ~ hr1$Employee_Status)
## 
##  Welch Two Sample t-test
## 
## data:  hr1$last_evaluation by hr1$Employee_Status
## t = 0.72534, df = 5154.9, p-value = 0.4683
## alternative hypothesis: true difference in means between group Left and group Stayed is not equal to 0
## 95 percent confidence interval:
##  -0.004493874  0.009772224
## sample estimates:
##   mean in group Left mean in group Stayed 
##            0.7181126            0.7154734

There is a significant difference between the means, where employees that left had evaluation scores of 0.3% slightly higher then the group who stayed.

Descriptive: Employees that left on average, have a similar last evaluation score as the people who stayed.

plot_ly(hr1 , 
        x = ~Employee_Status ,
        y = ~last_evaluation ,
        type = 'box',
        color = ~Employee_Status,
        colors = c('red','blue'))%>%
  layout(title = 'Employees that left on average, have a similar last evaluation score as the people who stayed.')

Fourth T-Test

t.test(hr1$number_project ~ hr1$Employee_Status)
## 
##  Welch Two Sample t-test
## 
## data:  hr1$number_project by hr1$Employee_Status
## t = 2.1663, df = 4236.5, p-value = 0.03034
## alternative hypothesis: true difference in means between group Left and group Stayed is not equal to 0
## 95 percent confidence interval:
##  0.006540119 0.131136535
## sample estimates:
##   mean in group Left mean in group Stayed 
##             3.855503             3.786664

There is a significant difference between the means, where people who left on average did 0.07 more projects.

Descriptive: The Employees that left on average, have a similar number of projects as the people who stayed.

plot_ly(hr1 , 
        x = ~Employee_Status ,
        y = ~number_project ,
        type = 'box',
        color = ~Employee_Status,
        colors = c('red','blue'))%>%
  layout(title = 'The Employees that left on average, have a similar number of projects as the people who stayed.')