library(tidyverse)
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library(readxl)
data<-read_excel("district.xls")
head(data)
## # A tibble: 6 × 137
## DISTNAME DISTRICT DZCNTYNM REGION DZRATING DZCAMPUS DPETALLC DPETBLAP DPETHISP
## <chr> <chr> <chr> <chr> <chr> <dbl> <dbl> <dbl> <dbl>
## 1 CAYUGA … 001902 001 AND… 07 A 3 574 4.4 11.5
## 2 ELKHART… 001903 001 AND… 07 A 4 1150 4 11.8
## 3 FRANKST… 001904 001 AND… 07 A 3 808 8.5 11.3
## 4 NECHES … 001906 001 AND… 07 A 2 342 8.2 13.5
## 5 PALESTI… 001907 001 AND… 07 B 6 3360 25.1 42.9
## 6 WESTWOO… 001908 001 AND… 07 B 4 1332 19.7 26.2
## # ℹ 128 more variables: DPETWHIP <dbl>, DPETINDP <dbl>, DPETASIP <dbl>,
## # DPETPCIP <dbl>, DPETTWOP <dbl>, DPETECOP <dbl>, DPETLEPP <dbl>,
## # DPETSPEP <dbl>, DPETBILP <dbl>, DPETVOCP <dbl>, DPETGIFP <dbl>,
## # DA0AT21R <dbl>, DA0912DR21R <dbl>, DAGC4X21R <dbl>, DAGC5X20R <dbl>,
## # DAGC6X19R <dbl>, DA0GR21N <dbl>, DA0GS21N <dbl>, DDA00A001S22R <dbl>,
## # DDA00A001222R <dbl>, DDA00A001322R <dbl>, DDA00AR01S22R <dbl>,
## # DDA00AR01222R <dbl>, DDA00AR01322R <dbl>, DDA00AM01S22R <dbl>, …
Correlation between number of economically disadvantaged students and assessment scores/performance indicators.
selected_data<-data %>% select(DPETPCIP, DA0AT21R)
Cor_matrix <- cor(selected_data, use = "complete.obs")
Cor_matrix
## DPETPCIP DA0AT21R
## DPETPCIP 1.000000000 -0.008076046
## DA0AT21R -0.008076046 1.000000000
pairs(selected_data)
I will now find the correlation using Pearson between two variables … number of economically disadvantaged students & number of gifted and talented students.
x1<-data$DPETPCIP
x2<-data$DPETGIFP
pearson_corr<- cor(x1, x2, method="pearson")
pearson_corr
## [1] 0.01306929
I chose the Pearson method since the two varibles I was trying to measure a linear relationship.
Since this number is close to 0, this means that being economically disadvantaged does not have a strong linear relationship and doesn’t correspond with being gifted and talented.