\[ \begin{array}{|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} \\ \hline H_0: \mu_1 \geq \mu_1 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu_1 < \mu_2 \leftrightarrow \mu_1 - \mu_2 < 0 \\ \hline H_0: \mu_1 = \mu_2 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu_1 \neq \mu_2 \leftrightarrow \mu_1 - \mu_2 \neq 0 \\ \hline H_0: \mu_1 \leq \mu_2 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 \\ \hline \end{array} \]
\[ \text{Si }X_1{\sim}N(\mu_1,\sigma_x^2),X_2{\sim}N(\mu_2,\sigma_x^2)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{\sigma_x\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}{\sim}N(0,1) \]
\[ \text{Si }X_1{\sim}P\left(E_P(X_1),Var_P(X_1)\right),X_2{\sim}P\left(E_P(X_2),Var_P(X_2)\right)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{\sigma_x\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}\stackrel{n{\rightarrow}\infty}{\sim}N(0,1) \]
\[ \text{Si }X_1{\sim}N(\mu_1,\sigma_1^2),X_2{\sim}N(\mu_2,\sigma_2^2)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}{\sim}N(0,1) \]
\[ \text{Si }X_1{\sim}P\left(E_P(X_1),Var_P(X_1)\right),X_2{\sim}P\left(E_P(X_2),Var_P(X_2)\right)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}\stackrel{n{\rightarrow}\infty}{\sim}N(0,1) \]
\[ \text{Si }X_1{\sim}N(\mu_1,\sigma_1^2),X_2{\sim}N(\mu_2,\sigma_2^2)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}{\sim}t_{(n-1)} \]
\[ \text{Si }X_1,X_2{\sim}P\left(E_P(X),Var_P(X)\right)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}\stackrel{n{\rightarrow}\infty}{\sim}N(0,1) \]
donde: \(s_p = \sqrt{\frac{(n_1 - 1)s_1^2 + (n_2 - 1)s_2^2}{n_1 + n_2 - 2}}\)
\[ \text{Si }X_1{\sim}N(\mu_1,s_1^2),X_2{\sim}N(\mu_2,s_2^2)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}{\sim}N(0,1) \]
\[ \text{Si }X_1{\sim}P\left(E_P(X_1),Var_P(X_1)\right),X_2{\sim}P\left(E_P(X_2),Var_P(X_2)\right)\text{ entonces }\frac{\left(\overline{x}_1-\overline{x}_2\right)-\left(\mu_1-\mu_2\right)}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}\stackrel{n{\rightarrow}\infty}{\sim}N(0,1) \]
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \mu \geq \mu_0 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu < \mu_0 \leftrightarrow \mu_1 - \mu_2 < 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\alpha}\sigma_x\sqrt{\frac{1}{n_1}+\frac{1}{n_2}} \right) \\ \hline H_0: \mu = \mu_0 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu \neq \mu_0 \leftrightarrow \mu_1 - \mu_2 \neq 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\frac{\alpha}{2}}\sigma_x\sqrt{\frac{1}{n_1}+\frac{1}{n_2}} \right) \cup \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\frac{\alpha}{2}}\sigma_x\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}, +\infty \right) \\ \hline H_0: \mu \leq \mu_0 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 & \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\alpha}\sigma_x\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}, +\infty \right) \\ \hline \end{array} \]
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \mu \geq \mu_0 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu < \mu_0 \leftrightarrow \mu_1 - \mu_2 < 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\alpha}\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}} \right) \\ \hline H_0: \mu = \mu_0 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu \neq \mu_0 \leftrightarrow \mu_1 - \mu_2 \neq 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\frac{\alpha}{2}}\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}} \right) \cup \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\frac{\alpha}{2}}\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}, +\infty \right) \\ \hline H_0: \mu \leq \mu_0 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 & \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\alpha}\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}, +\infty \right) \\ \hline \end{array} \]
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \mu \geq \mu_0 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu < \mu_0 \leftrightarrow \mu_1 - \mu_2 < 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - t_{\left(n-1,1-\alpha\right)}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}} \right) \\ \hline H_0: \mu = \mu_0 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu \neq \mu_0 \leftrightarrow \mu_1 - \mu_2 \neq 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - t_{\left(n-1,1-\frac{\alpha}{2}\right)}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}} \right) \cup \left( \left( \overline{x}_1 - \overline{x}_2 \right) + t_{\left(n-1,1-\frac{\alpha}{2}\right)}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}, +\infty \right) \\ \hline H_0: \mu \leq \mu_0 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 & \left( \left( \overline{x}_1 - \overline{x}_2 \right) + t_{\left(n-1,1-\alpha\right)}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}, +\infty \right) \\ \hline \end{array} \]
donde: \(s_p = \sqrt{\frac{(n_1 - 1)s_1^2 + (n_2 - 1)s_2^2}{n_1 + n_2 - 2}}\)
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \mu \geq \mu_0 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu < \mu_0 \leftrightarrow \mu_1 - \mu_2 < 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - t_{\left(n-1,1-\alpha\right)}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}} \right) \\ \hline H_0: \mu = \mu_0 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu \neq \mu_0 \leftrightarrow \mu_1 - \mu_2 \neq 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - t_{\left(n-1,1-\frac{\alpha}{2}\right)}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}} \right) \cup \left( \left( \overline{x}_1 - \overline{x}_2 \right) + t_{\left(n-1,1-\frac{\alpha}{2}\right)}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}, +\infty \right) \\ \hline H_0: \mu \leq \mu_0 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 & \left( \left( \overline{x}_1 - \overline{x}_2 \right) + t_{\left(n-1,1-\alpha\right)}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}, +\infty \right) \\ \hline \end{array} \]
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \mu \geq \mu_0 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu < \mu_0 \leftrightarrow \mu_1 - \mu_2 < 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\alpha}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}} \right) \\ \hline H_0: \mu = \mu_0 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu \neq \mu_0 \leftrightarrow \mu_1 - \mu_2 \neq 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\frac{\alpha}{2}}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}} \right) \cup \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\frac{\alpha}{2}}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}, +\infty \right) \\ \hline H_0: \mu \leq \mu_0 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 & \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\alpha}s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}, +\infty \right) \\ \hline \end{array} \]
donde: \(s_p = \sqrt{\frac{(n_1 - 1)s_1^2 + (n_2 - 1)s_2^2}{n_1 + n_2 - 2}}\)
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \mu \geq \mu_0 \leftrightarrow \mu_1 - \mu_2 \geq 0 & H_1: \mu < \mu_0 \leftrightarrow \mu_1 - \mu_2 < 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\alpha}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}} \right) \\ \hline H_0: \mu = \mu_0 \leftrightarrow \mu_1 - \mu_2 = 0 & H_1: \mu \neq \mu_0 \leftrightarrow \mu_1 - \mu_2 \neq 0 & \left( -\infty, \left( \overline{x}_1 - \overline{x}_2 \right) - Z_{1-\frac{\alpha}{2}}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}} \right) \cup \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\frac{\alpha}{2}}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}, +\infty \right) \\ \hline H_0: \mu \leq \mu_0 \leftrightarrow \mu_1 - \mu_2 \leq 0 & H_1: \mu > \mu_0 \leftrightarrow \mu_1 - \mu_2 > 0 & \left( \left( \overline{x}_1 - \overline{x}_2 \right) + Z_{1-\alpha}\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}, +\infty \right) \\ \hline \end{array} \]
Supongamos una población de trabajadores con un salario mínimo de $1.350.000 pesos, donde se desea comparar los salarios de hombres y mujeres. Se asume que el salario de los hombres tiene una varianza de $30.000, mientras que el de las mujeres tiene una varianza de $20.000.
Simularemos los salarios de ambos grupos, asumiendo que los hombres tienen un salario medio de $1.400.000 y las mujeres $1.300.000. Tomaremos muestras de cada grupo y realizaremos una prueba de hipótesis para determinar si hay evidencia suficiente para rechazar la hipótesis nula de que las varianzas de los salarios de hombres y mujeres son iguales.
library(tidyverse)
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## ✔ lubridate 1.9.3 ✔ tidyr 1.3.1
## ✔ purrr 1.0.2
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library(mosaic)
## Registered S3 method overwritten by 'mosaic':
## method from
## fortify.SpatialPolygonsDataFrame ggplot2
##
## The 'mosaic' package masks several functions from core packages in order to add
## additional features. The original behavior of these functions should not be affected by this.
##
## Attaching package: 'mosaic'
##
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##
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# Fijar los parámetros poblacionales
mu_hombres <- 1400000
sigma2_hombres <- 30000
mu_mujeres <- 1300000
sigma2_mujeres <- 20000
# Simular la población
set.seed(123) # Para reproducibilidad
salarios_hombres <- rnorm(n=125000, mean=mu_hombres, sd=sqrt(sigma2_hombres))
salarios_mujeres <- rnorm(n=125000, mean=mu_mujeres, sd=sqrt(sigma2_mujeres))
# Crear un data frame
INGRESOS <- data.frame(
tipo = rep(c("Hombres", "Mujeres"), each = 125000),
salarios = c(salarios_hombres, salarios_mujeres)
)
INGRESOS %>%
ggplot(mapping=aes(x=tipo, y=salarios)) +
geom_boxplot(colour="purple", fill="blue") +
labs(title="Boxplot de Salarios", y="Salarios", x="")
muestra <- INGRESOS %>%
sample_frac(
size=0.3
)
\[ \begin{array}{|c|c|c|} \hline \text{Hipótesis nula ($H_0$)} & \text{Hipótesis alternativa ($H_1$)} & \text{Región de rechazo ($H_0$)} \\ \hline H_0: \sigma_1^2 = \sigma_2^2 \leftrightarrow \frac{\sigma_1^2}{\sigma_2^2} = 1 & H_1: \sigma_1^2 \neq \sigma_2^2 \leftrightarrow \frac{\sigma_1^2}{\sigma_2^2} \neq 1 & \left( 0, F_{\alpha/2, n_1-1, n_2-1} \right) \cup \left( F_{1-\alpha/2, n_1-1, n_2-1}, +\infty \right) \\ \hline \end{array} \]
# Realizar la prueba de hipótesis (Prueba F)
prueba_f <- var.test(
x=muestra[muestra$tipo=="Hombres", "salarios"],
y=muestra[muestra$tipo=="Mujeres","salarios"],
ratio = 1,
alternative = "two.sided",
conf.level = 0.95
)
# Resultados
print(prueba_f)
##
## F test to compare two variances
##
## data: muestra[muestra$tipo == "Hombres", "salarios"] and muestra[muestra$tipo == "Mujeres", "salarios"]
## F = 1.4862, num df = 37441, denom df = 37557, p-value < 2.2e-16
## alternative hypothesis: true ratio of variances is not equal to 1
## 95 percent confidence interval:
## 1.456464 1.516640
## sample estimates:
## ratio of variances
## 1.486247