First Steps with R Basic calculations You can use R for basic computations you would perform in a calculator
# Addition
2-3
[1] -1
4+5
[1] 9
# Division
2/3
[1] 0.6666667
5/2
[1] 2.5
# Exponentiation
2^3
[1] 8
3^3
[1] 27
# Square root
sqrt(2)
[1] 1.414214
sqrt(16)
[1] 4
# Logarithms
log(2)
[1] 0.6931472
log10(10)
[1] 1
log10(100)
[1] 2
#Question_1: Compute the log base 5 of 10 and the log of 10.
log(10, base = 5)
[1] 1.430677
log(10)
[1] 2.302585
Computing some offensive metrics in Baseball
#Batting Average=(No. of Hits)/(No. of At Bats)
#What is the batting average of a player that bats 29 hits in 112 at bats?
BA=(29)/(112)
BA
[1] 0.2589286
Batting_Average=round(BA,digits = 3)
Batting_Average
[1] 0.259
Question_2:What is the batting average of a player that bats 42 hits in 212 at bats?
#On Base Percentage
#OBP=(H+BB+HBP)/(At Bats+H+BB+HBP+SF)
#Let us compute the OBP for a player with the following general stats
#AB=515,H=172,BB=84,HBP=5,SF=6
OBP=(172+84+5)/(515+172+84+5+6)
OBP
[1] 0.3337596
BA=(42)/(212)
BA
[1] 0.1981132
#
On_Base_Average=round(BA,digits = 3)
On_Base_Average
[1] 0.198
On_Base_Percentage=round(OBP,digits = 3)
On_Base_Percentage
[1] 0.334
Question_3:Compute the OBP for a player with the following general stats: #AB=565,H=156,BB=65,HBP=3,SF=7
#AB=565,H=156,BB=65,HBP=3,SF=7
OBP2=(156+65+3)/(565+156+65+3+7)
OBP2
[1] 0.281407
Often you will want to test whether something is less than, greater than or equal to something.
3 == 8# Does 3 equals 8?
[1] FALSE
3 != 8# Is 3 different from 8?
[1] TRUE
3 <= 8# Is 3 less than or equal to 8?
[1] TRUE
The logical operators are & for logical AND, | for logical OR, and ! for NOT. These are some examples:
# Logical Disjunction (or)
FALSE | FALSE # False OR False
[1] FALSE
# Logical Conjunction (and)
TRUE & FALSE #True AND False
[1] FALSE
# Negation
! FALSE # Not False
[1] TRUE
# Combination of statements
2 < 3 | 1 == 5 # 2<3 is True, 1==5 is False, True OR False is True
[1] TRUE
Assigning Values to Variables In R, you create a variable and assign it a value using <- as follows
Total_Bases <- 6 + 5
Total_Bases*3
[1] 33
To see the variables that are currently defined, use ls (as in “list”)
ls()
[1] "allcontracts" "BA" "Batting_Average"
[4] "con" "contract_length" "contract_years"
[7] "contracts_mean" "contracts_median" "contracts_n"
[10] "contracts_sd" "contracts_w1sd" "contracts_w2sd"
[13] "contracts_w3sd" "hits_per_9innings" "HR_before"
[16] "JSn_seasons" "n_1" "n_2"
[19] "n_3" "n_4" "n_seasons"
[22] "OBP" "OBP2" "On_Base_Average"
[25] "On_Base_Average_Percentage" "On_Base_Percentage" "pitches_by_innings"
[28] "Robert_HRs" "runs_per_9innings" "salary_ave"
[31] "salary_ave_bask_nfl" "strikes_by_innings" "Total_Bases"
[34] "Walks_before" "wanted_HR" "wanted_walks"
[37] "x_4" "x_6" "y_1"
[40] "y_2" "y_3" "y_4"
To delete a variable, use rm (as in “remove”)
rm(Total_Bases)
ls()
[1] "allcontracts" "BA" "Batting_Average"
[4] "con" "contract_length" "contract_years"
[7] "contracts_mean" "contracts_median" "contracts_n"
[10] "contracts_sd" "contracts_w1sd" "contracts_w2sd"
[13] "contracts_w3sd" "hits_per_9innings" "HR_before"
[16] "JSn_seasons" "n_1" "n_2"
[19] "n_3" "n_4" "n_seasons"
[22] "OBP" "OBP2" "On_Base_Average"
[25] "On_Base_Average_Percentage" "On_Base_Percentage" "pitches_by_innings"
[28] "Robert_HRs" "runs_per_9innings" "salary_ave"
[31] "salary_ave_bask_nfl" "strikes_by_innings" "Walks_before"
[34] "wanted_HR" "wanted_walks" "x_4"
[37] "x_6" "y_1" "y_2"
[40] "y_3" "y_4"
Either <- or = can be used to assign a value to a variable, but I prefer <- because is less likely to be confused with the logical operator ==
Vectors The basic type of object in R is a vector, which is an ordered list of values of the same type. You can create a vector using the c() function (as in “concatenate”).
pitches_by_innings <- c(12, 15, 10, 20, 10)
pitches_by_innings
[1] 12 15 10 20 10
strikes_by_innings <- c(9, 12, 6, 14, 9)
strikes_by_innings
[1] 9 12 6 14 9
Question_4: Define two vectors,runs_per_9innings and hits_per_9innings, each with five elements.
runs_per_9innings <- c(0, 1, 0, 3, 0)
runs_per_9innings
[1] 0 1 0 3 0
hits_per_9innings <- c(5, 0, 0, 1, 2)
hits_per_9innings
[1] 5 0 0 1 2
There are also some functions that will create vectors with regular patterns, like repeated elements.
# replicate function
rep(2, 5)
[1] 2 2 2 2 2
# consecutive numbers
1:5
[1] 1 2 3 4 5
# sequence from 1 to 10 with a step of 2
seq(1, 10, by=2)
[1] 1 3 5 7 9
Many functions and operators like + or - will work on all elements of the vector.
# add vectors
pitches_by_innings
[1] 12 15 10 20 10
strikes_by_innings
[1] 9 12 6 14 9
pitches_by_innings+strikes_by_innings
[1] 21 27 16 34 19
# compare vectors
pitches_by_innings == strikes_by_innings
[1] FALSE FALSE FALSE FALSE FALSE
# find length of vector
length(pitches_by_innings)
[1] 5
# find minimum value in vector
min(pitches_by_innings)
[1] 10
# find average value in vector
mean(pitches_by_innings)
[1] 13.4
You can access parts of a vector by using [. Recall what the value is of the vector pitches_by_innings.
pitches_by_innings
[1] 12 15 10 20 10
# If you want to get the first element:
pitches_by_innings[1]
[1] 12
Question_5: Get the first element of hits_per_9innings.
hits_per_9innings
[1] 5 0 0 1 2
hits_per_9innings[1]
[1] 5
If you want to get the last element of pitches_by_innings without explicitly typing the number of elements of pitches_by_innings, make use of the length function, which calculates the length of a vector:
pitches_by_innings[length(pitches_by_innings)]
[1] 10
Question_6: Get the last element of hits_per_9innings.
hits_per_9innings
[1] 5 0 0 1 2
hits_per_9innings[length(hits_per_9innings)]
[1] 2
You can also extract multiple values from a vector. For instance to get the 2nd through 4th values use
pitches_by_innings[c(2, 3, 4)]
[1] 15 10 20
Vectors can also be strings or logical values
player_positions <- c("catcher", "pitcher", "infielders", "outfielders")
player_positions
[1] "catcher" "pitcher" "infielders" "outfielders"
Data Frames In statistical applications, data is often stored as a data frame, which is like a spreadsheet, with rows as observations and columns as variables.
To manually create a data frame, use the data.frame() function.
data.frame(bonus = c(2, 3, 1),#in millions
active_roster = c("yes", "no", "yes"),
salary = c(1.5, 2.5, 1))#in millions
Most often you will be using data frames loaded from a file. For example, load the results of a fan’s survey. The function load or read.table can be used for this.
How to Make a Random Sample To randomly select a sample use the function sample(). The following code selects 5 numbers between 1 and 10 at random (without duplication)
sample(1:10, size=5)
[1] 2 8 7 9 3
The first argument gives the vector of data to select elements from. The second argument (size=) gives the size of the sample to select. Taking a simple random sample from a data frame is only slightly more complicated, having two steps:
Use sample() to select a sample of size n from a vector of the row numbers of the data frame. Use the index operator [ to select those rows from the data frame. Consider the following example with fake data. First, make up a data frame with two columns. (LETTERS is a character vector of length 26 with capital letters A to Z; LETTERS is automatically defined and pre-loaded in R)
bar <- data.frame(var1 = LETTERS[1:10], var2 = 1:10)
# Check data frame
bar
Suppose you want to select a random sample of size 5. First, define a variable n with the size of the sample, i.e. 5
n <- 5
Now, select a sample of size 5 from the vector with 1 to 10 (the number of rows in bar). Use the function nrow() to find the number of rows in bar instead of manually entering that number.
Use : to create a vector with all the integers between 1 and the number of rows in bar.
samplerows <- sample(1:nrow(bar), size=n)
# print sample rows
samplerows
[1] 10 2 6 4 8
The variable samplerows contains the rows of bar which make a random sample from all the rows in bar. Extract those rows from bar with
# extract rows
barsample <- bar[samplerows, ]
# print sample
print(barsample)
The code above creates a new data frame called barsample with a random sample of rows from bar.
In a single line of code:
bar[sample(1:nrow(bar), n), ]
Using Tables The table() command allows us to look at tables. Its simplest usage looks like table(x) where x is a categorical variable.
For example, a survey asks people if they support the home team or not. The data is
Yes, No, No, Yes, Yes
We can enter this into R with the c() command, and summarize with the table() command as follows
x <- c("Yes","No","No","Yes","Yes")
table(x)
x
No Yes
2 3
Numerical measures of center and spread Suppose, MLB Teams’ CEOs yearly compensations are sampled and the following are found (in millions)
12 .4 5 2 50 8 3 1 4 0.25
sals <- c(12, .4, 5, 2, 50, 8, 3, 1, 4, 0.25)
# the average
mean(sals)
[1] 8.565
# the variance
var(sals)
[1] 225.5145
# the standard deviation
sd(sals)
[1] 15.01714
# the median
median(sals)
[1] 3.5
# Tukey's five number summary, usefull for boxplots
# five numbers: min, lower hinge, median, upper hinge, max
fivenum(sals)
[1] 0.25 1.00 3.50 8.00 50.00
# summary statistics
summary(sals)
Min. 1st Qu. Median Mean 3rd Qu. Max.
0.250 1.250 3.500 8.565 7.250 50.000
How about the mode? In R we can write our own functions, and a first example of a function is shown below in order to compute the mode of a vector of observations x
# Function to find the mode, i.e. most frequent value
getMode <- function(x) {
ux <- unique(x)
ux[which.max(tabulate(match(x, ux)))]
}
As an example, we can use the function defined above to find the most frequent value of the number of pitches_by_innings
# Most frequent value in baz
pitches_by_innings
[1] 12 15 10 20 10
getMode(pitches_by_innings)
[1] 10
Question_7: Find the most frequent value of hits_per_9innings.
hits_per_9innings
[1] 5 0 0 1 2
getMode(hits_per_9innings)
[1] 0
Question_8: Summarize the following survey with the
table() command: What is your favorite day of the week to
watch baseball? A total of 10 fans submitted this survey. Saturday,
Saturday, Sunday, Monday, Saturday,Tuesday, Sunday, Friday, Friday,
Monday
survey <- c("Saturday","Saturday","Sunday","Monday","Saturday","Tuesday","Sunday","Friday","Friday","Monday")
summary_table <-table(survey)
summary_table
survey
Friday Monday Saturday Sunday Tuesday
2 2 3 2 1
favorite_day <- names(summary_table[summary_table==max(summary_table)])
favorite_day
[1] "Saturday"
Question_9: What is the most frequent answer recorded in the survey? Use the getMode function to compute results.
frequent_answer <- getMode(survey)
frequent_answer
[1] "Saturday"