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Chapter 8.8, # 27

Find the Taylor Series for f(x)=sin(2x+3).

From Key Idea 8.8.1, and Theorem 8.8.2, if we let f(x)=sin(x) and h(x)=2x+3, then

sin(x)=n=0(1)n(2n+1)!x2n+1

Therefore,

f(h(x))=sin(2x+3)=n=0(1)n(2n+1)!(2x+3)n

The first few terms are,

113!(2x+3)+15!(2x+3)17!(2x+3)+