Basic Time Series Forecasting Methods

Project Objective

To forecast data using different types of time series methods.

Example 1: Naive Approach

Time Series Data

months <- 1:6
values <- c(17, 13, 15, 11, 17, 14)

Part A: Most Recent Values as Forecast

forecast_a <- values[-length(values)] #exclude the last value
actual_a <- values[-1] #exclude the first value
mse_a <- mean((actual_a - forecast_a)^2)
mse_a #result: 16.2
## [1] 16.2
Result: Mean Squared Error: 16.20
forecast_month_7_a <- tail(values, 1)
forecast_month_7_a #result: 14
## [1] 14
Result: Forecast A for week 7 is 14.

Part B: Average All of the Data as Forecast

cumulative_avgs <- cumsum(values[-length(values)]) / (1:(length(values) - 1))
forecast_b <- cumulative_avgs
actual_b <- values[-1] #exclude the first value
mse_b <- mean((actual_b - forecast_b)^2)
mse_b #8.27
## [1] 8.272
Result: Mean Squared Error: 8.27.
forecast_month_7_b <- mean(values) #average of all months as forecast for month 7
forecast_month_7_b #result: 14.5
## [1] 14.5
Result: Forecast B for week 7 is 14.5.

Part C: Which Method is Better?

better_method <- ifelse(mse_a < mse_b, "Most Recent Value", "Average of All Data")
list(
  MSE_most_recent_value = mse_a,
  forecast_month_7_most_recent = forecast_month_7_a,
  MSE_average_of_all_data = mse_b,
  forecast_month_7_average = forecast_month_7_b,
  Better_Method = better_method
)
## $MSE_most_recent_value
## [1] 16.2
## 
## $forecast_month_7_most_recent
## [1] 14
## 
## $MSE_average_of_all_data
## [1] 8.272
## 
## $forecast_month_7_average
## [1] 14.5
## 
## $Better_Method
## [1] "Average of All Data"
Result: The better method is the Average of all Data.

Part D: Finding Mean Absolute Error

mae <- mean(abs(actual_a - forecast_a))
mae #result: 3.8
## [1] 3.8
Result: The mean absolute error is 3.80.

Part E: Finding Mean Absolute Percentage Error

mape <- mean(abs((actual_a - forecast_a) / actual_a)) * 100
mape #result: 27.44
## [1] 27.43778
Result: The mean absolute percentage error is 27.44%.

Example 2

Install and Load Packages

#install.packages("dplyr")
#install.packages("zoo")

library(dplyr)
## Warning: package 'dplyr' was built under R version 4.3.3
## 
## Attaching package: 'dplyr'
## The following objects are masked from 'package:stats':
## 
##     filter, lag
## The following objects are masked from 'package:base':
## 
##     intersect, setdiff, setequal, union
library(zoo)
## Warning: package 'zoo' was built under R version 4.3.3
## 
## Attaching package: 'zoo'
## The following objects are masked from 'package:base':
## 
##     as.Date, as.Date.numeric
library(magrittr)

Load the Data

df <- data.frame(month=c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12),
                 data=c(240, 352, 230, 260, 280, 322, 220, 310, 240, 310, 240, 230))

Part A: Time Series Plot

plot(df$month, df$data, type = "o", col = "blue", xlab = "Month", ylab = 
       "Value of Building Contracts (in millions)", 
     main = "Value of Alabama Building Contracts Over 12 Month Period")

Interpretation:  The time series plot exhibits a horizontal pattern.

Part B: Three-Month Moving Average

df$avg_value <- c(NA, NA, NA, 
                  (df$data[1] + df$data[2] + df$data[3]) / 3,
                  (df$data[2] + df$data[3] + df$data[4]) / 3,
                  (df$data[3] + df$data[4] + df$data[5]) / 3,
                  (df$data[4] + df$data[5] + df$data[6]) / 3,
                  (df$data[5] + df$data[6] + df$data[7]) / 3,
                  (df$data[6] + df$data[7] + df$data[8]) / 3,
                  (df$data[7] + df$data[8] + df$data[9]) / 3,
                  (df$data[8] + df$data[9] + df$data[10]) / 3,
                  (df$data[9] + df$data[10] + df$data[11]) / 3)

Calculate the Squared Errors (only for the months where moving avg is available)

df <- df %>%
  mutate(squared_error = ifelse(is.na(avg_value), NA, (data - avg_value)^2)
  )

Compute MSE (excluding the initial months with NA)

mse <- mean(df$squared_error, na.rm = TRUE)
mse #result: 2040.44
## [1] 2040.444
Result: The mean squared error for the three-month moving average is 2040.44.

Exponential Smoothing

alpha = 0.2
exp_smooth <- rep(NA, length(df$data))
exp_smooth[1] <- df$data[1] #starting point
for(i in 2:length(df$data)) {
  exp_smooth[i] <- alpha * df$data[i - 1] + (1 - alpha) * exp_smooth[i - 1]
}
mse_exp_smooth <- mean((df$data[2:12] - exp_smooth[2:12])^2)
mse_exp_smooth #result: 2593.76
## [1] 2593.762
Result: The mean squared error for exponential smoothing is 2593.76 

Compare Both Methods

better_method <- ifelse(mse < mse_exp_smooth, "Three-Month Moving Average", "Exponential Smoothing")
list(
  MSE_moving_average = mse,
  MSE_exponential_smoothing = mse_exp_smooth,
  Better_Method = better_method
)
## $MSE_moving_average
## [1] 2040.444
## 
## $MSE_exponential_smoothing
## [1] 2593.762
## 
## $Better_Method
## [1] "Three-Month Moving Average"
Result: The better method is the three-month moving average.

Example 3

Load Packages & Data

# Load the packages
library(readxl)
## Warning: package 'readxl' was built under R version 4.3.3
library(ggplot2)
## Warning: package 'ggplot2' was built under R version 4.3.3
# Load the data
df1 <- read_excel("C:/Users/14086/Downloads/R MARKDOWN/Mortgage.xlsx")

Part A: Time Series Plot

ggplot(df1, aes(x = Year, y = Interest_Rate)) +
  geom_line() +
  geom_point() +
  xlab("Year") +
  ylab("Interest_Rate (%)") +
  ggtitle("Time Series Plot of Interest Rate (%) for a 30-year Fixed-Rate Mortgage")

Interpretation: The time series plot exhibits a decreasing pattern, with a sudden increase in interest rates after the year 2020.

Part B: Develop a Linear Trend Equation

model <- lm(Interest_Rate ~ Period, data = df1)
summary(model)
## 
## Call:
## lm(formula = Interest_Rate ~ Period, data = df1)
## 
## Residuals:
##     Min      1Q  Median      3Q     Max 
## -1.3622 -0.7212 -0.2823  0.5015  3.1847 
## 
## Coefficients:
##             Estimate Std. Error t value Pr(>|t|)    
## (Intercept)  6.69541    0.43776  15.295 3.32e-13 ***
## Period      -0.12890    0.03064  -4.207 0.000364 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## Residual standard error: 1.039 on 22 degrees of freedom
## Multiple R-squared:  0.4459, Adjusted R-squared:  0.4207 
## F-statistic:  17.7 on 1 and 22 DF,  p-value: 0.0003637
Result: Linear Trend Equation: Revenue = 6.70 - 0.13*Period OR y = 6.70 - 0.13t

Part C: Forecast for Period 25 (i.e., 2024)

forecast_period_25 <- predict(model, newdata = data.frame(Period = 25))
forecast_period_25 #3.47
##        1 
## 3.472942
Result: The forecast for period 25 is 3.47.