Analysis
Random Forest Graph:
##
##
## Cell Contents
## |-------------------------|
## | N |
## | Chi-square contribution |
## | N / Row Total |
## | N / Col Total |
## | N / Table Total |
## |-------------------------|
##
##
## Total Observations in Table: 3009
##
##
## | val$Attrition_Flag
## val$predicted_Attrition_Flag | Attrited Customer | Existing Customer | Row Total |
## -----------------------------|-------------------|-------------------|-------------------|
## Attrited Customer | 397 | 36 | 433 |
## | 1520.599 | 294.348 | |
## | 0.917 | 0.083 | 0.144 |
## | 0.814 | 0.014 | |
## | 0.132 | 0.012 | |
## -----------------------------|-------------------|-------------------|-------------------|
## Existing Customer | 91 | 2485 | 2576 |
## | 255.598 | 49.477 | |
## | 0.035 | 0.965 | 0.856 |
## | 0.186 | 0.986 | |
## | 0.030 | 0.826 | |
## -----------------------------|-------------------|-------------------|-------------------|
## Column Total | 488 | 2521 | 3009 |
## | 0.162 | 0.838 | |
## -----------------------------|-------------------|-------------------|-------------------|
##
##
Conclusions:
- 462 I predicted were going to leave
- The cost of my program is 462 x 100 = $46,200
- We will save 30% of 377 = 113.1 which had a value of $2,300 x 113.1
= $260,130
- The net of this program is $260,130 from 2,994 employees
- Per customer is $86.89 per customer